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When an optically active compound is placed in a 10 dm tube is present 20 gm in a 200 ml solution rotates the PPL by 30º. Calculate the angle of rotation & specific angle of rotation if above solution diluted to 1 Litre.
- a)16º & 36º
- b)6º & 30º
- c)3º & 30º
- d)6º & 36º
Correct answer is option 'B'. Can you explain this answer?
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To calculate the specific angle of rotation, we need to use the formula:
Specific rotation = observed rotation / (concentration * path length)
Given data:
- Compound concentration = 20 g in 200 mL
- Tube length (path length) = 10 dm = 100 cm
First, we need to convert the concentration from grams per milliliter (g/mL) to grams per cubic centimeter (g/cm³) since the path length is given in centimeters.
Concentration = 20 g / 200 mL = 0.1 g/mL = 0.1 g/cm³
Now we can calculate the specific angle of rotation:
Specific rotation = 30 / (0.1 * 100)
Specific rotation = 30 / 10
Specific rotation = 3°/dm*g/mL
To find the specific rotation when the solution is diluted to 1 liter, we need to calculate the new concentration.
Given data:
- Initial concentration = 0.1 g/cm³
- Volume after dilution = 1 L = 1000 mL
To find the new concentration, we can use the equation:
Initial concentration * Initial volume = Final concentration * Final volume
0.1 g/cm³ * 200 mL = Final concentration * 1000 mL
Final concentration = (0.1 g/cm³ * 200 mL) / 1000 mL
Final concentration = 0.02 g/mL = 0.02 g/cm³
Now we can calculate the new specific angle of rotation:
Specific rotation = 30 / (0.02 * 100)
Specific rotation = 30 / 2
Specific rotation = 15°/dm*g/mL
Therefore, the specific angle of rotation when the solution is diluted to 1 liter is 15°/dm*g/mL, which is equivalent to 6°/30' (option B).
Specific rotation = observed rotation / (concentration * path length)
Given data:
- Compound concentration = 20 g in 200 mL
- Tube length (path length) = 10 dm = 100 cm
First, we need to convert the concentration from grams per milliliter (g/mL) to grams per cubic centimeter (g/cm³) since the path length is given in centimeters.
Concentration = 20 g / 200 mL = 0.1 g/mL = 0.1 g/cm³
Now we can calculate the specific angle of rotation:
Specific rotation = 30 / (0.1 * 100)
Specific rotation = 30 / 10
Specific rotation = 3°/dm*g/mL
To find the specific rotation when the solution is diluted to 1 liter, we need to calculate the new concentration.
Given data:
- Initial concentration = 0.1 g/cm³
- Volume after dilution = 1 L = 1000 mL
To find the new concentration, we can use the equation:
Initial concentration * Initial volume = Final concentration * Final volume
0.1 g/cm³ * 200 mL = Final concentration * 1000 mL
Final concentration = (0.1 g/cm³ * 200 mL) / 1000 mL
Final concentration = 0.02 g/mL = 0.02 g/cm³
Now we can calculate the new specific angle of rotation:
Specific rotation = 30 / (0.02 * 100)
Specific rotation = 30 / 2
Specific rotation = 15°/dm*g/mL
Therefore, the specific angle of rotation when the solution is diluted to 1 liter is 15°/dm*g/mL, which is equivalent to 6°/30' (option B).
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When an optically active compound is placed in a 10 dm tube is present 20 gm in a 200 ml solution rotates the PPL by 30º. Calculate the angle of rotation & specific angle of rotation if above solution diluted to 1 Litre.a)16º & 36ºb)6º & 30ºc)3º & 30ºd)6º & 36ºCorrect answer is option 'B'. Can you explain this answer?
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When an optically active compound is placed in a 10 dm tube is present 20 gm in a 200 ml solution rotates the PPL by 30º. Calculate the angle of rotation & specific angle of rotation if above solution diluted to 1 Litre.a)16º & 36ºb)6º & 30ºc)3º & 30ºd)6º & 36ºCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about When an optically active compound is placed in a 10 dm tube is present 20 gm in a 200 ml solution rotates the PPL by 30º. Calculate the angle of rotation & specific angle of rotation if above solution diluted to 1 Litre.a)16º & 36ºb)6º & 30ºc)3º & 30ºd)6º & 36ºCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When an optically active compound is placed in a 10 dm tube is present 20 gm in a 200 ml solution rotates the PPL by 30º. Calculate the angle of rotation & specific angle of rotation if above solution diluted to 1 Litre.a)16º & 36ºb)6º & 30ºc)3º & 30ºd)6º & 36ºCorrect answer is option 'B'. Can you explain this answer?.
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