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A block rests on a rough inclined plane making an angle of 30 with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of block is (g=10m/s2)
  • a)
    2.0kg
  • b)
    4.0kg
  • c)
    1.6kg
  • d)
    2.5kg
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A block rests on a rough inclined plane making an angle of30∘wit...
Given parameters:
- Angle of inclined plane = 30 degrees
- Coefficient of static friction = 0.8
- Frictional force = 10 N
- Acceleration due to gravity = 10 m/s^2

Finding the mass of the block:
We can use the following formula to find the mass of the block:

frictional force = coefficient of friction x normal force
where normal force is the force perpendicular to the inclined plane.

Normal force can be found using the following formula:

normal force = weight of block x cos(theta)
where theta is the angle of the inclined plane.

Using these formulas, we can solve for the mass of the block as follows:

- Frictional force = coefficient of friction x normal force
- 10 N = 0.8 x normal force
- Normal force = 12.5 N (dividing both sides by 0.8)
- Normal force = weight of block x cos(theta)
- 12.5 N = weight of block x cos(30 degrees)
- Weight of block = 25 N (dividing both sides by cos(30 degrees))
- Mass of block = weight of block / acceleration due to gravity
- Mass of block = 2.5 kg

Therefore, the correct answer is option A (2.0 kg).
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A block rests on a rough inclined plane making an angle of30∘wit...
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A block rests on a rough inclined plane making an angle of30∘with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of block is(g=10m/s2)a)2.0kgb)4.0kgc)1.6kgd)2.5kgCorrect answer is option 'A'. Can you explain this answer?
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A block rests on a rough inclined plane making an angle of30∘with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of block is(g=10m/s2)a)2.0kgb)4.0kgc)1.6kgd)2.5kgCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block rests on a rough inclined plane making an angle of30∘with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of block is(g=10m/s2)a)2.0kgb)4.0kgc)1.6kgd)2.5kgCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block rests on a rough inclined plane making an angle of30∘with the horizontal. The coefficient of static friction between block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of block is(g=10m/s2)a)2.0kgb)4.0kgc)1.6kgd)2.5kgCorrect answer is option 'A'. Can you explain this answer?.
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