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A plank of mass m moving with a velocity v along a frictionless horizontal track and a body of mass m/2 moving with 2v collides with plank drastically final speed of the plank is?
Most Upvoted Answer
A plank of mass m moving with a velocity v along a frictionless horizo...
Initial Conditions:
- Mass of the plank: m
- Velocity of the plank: v
- Mass of the body: m/2
- Velocity of the body: 2v

Conservation of Momentum:
When two bodies collide, the total momentum before the collision is equal to the total momentum after the collision, provided there are no external forces acting on the system. Mathematically, it can be expressed as:
m1*v1 + m2*v2 = m1*v1' + m2*v2'

In this case, the momentum of the plank before the collision is mv, and the momentum of the body before the collision is (m/2)*(2v) = mv. After the collision, the final velocity of the plank is v' and the final velocity of the body is 2v'. Therefore, we can write the equation as:
mv + mv = mv' + (m/2)*(2v')

Simplifying the equation:
2mv = mv' + mv'
2mv = 2mv'
v' = v

Explanation:
The final speed of the plank after the collision is equal to its initial speed. This means that the collision between the plank and the body does not change the speed of the plank. The velocity of the body does not affect the final speed of the plank because the mass of the body is only half of the mass of the plank.

Conclusion:
When a plank of mass m moving with velocity v collides with a body of mass m/2 moving with 2v, the final speed of the plank remains the same as its initial speed, v. The collision does not change the speed of the plank.
Community Answer
A plank of mass m moving with a velocity v along a frictionless horizo...
Plank will stop v=0m/s
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