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500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution?
Verified Answer
500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed wi...
Ans.
Method to Solve :
M=0.227mol/L
Explanation:
volumes of different solutions are not additive, so 100 mL of sulfuric acid and 400 mL of water don't make 500 mL of solution but less.
in spite of this you have 150 g of acid 1 M + 400 g of water= 550 g of material and a final density of 1.25 g/mL then you have
V=
=
At the beginning you have
of acid.
In the final solution, you have the same amount then Molarity is
M=
pay attention: the utilizzed numbers are not real, but they are used only for this exercise
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Most Upvoted Answer
500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed wi...
Given Data:
- Volume of 1 M H2SO4 solution = 500 mL
- Density of 1 M H2SO4 solution = 1.4 g/mL
- Volume of 2.5 M HCl solution = 400 mL
- Density of 2.5 M HCl solution = 1.25 g/mL
- Final solution density = 1.2 g/mL
Approach:
1. Calculate the mass of H2SO4 and HCl solutions.
2. Determine the total volume of the final solution.
3. Use the mass and volume information to calculate the concentration of H+ ions in the final solution.
Calculations:
1. Mass of H2SO4 solution:
Mass = Volume × Density
Mass = 500 mL × 1.4 g/mL
Mass = 700 g
2. Mass of HCl solution:
Mass = Volume × Density
Mass = 400 mL × 1.25 g/mL
Mass = 500 g
3. Total volume of the final solution:
Volume = Volume of H2SO4 solution + Volume of HCl solution
Volume = 500 mL + 400 mL
Volume = 900 mL
4. Mass of the final solution:
Mass = Mass of H2SO4 solution + Mass of HCl solution
Mass = 700 g + 500 g
Mass = 1200 g
5. Concentration of H+ ions in the final solution:
Concentration of H2SO4 solution = 1 M
Concentration of HCl solution = 2.5 M
Total moles of H+ ions = Moles from H2SO4 solution + Moles from HCl solution
Moles from H2SO4 solution = Concentration × Volume
Moles from H2SO4 solution = 1 M × (500 mL / 1000 mL/L)
Moles from H2SO4 solution = 0.5 moles
Moles from HCl solution = Concentration × Volume
Moles from HCl solution = 2.5 M × (400 mL / 1000 mL/L)
Moles from HCl solution = 1 mole
Total moles of H+ ions = 0.5 moles + 1 mole
Total moles of H+ ions = 1.5 moles
Concentration of H+ ions in the final solution = Total moles / Total volume
Concentration of H+ ions = 1.5 moles / (900 mL / 1000 mL/L)
Concentration of H+ ions = 1.67 M
Conclusion:
The concentration of H+ ions in the final solution is 1.67 M.
- Volume of 1 M H2SO4 solution = 500 mL
- Density of 1 M H2SO4 solution = 1.4 g/mL
- Volume of 2.5 M HCl solution = 400 mL
- Density of 2.5 M HCl solution = 1.25 g/mL
- Final solution density = 1.2 g/mL
Approach:
1. Calculate the mass of H2SO4 and HCl solutions.
2. Determine the total volume of the final solution.
3. Use the mass and volume information to calculate the concentration of H+ ions in the final solution.
Calculations:
1. Mass of H2SO4 solution:
Mass = Volume × Density
Mass = 500 mL × 1.4 g/mL
Mass = 700 g
2. Mass of HCl solution:
Mass = Volume × Density
Mass = 400 mL × 1.25 g/mL
Mass = 500 g
3. Total volume of the final solution:
Volume = Volume of H2SO4 solution + Volume of HCl solution
Volume = 500 mL + 400 mL
Volume = 900 mL
4. Mass of the final solution:
Mass = Mass of H2SO4 solution + Mass of HCl solution
Mass = 700 g + 500 g
Mass = 1200 g
5. Concentration of H+ ions in the final solution:
Concentration of H2SO4 solution = 1 M
Concentration of HCl solution = 2.5 M
Total moles of H+ ions = Moles from H2SO4 solution + Moles from HCl solution
Moles from H2SO4 solution = Concentration × Volume
Moles from H2SO4 solution = 1 M × (500 mL / 1000 mL/L)
Moles from H2SO4 solution = 0.5 moles
Moles from HCl solution = Concentration × Volume
Moles from HCl solution = 2.5 M × (400 mL / 1000 mL/L)
Moles from HCl solution = 1 mole
Total moles of H+ ions = 0.5 moles + 1 mole
Total moles of H+ ions = 1.5 moles
Concentration of H+ ions in the final solution = Total moles / Total volume
Concentration of H+ ions = 1.5 moles / (900 mL / 1000 mL/L)
Concentration of H+ ions = 1.67 M
Conclusion:
The concentration of H+ ions in the final solution is 1.67 M.
Community Answer
500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed wi...
500 cc 1 m H2so4
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500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution?
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500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution?.
500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution?.
Solutions for 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? in English & in Hindi are available as part of our courses for Class 11.
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500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution?, a detailed solution for 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? has been provided alongside types of 500 ml 1 molar H2 S o4 solution of density 1.4 gram per ml is mixed with 400 ml of 2.5 molar HCL solution of density 1.25 gram per ml to give a final solution of density 1.2 gram per ml find the concentration of H ion in the final solution? theory, EduRev gives you an
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