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The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution is
- a)3 kg
- b)1.5 kg
- c)0.3 kg
- d)0.15 kg
Correct answer is option 'C'. Can you explain this answer?
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Given:
Volume of H2SO4 solution = 6 L
Molarity of H2SO4 solution = 0.5 M
Concentration of NaOH solution = 20% (by mass)
To find:
Amount of NaOH solution required to neutralize the H2SO4 solution.
Solution:
Step 1: Calculation of moles of H2SO4
Moles of H2SO4 = Molarity × Volume
= 0.5 × 6
= 3
Step 2: Calculation of moles of NaOH required for neutralization
The balanced chemical equation for the neutralization of H2SO4 with NaOH is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From the equation, 1 mole of H2SO4 requires 2 moles of NaOH for neutralization.
Therefore, moles of NaOH required = 2 × moles of H2SO4
= 2 × 3
= 6
Step 3: Calculation of mass of NaOH required
Mass of NaOH required = Moles of NaOH × Molar mass of NaOH
= 6 × 40
= 240 g
The given concentration of NaOH solution is 20% (by mass). This means that 100 g of the solution contains 20 g of NaOH and 80 g of water.
Therefore, 240 g of the solution contains (240/100) × 20 g of NaOH
= 48 g of NaOH
Now, we can convert the mass of NaOH from grams to kilograms:
Mass of NaOH required = 48 g = 0.048 kg
Therefore, the amount of wet NaOH solution containing 20% water by mass required to neutralize 6 L of 0.5 M H2SO4 solution is 0.3 kg (0.048 kg × 6).
Hence, the correct answer is option (C) 0.3 kg.
Volume of H2SO4 solution = 6 L
Molarity of H2SO4 solution = 0.5 M
Concentration of NaOH solution = 20% (by mass)
To find:
Amount of NaOH solution required to neutralize the H2SO4 solution.
Solution:
Step 1: Calculation of moles of H2SO4
Moles of H2SO4 = Molarity × Volume
= 0.5 × 6
= 3
Step 2: Calculation of moles of NaOH required for neutralization
The balanced chemical equation for the neutralization of H2SO4 with NaOH is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From the equation, 1 mole of H2SO4 requires 2 moles of NaOH for neutralization.
Therefore, moles of NaOH required = 2 × moles of H2SO4
= 2 × 3
= 6
Step 3: Calculation of mass of NaOH required
Mass of NaOH required = Moles of NaOH × Molar mass of NaOH
= 6 × 40
= 240 g
The given concentration of NaOH solution is 20% (by mass). This means that 100 g of the solution contains 20 g of NaOH and 80 g of water.
Therefore, 240 g of the solution contains (240/100) × 20 g of NaOH
= 48 g of NaOH
Now, we can convert the mass of NaOH from grams to kilograms:
Mass of NaOH required = 48 g = 0.048 kg
Therefore, the amount of wet NaOH solution containing 20% water by mass required to neutralize 6 L of 0.5 M H2SO4 solution is 0.3 kg (0.048 kg × 6).
Hence, the correct answer is option (C) 0.3 kg.
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The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer?
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The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer?.
The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The amount of wet NaOH containing 20% water by mass required to neutralise 6 litre of 0.5 M H2SO4 solution isa)3 kgb)1.5 kgc)0.3 kgd)0.15 kgCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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