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Assignment - Triangles, Class 10 Mathematics PDF Download

VERY SHORT ANSWER TYPE QUESTIONS

1. In the given figure, XY||BC.
Given that AX = 3 cm, XB = 1.5 cm and BC = 6 cm.
Calculate :
(i) AY/ YC        
(ii) XY.

CBSE Class 10,Class 10 Mathematics

2. D and E are points on the sides AB and AC respectively of ΔABC. For each of the following cases, state whether DE||BC:
(i) AD = 5.7 cm, BD = 9.5 cm, AE = 3.6 cm and EC = 6 cm
(ii) AB = 5.6 cm, AD = 1.4 cm, AC = 9.6 cm and EC = 2.4 cm.
(iii) AB = 11.7 cm, BD = 5.2 cm, AE = 4.4 cm and AC = 9.9 cm.
(iv) AB = 10.8 cm, BD = 4.5 cm, AC = 4.8 cm and AE = 2.8 cm.

3. In ΔABC, AD is the bisector of ∠A. If BC = 10 cm, BD = 6 cm and AC = 6 cm, find AB. 

CBSE Class 10,Class 10 Mathematics

4. AB and CD are two vertical poles of height 6 m and 11 m respectively. If the distance between their feet is 12 m, find the distance between their tops.

CBSE Class 10,Class 10 Mathematics

5. ΔABC and ΔPQR are similar triangles such that area (ΔABC) = 49 cm2 and area (ΔPQR) = 25 cm2.

If AB = 5.6 cm, find the length of PQ .

6. ΔABC and ΔPQR are similar triangles such that area (ΔABC) = 28 cm2 and area (ΔPQR) = 63 cm2.

If PR = 8.4 cm, find the length of AC.

7. ΔABC ~ ΔDEF. If BC = 4 cm, EF = 5 cm and area (ΔABC) = 32 cm2, determine the area of ΔDEF.

8. The areas of two similar triangles are 48 cm2 and 75 cm2 respectively. If the altitude of the first triangle be 3.6 cm, find the corresponding altitude of the other.

9. A rectangular field is 40 m long and 30 m broad. Find the length of its diagonal.

10. A man goes 15 m due west and then 8 m due north. How far is he from the starting point?

11. A ladder 17 m long reaches the window of a building 15 m above the ground. Find the distance of the foot of the ladder from the building.

SHORT ANSWER TYPE QUESTIONS

1. In the given fig, DE||BC.
(i) If AD = 3.6 cm, AB = 9 cm and AE = 2.4 cm, find EC.

(ii) If AD / DB = 35 and AC = 5.6 cm, find AE.

CBSE Class 10,Class 10 Mathematics

(iii) If AD = x cm, DB = (x–2) cm, AE = (x+2) cm and EC = (x–1) cm, find the value of x.

2. In the given figure, BACBSE Class 10,Class 10 MathematicsDC. Show that ΔOAB ~ ΔODC. If AB = 4 cm, CD = 3 cm, OC = 5·7 cm and OD = 3·6 cm, find OA and OB.

CBSE Class 10,Class 10 Mathematics

3. In the given figure, ∠ABC = 90° and BD CBSE Class 10,Class 10 Mathematics AC. If AB = 5·7 cm, BD = 3·8 cm and CD =5·4 cm, find BC.

CBSE Class 10,Class 10 Mathematics

4. In the given figure, ΔABC ~ ΔPQR and AM, PN are altitudes, whereas AX and PY are medians. Prove that

CBSE Class 10,Class 10 Mathematics

5. In the given figure, BCCBSE Class 10,Class 10 MathematicsDE, area (ΔABC) = 25 cm2, area (trap. BCED) = 24 cm2 and DE = 14 cm. Calculate the length of BC.

CBSE Class 10,Class 10 Mathematics

6. In ΔABC, ∠C = 90°. If BC = a, AC = b and AB = c, find :
(i) c when a = 8 cm and b = 6 cm.
(ii) a when c = 25 cm and b = 7 cm
(iii) b when c = 13 cm and a = 5 cm

7. The sides of a right triangle containing the right angle are (5x) cm and (3x – 1) cm. If the area of triangle be 60 cm2, calculate the length of the sides of the triangle.

