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Which of the following does not undergo Cannizzaro's reaction?
- a)benzaldehyde
- b)2-methylpropanal
- c)p-methoxybenzaldehyde
- d)2,2-dimethylpropanal
Correct answer is option 'B'. Can you explain this answer?
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Which of the following does not undergo Cannizzaro's reaction?a)be...
Cannizaro occurs only in absence of Alpha hydrogen
and in presence of Alpha hydrogen aldol condensation take place
and in presence of Alpha hydrogen aldol condensation take place
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Which of the following does not undergo Cannizzaro's reaction?a)be...
Explanation:
Cannizzaro reaction is a disproportionation reaction of aldehydes (and some ketones) in which one molecule is oxidized to a carboxylic acid and the other is reduced to an alcohol. The reaction is carried out in the presence of a strong base, usually an alkali metal hydroxide, and water. The reaction is named after its discoverer, Stanislao Cannizzaro.
The following are the options given in the question and their suitability for Cannizzaro reaction:
a) Benzaldehyde: undergoes Cannizzaro reaction to form benzoic acid and benzyl alcohol.
b) 2-methylpropanal: does not undergo Cannizzaro reaction because it does not have a hydrogen atom in the alpha position to the carbonyl group.
c) p-methoxybenzaldehyde: undergoes Cannizzaro reaction to form p-methoxybenzoic acid and p-methoxybenzyl alcohol.
d) 2,2-dimethylpropanal: undergoes Cannizzaro reaction to form 2,2-dimethylpropanoic acid and 2,2-dimethylpropan-1-ol.
Therefore, the correct answer is option 'B' as 2-methylpropanal does not have a hydrogen atom in the alpha position to the carbonyl group and hence does not undergo Cannizzaro reaction.
In summary:
- Aldehydes with alpha-hydrogens undergo Cannizzaro reaction.
- Aldehydes without alpha-hydrogens, such as 2-methylpropanal, do not undergo Cannizzaro reaction.
Cannizzaro reaction is a disproportionation reaction of aldehydes (and some ketones) in which one molecule is oxidized to a carboxylic acid and the other is reduced to an alcohol. The reaction is carried out in the presence of a strong base, usually an alkali metal hydroxide, and water. The reaction is named after its discoverer, Stanislao Cannizzaro.
The following are the options given in the question and their suitability for Cannizzaro reaction:
a) Benzaldehyde: undergoes Cannizzaro reaction to form benzoic acid and benzyl alcohol.
b) 2-methylpropanal: does not undergo Cannizzaro reaction because it does not have a hydrogen atom in the alpha position to the carbonyl group.
c) p-methoxybenzaldehyde: undergoes Cannizzaro reaction to form p-methoxybenzoic acid and p-methoxybenzyl alcohol.
d) 2,2-dimethylpropanal: undergoes Cannizzaro reaction to form 2,2-dimethylpropanoic acid and 2,2-dimethylpropan-1-ol.
Therefore, the correct answer is option 'B' as 2-methylpropanal does not have a hydrogen atom in the alpha position to the carbonyl group and hence does not undergo Cannizzaro reaction.
In summary:
- Aldehydes with alpha-hydrogens undergo Cannizzaro reaction.
- Aldehydes without alpha-hydrogens, such as 2-methylpropanal, do not undergo Cannizzaro reaction.
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Which of the following does not undergo Cannizzaro's reaction?a)benzaldehydeb)2-methylpropanalc)p-methoxybenzaldehyded)2,2-dimethylpropanalCorrect answer is option 'B'. Can you explain this answer?
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