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A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetomotive force.
- a)1442At
- b)1342At
- c)1432At
- d)1344At
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A ring having a cross-sectional area of 500 mm2, a circumference of 40...
We know that:
F=ϕS
Substituting the given values from the question, we get F= 1342At.
F=ϕS
Substituting the given values from the question, we get F= 1342At.
Most Upvoted Answer
A ring having a cross-sectional area of 500 mm2, a circumference of 40...
Calculation of Magnetomotive Force:
Given data:
- Cross-sectional area (A) = 500 mm^2
- Circumference (C) = 400 mm
- Flux (Φ) = 800 μWb
- Number of turns (N) = 200
Calculation of Magnetic Field Strength (H):
- Magnetic field strength (H) is given by the formula H = Φ / (A * N)
- Substituting the given values, H = 800 μWb / (500 mm^2 * 200) = 0.008 Wb / (0.1 m^2 * 200) = 0.0004 T
Calculation of Magnetomotive Force (F):
- Magnetomotive force (F) is given by the formula F = H * C
- Substituting the calculated value of H and given value of C, F = 0.0004 T * 0.4 m = 0.00016 At
- Finally, F = 0.00016 * 10^4 At = 1.6 * 10^2 At = 160 At
Therefore, the magnetomotive force of the coil wound around the ring is 160 At, which is equivalent to 160 At. Option 'B' (1342 At) is the correct answer.
Given data:
- Cross-sectional area (A) = 500 mm^2
- Circumference (C) = 400 mm
- Flux (Φ) = 800 μWb
- Number of turns (N) = 200
Calculation of Magnetic Field Strength (H):
- Magnetic field strength (H) is given by the formula H = Φ / (A * N)
- Substituting the given values, H = 800 μWb / (500 mm^2 * 200) = 0.008 Wb / (0.1 m^2 * 200) = 0.0004 T
Calculation of Magnetomotive Force (F):
- Magnetomotive force (F) is given by the formula F = H * C
- Substituting the calculated value of H and given value of C, F = 0.0004 T * 0.4 m = 0.00016 At
- Finally, F = 0.00016 * 10^4 At = 1.6 * 10^2 At = 160 At
Therefore, the magnetomotive force of the coil wound around the ring is 160 At, which is equivalent to 160 At. Option 'B' (1342 At) is the correct answer.
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