8. Find the altitude of an equilateral triangle of side 5√3 cm.

9. In the adjoining figure (not drawn to scale), PS = 4 cm, SR = 2 cm, PT = 3 cm and QT = 5cm.
(i) Show that ΔPQR ~ ΔPST. (ii) Calculate ST, if QR = 5·8 cm.

CBSE Class 10,Class 10 Mathematics

10. In the given figure, ABCBSE Class 10,Class 10 MathematicsPQ and ACCBSE Class 10,Class 10 MathematicsPR. Prove that BCCBSE Class 10,Class 10 MathematicsQR.

CBSE Class 10,Class 10 Mathematics

11. In the given figure, AB and DE are perpendicular to BC. If AB = 9 cm, DE = 3 cm and AC = 24 cm, calculate AD.

CBSE Class 10,Class 10 Mathematics

12. In the given figure, DE ⊥ BC. If DE = 4 cm, BC = 6 cm and area (ΔADE) = 20 cm2, find the area of ΔABC.

CBSE Class 10,Class 10 Mathematics

13. A ladder 15 m long reaches a window which is 9 m above the ground on one side of the street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 12 m high. Find the width of the street.

CBSE Class 10,Class 10 Mathematics

14. In the given figure, ABCD is a quadrilateral in which BC = 3 cm, AD = 13 cm, DC = 12 cm and ∠ABD = ∠BCD = 90°. Calculate the length of AB.

CBSE Class 10,Class 10 Mathematics

15. In the given figure, ∠PSR = 90°, PQ = 10 cm, QS = 6 cm and RQ = 9 cm, calculate the length of PR.

CBSE Class 10,Class 10 Mathematics

16. In a rhombus PQRS, side PQ = 17 cm and diagonal PR = 16 cm. Calculate the area of the rhombus.

17. From the given figure, find the area of trapezium ABCD.

CBSE Class 10,Class 10 Mathematics

18. In a rhombus ABCD, prove that AC2 + BD2 = 4AB2.

19. A ladder 13 m long rests against a vertical wall. If the foot of the ladder is 5 m from the foot of the wall, find the distance of the other end of the ladder from the ground.

LONG ANSWER TYPE QUESTIONS

1. In the given figure, it is given that ∠ABD = ∠CDB = ∠PQB = 90°. If AB = x units, CD = y units and PQ = z units, prove that  CBSE Class 10,Class 10 Mathematics

CBSE Class 10,Class 10 Mathematics

2. In the adjoining figure, ABCD is a parallelogram, P is a point on side BC and DP when produced meets AB produced at L. Prove that: (i) DP : PL = DC : BL (ii) DL : DP = AL : DC.

CBSE Class 10,Class 10 Mathematics

3. In the given figure, ABCD is a parallelogram, E is a point on BC and the diagonal BD intersects AE at F. Prove that: DF × FE = FB × FA.

CBSE Class 10,Class 10 Mathematics

4. In the adjoining figure, ABCD is a parallelogram in which AB = 16 cm, BC = 10 cm and L is a point on AC such that CL : LA = 2 : 3. If BL produced meets CD at M and AD produced at N, prove that:

(i) ΔCLB ~ ΔALN (ii) ΔCLM ~ ΔALB

CBSE Class 10,Class 10 Mathematics

5. In the given figure, medians AD and BE of ΔABC meet at G and DF||BE. Prove that

(i) EF = FC (ii) AG : GD = 2 : 1.

CBSE Class 10,Class 10 Mathematics

6. In the given figure, the medians BE and CF of ΔABC meet at G. Prove that:

(i) ΔGEF ~ ΔGBC and therefore, BG = 2GE. (ii) AB × AF = AE × AC.

CBSE Class 10,Class 10 Mathematics

7. In the given figure, DE⊥BC and BD = DC.

CBSE Class 10,Class 10 Mathematics
(i) Prove that DE bisects ∠ADC.

(ii) If AD = 4·5 cm, AE = 3·9 cm and DC = 7-5 cm, find CE.

(iii) Find the ratio AD : DB.

8. O is any point inside a ΔABC. The bisectors of ∠AOB, ∠BOC and ∠COA meet the sides AB, BC and CA in points D, E and F respectively. Prove that AD·BE·CF = DB·EC·FA.

CBSE Class 10,Class 10 Mathematics

9. In the figure, DE⊥BC.

CBSE Class 10,Class 10 Mathematics

(i) Prove that ΔADE and ΔABC are similar.

