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In a series RL circuit 5 A current is flowing, voltage drop across R is 16 V and voltage drop across L is 12 V calculate impedance –

  • a)
    4 ∠-36.9°Ω

  • b)
    8 ∠-36.9° Ω 

  • c)
    8 ∠36.9°Ω

  • d)
    4 ∠36.9° Ω

Correct answer is option 'D'. Can you explain this answer?
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In a series RL circuit 5 A current is flowing, voltage drop across R i...


⇒ z = 4 ∠36 - 9°
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In a series RL circuit 5 A current is flowing, voltage drop across R i...








⇒ z = 4 ∠36 - 9°
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Community Answer
In a series RL circuit 5 A current is flowing, voltage drop across R i...
Given Data
- Current (I) = 5 A
- Voltage drop across Resistor (V_R) = 16 V
- Voltage drop across Inductor (V_L) = 12 V
Calculating Total Voltage
To find the total voltage (V_T) in the circuit, we need to consider the voltage across both the resistor and inductor. Since they are in series, we use the Pythagorean theorem:
- V_T = √(V_R^2 + V_L^2)
Calculating it:
- V_T = √(16^2 + 12^2)
- V_T = √(256 + 144)
- V_T = √400
- V_T = 20 V
Calculating Impedance (Z)
Impedance in an RL circuit is given by:
- Z = V_T / I
Substituting the values:
- Z = 20 V / 5 A = 4 Ω
Calculating Phase Angle (φ)
The phase angle can be calculated using:
- tan(φ) = V_L / V_R
Calculating it:
- tan(φ) = 12 V / 16 V
- tan(φ) = 0.75
Now, finding the angle:
- φ = arctan(0.75) ≈ 36.87°
Final Impedance Representation
The impedance can be expressed in polar form as:
- Z = 4 ∠ 36.87° Ω
Thus, the correct answer is:
- Option D: 4 ∠ 36.9° Ω
This indicates that the impedance has a magnitude of 4 Ω and a phase angle of approximately 36.9 degrees, confirming option D as the correct choice.
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