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The sum of opposite sides of quadrilateral circuscribed about a circle ,is always equal. What is the meaning of this statement? How to prove it ?
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The sum of opposite sides of quadrilateral circuscribed about a circle...
First make the diagram with give information.

It can be observed that

DR = DS (Tangents on the circle from point D) …......(1)

CR = CQ (Tangents on the circle from point C) …....(2)

BP = BQ (Tangents on the circle from point B) …...(3)

AP = AS (Tangents on the circle from point A) ….(4)

Adding all these equations, we obtain

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

CD + AB = AD + BC  

[Q.E.D]

That's all☺
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