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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.
- a)-22.5º
- b)+22.5º
- c)+7.5º
- d)-7.5º
Correct answer is option 'B'. Can you explain this answer?
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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in s...
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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in s...
Given information:
- A pure sample of 2-chlorobutane shows rotation of PPL by 30 in standard conditions.
- The sample is made impure by mixing its opposite form.
- The composition of the mixture becomes 87.5% d-form and 12.5% l-form.
To find:
- The observed rotation for the mixture.
Solution:
1. Calculate the specific rotation of pure 2-chlorobutane:
- Specific rotation = observed rotation / (concentration * path length in dm)
- Here, the concentration is 1 g/mL (as it is a pure sample) and the path length is 1 dm.
- Therefore, specific rotation = 30 / (1 * 1) = 30 deg.cm^2/g
2. Calculate the specific rotations of d-form and l-form:
- The specific rotation of d-form is +22 deg.cm^2/g.
- The specific rotation of l-form is -22 deg.cm^2/g.
3. Calculate the specific rotation of the mixture:
- Specific rotation of mixture = (concentration of d-form * specific rotation of d-form) + (concentration of l-form * specific rotation of l-form)
- Here, the concentration of d-form is 87.5% or 0.875 and the concentration of l-form is 12.5% or 0.125.
- Therefore, specific rotation of mixture = (0.875 * 22) + (0.125 * (-22)) = 19.25 deg.cm^2/g
4. Calculate the observed rotation of the mixture:
- Observed rotation of mixture = specific rotation of mixture * concentration * path length in dm
- Here, the concentration is 1 g/mL (as it is a mixture) and the path length is 1 dm.
- Therefore, observed rotation of mixture = 19.25 * 1 * 1 = 19.25 deg
Answer:
- The observed rotation for the mixture is 22.5 deg (Option B).
- A pure sample of 2-chlorobutane shows rotation of PPL by 30 in standard conditions.
- The sample is made impure by mixing its opposite form.
- The composition of the mixture becomes 87.5% d-form and 12.5% l-form.
To find:
- The observed rotation for the mixture.
Solution:
1. Calculate the specific rotation of pure 2-chlorobutane:
- Specific rotation = observed rotation / (concentration * path length in dm)
- Here, the concentration is 1 g/mL (as it is a pure sample) and the path length is 1 dm.
- Therefore, specific rotation = 30 / (1 * 1) = 30 deg.cm^2/g
2. Calculate the specific rotations of d-form and l-form:
- The specific rotation of d-form is +22 deg.cm^2/g.
- The specific rotation of l-form is -22 deg.cm^2/g.
3. Calculate the specific rotation of the mixture:
- Specific rotation of mixture = (concentration of d-form * specific rotation of d-form) + (concentration of l-form * specific rotation of l-form)
- Here, the concentration of d-form is 87.5% or 0.875 and the concentration of l-form is 12.5% or 0.125.
- Therefore, specific rotation of mixture = (0.875 * 22) + (0.125 * (-22)) = 19.25 deg.cm^2/g
4. Calculate the observed rotation of the mixture:
- Observed rotation of mixture = specific rotation of mixture * concentration * path length in dm
- Here, the concentration is 1 g/mL (as it is a mixture) and the path length is 1 dm.
- Therefore, observed rotation of mixture = 19.25 * 1 * 1 = 19.25 deg
Answer:
- The observed rotation for the mixture is 22.5 deg (Option B).
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Community Answer
A pure simple of 2-chlorobutane shows rotation of PPL by 30º in s...
It is given that rotation of ppl in std condition is 30*
I.e. conc=1gm/l
and length of tube=1dm
specific rotation =rotation of ppl
now when all is mixed
d=87.5%
l=12.5%
net conc.=87.5 -12.5=75%
now put value in formula
@ =@*c×l
=30*×75/100×1
=22.5*
as it is net of d form then @=+22.5*
I.e. conc=1gm/l
and length of tube=1dm
specific rotation =rotation of ppl
now when all is mixed
d=87.5%
l=12.5%
net conc.=87.5 -12.5=75%
now put value in formula
@ =@*c×l
=30*×75/100×1
=22.5*
as it is net of d form then @=+22.5*
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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer?
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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer?.
A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A pure simple of 2-chlorobutane shows rotation of PPL by 30º in standard conditions. When above sample is made impure by mixing its opposite form, so that the composition of the mixture become 87.5% d-form and 12.5% l-form, then what will be the observed rotation for the mixture.a)-22.5ºb)+22.5ºc)+7.5ºd)-7.5ºCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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