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2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is?
Most Upvoted Answer
2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to...
Here we will apply
M1V1=M2V2
1*200/1000=1200/1000*M2
1/6= M2
Molar concentration of diluted solution is 1/6
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2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to...
Calculation of Molar Concentration of H2SO4 in Dilute Solution
Given:
- Mass of Mg = 2.4 g
- Volume of H2SO4 = 200 mL
- Molarity of H2SO4 = 1 M
- Final volume of solution = 1 L
Step 1: Calculate the moles of Mg
Using the formula:
moles of Mg = mass of Mg / molar mass of Mg
where molar mass of Mg = 24.31 g/mol (atomic weight of Mg)
moles of Mg = 2.4 g / 24.31 g/mol
moles of Mg = 0.0988 mol
Step 2: Calculate the moles of H2SO4
Using the formula:
moles of H2SO4 = molarity of H2SO4 x volume of H2SO4 (in L)
volume of H2SO4 = 200 mL = 0.2 L
moles of H2SO4 = 1 M x 0.2 L
moles of H2SO4 = 0.2 mol
Step 3: Calculate the molarity of H2SO4 in the dilute solution
Since the final volume of the solution is 1 L and the H2SO4 and Mg have reacted completely, the moles of H2SO4 in the solution must be equal to the moles of Mg.
moles of H2SO4 = moles of Mg
molarity of H2SO4 = moles of H2SO4 / volume of solution (in L)
volume of solution = 1 L
molarity of H2SO4 = 0.0988 mol / 1 L
molarity of H2SO4 = 0.0988 M
Answer: The molar concentration of H2SO4 in the dilute solution is 0.0988 M.
Given:
- Mass of Mg = 2.4 g
- Volume of H2SO4 = 200 mL
- Molarity of H2SO4 = 1 M
- Final volume of solution = 1 L
Step 1: Calculate the moles of Mg
Using the formula:
moles of Mg = mass of Mg / molar mass of Mg
where molar mass of Mg = 24.31 g/mol (atomic weight of Mg)
moles of Mg = 2.4 g / 24.31 g/mol
moles of Mg = 0.0988 mol
Step 2: Calculate the moles of H2SO4
Using the formula:
moles of H2SO4 = molarity of H2SO4 x volume of H2SO4 (in L)
volume of H2SO4 = 200 mL = 0.2 L
moles of H2SO4 = 1 M x 0.2 L
moles of H2SO4 = 0.2 mol
Step 3: Calculate the molarity of H2SO4 in the dilute solution
Since the final volume of the solution is 1 L and the H2SO4 and Mg have reacted completely, the moles of H2SO4 in the solution must be equal to the moles of Mg.
moles of H2SO4 = moles of Mg
molarity of H2SO4 = moles of H2SO4 / volume of solution (in L)
volume of solution = 1 L
molarity of H2SO4 = 0.0988 mol / 1 L
molarity of H2SO4 = 0.0988 M
Answer: The molar concentration of H2SO4 in the dilute solution is 0.0988 M.
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2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is?
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2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is?.
2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2.4 g of Mg is treated with 200 mL of 1M H2SO4 and solution diluted to 1 L. Molar concentration of H2SO4 in dilute solution is?.
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