In which of the following compounds, nitrogen exhibits highest oxidati...
Explanation:
In order to determine the oxidation state of nitrogen in the given compounds, we need to consider the electronegativity and the number of bonds formed by nitrogen with other elements.
N2H4:
In N2H4, each nitrogen atom is bonded to two hydrogen atoms. The electronegativity of hydrogen is lower than that of nitrogen, so each nitrogen atom will have a higher oxidation state. Therefore, the oxidation state of nitrogen in N2H4 is -2.
NH3:
In NH3, nitrogen is bonded to three hydrogen atoms. Again, the electronegativity of hydrogen is lower than that of nitrogen, so each hydrogen atom will have a higher oxidation state. Therefore, the oxidation state of nitrogen in NH3 is -3.
N3H:
In N3H, nitrogen is bonded to three hydrogen atoms. Similar to NH3, the oxidation state of nitrogen in N3H is -3.
NH2OH:
In NH2OH, nitrogen is bonded to two hydrogen atoms and one oxygen atom. The electronegativity of oxygen is higher than that of nitrogen, so nitrogen will have a lower oxidation state compared to oxygen. The oxygen atom will have an oxidation state of -2. Therefore, the oxidation state of nitrogen in NH2OH is +1.
Conclusion:
Among the given compounds, the compound in which nitrogen exhibits the highest oxidation state is N3H, with an oxidation state of -3.