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In which of the following compounds, nitrogen exhibits highest oxidation state ? [2012]
  • a)
    N2H4
  • b)
    NH3
  • c)
    N3H
  • d)
    NH2OH
Correct answer is option 'C'. Can you explain this answer?
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In which of the following compounds, nitrogen exhibits highest oxidati...
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Explanation:

In order to determine the oxidation state of nitrogen in the given compounds, we need to consider the electronegativity and the number of bonds formed by nitrogen with other elements.

N2H4:
In N2H4, each nitrogen atom is bonded to two hydrogen atoms. The electronegativity of hydrogen is lower than that of nitrogen, so each nitrogen atom will have a higher oxidation state. Therefore, the oxidation state of nitrogen in N2H4 is -2.

NH3:
In NH3, nitrogen is bonded to three hydrogen atoms. Again, the electronegativity of hydrogen is lower than that of nitrogen, so each hydrogen atom will have a higher oxidation state. Therefore, the oxidation state of nitrogen in NH3 is -3.

N3H:
In N3H, nitrogen is bonded to three hydrogen atoms. Similar to NH3, the oxidation state of nitrogen in N3H is -3.

NH2OH:
In NH2OH, nitrogen is bonded to two hydrogen atoms and one oxygen atom. The electronegativity of oxygen is higher than that of nitrogen, so nitrogen will have a lower oxidation state compared to oxygen. The oxygen atom will have an oxidation state of -2. Therefore, the oxidation state of nitrogen in NH2OH is +1.

Conclusion:
Among the given compounds, the compound in which nitrogen exhibits the highest oxidation state is N3H, with an oxidation state of -3.
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