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A merchant have a diamond, the cost of diamond is square of its weight. If a diamond broken in 4 parts in1:2:3:4.He sold all four parts then he got 7,000 loss at all . find its real cost?
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A merchant have a diamond, the cost of diamond is square of its weigh...
Ans.

Cost ∝ (weight)
2
Total weight of original diamond = 1k + 2k + 3k + 4k = 10k, where k is positive integer
Cost of original diamond = (10k)
2
 = 100k
2
Total cost of four broken pieces = k
2
(1 + 4 + 9 + 16) = 30k
2
The value of broken pieces is 70,000 less than the original diamond.
Difference in cost = 70,000
100k
2
 - 30k
2
 = 70,000
70k
2
 = 70,000
k
2
 = 1,000
Cost of original diamond = 100k
2
 = 100 � 1,000
= 1,00,000
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A merchant have a diamond, the cost of diamond is square of its weight. If a diamond broken in 4 parts in1:2:3:4.He sold all four parts then he got 7,000 loss at all . find its real cost?
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A merchant have a diamond, the cost of diamond is square of its weight. If a diamond broken in 4 parts in1:2:3:4.He sold all four parts then he got 7,000 loss at all . find its real cost? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about A merchant have a diamond, the cost of diamond is square of its weight. If a diamond broken in 4 parts in1:2:3:4.He sold all four parts then he got 7,000 loss at all . find its real cost? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A merchant have a diamond, the cost of diamond is square of its weight. If a diamond broken in 4 parts in1:2:3:4.He sold all four parts then he got 7,000 loss at all . find its real cost?.
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