(ii) Given that AD = 1/2 BD, calculate DE, if BC = 4.5 cm.

10. In the adjoining figure, ABCD is a trapezium in which AB⊥DC and AB = 2 DC. Determine the ratio of the areas of ΔAOB and ΔCOD.

CBSE Class 10,Class 10 Mathematics

11. In the adjoining figure, LM is parallel to BC. AB = 6 cm, AL = 2cm and AC = 9 cm. Calculate :

(i) the length of CM.

(ii) the value of CBSE Class 10,Class 10 Mathematics

CBSE Class 10,Class 10 Mathematics

12. In the given figure, DE||BC and DE : BC = 3 : 5. Calculate the ratio of the areas of ΔADE and the trapezium BCED.

CBSE Class 10,Class 10 Mathematics

13. In ΔABC, D and E are mid-points of AB and AC respectively. Find the ratio of the areas of ΔADE and ΔABC.

CBSE Class 10,Class 10 Mathematics

14. In a ΔPQR, L and M are two points on the base QR, such that ∠LPQ = ∠QRP and ∠RPM = ∠RQP. Prove that (i) ΔPQL ~ ΔRPM (ii) QL·RM = PL·PM (iii) PQ2 = QL·QR

15. In the adjoining figure, the medians BD and CE of a ΔABC meet at G.

Prove that:

(i) ΔEGD ~ ΔCGB

(ii) BG = 2 GD from (i) above.

CBSE Class 10,Class 10 Mathematics

16. In the adjoining figure, PQRS is a parallelogram with PQ = 15 cm and RQ = 10 cm. L is a point on RP such that RL : LP = 2 : 3. QL produced meets RS at M and PS produced at N. Find the lengths of PN and RM.

CBSE Class 10,Class 10 Mathematics

 

 

ANSWER KEY

VERY SHORT ANSWER TYPE QUESTIONS

1. (i) 2/1 (ii) 4 cm 2. (i) Yes, (ii) No, (iii) No, (iv) Yes

3. 9 cm

4. 13 m

5. PQ = 4 cm

6. AC = 5.6 cm

7. 50 cm2
8. 4.5 cm

9. 50 m

10. 17 m

11. 8 m

SHORT ANSWER TYPE QUESTIONS

1. (i) 3.6 cm, (ii) 2.1 cm, (iii) x = 4 2. OA = 4.8 cm, OB = 7.6 cm

3. 8.1 cm

5. 10 cm

6. (i) 10 cm, (ii) 24 cm, (iii) 12 cm
7. 15cm, 8 cm, 17cm

8. 7.5 cm

9. 2.9 cm

11. 16 cm

12. 45 cm2

13. 21 m

14. 4 cm

15. 17 cm

16. 240 cm2
17. 14 cm2

19. 12 m

LONG ANSWER TYPE QUESTIONS

7. (ii) 6.5 cm, (ii) 3 : 5 9. DE = 1.5 cm

10. 4 : 1

11. (i) 6 cm, (ii) 1/8

12. 9 : 16

13. 1 : 4

16. PN = 15 cm, RM = 10 cm

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FAQs on Assignment - Triangles, Class 10 Mathematics

1. What are the different types of triangles based on their angles?
Ans. There are three types of triangles based on their angles: 1. Acute-angled triangle: A triangle in which all three angles are less than 90 degrees. 2. Obtuse-angled triangle: A triangle in which one angle is greater than 90 degrees. 3. Right-angled triangle: A triangle in which one angle is exactly 90 degrees.
2. Can a triangle have two right angles?
Ans. No, a triangle cannot have two right angles. The sum of all three angles in a triangle is always 180 degrees. Since a right angle measures 90 degrees, having two right angles would result in a sum of 180 degrees, leaving no room for the third angle.
3. How can we determine if three given sides form a triangle?
Ans. To determine if three given sides form a triangle, we can apply the triangle inequality theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. If this condition is satisfied for all three combinations of sides, then the given lengths form a triangle.
4. What is Pythagoras' theorem and how is it used in triangles?
Ans. Pythagoras' theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. It can be represented as a^2 + b^2 = c^2, where "a" and "b" are the lengths of the two sides, and "c" is the length of the hypotenuse. This theorem is widely used to find the length of a side or to determine if a triangle is a right-angled triangle.
5. What is the sum of the angles in a triangle?
Ans. The sum of the three angles in any triangle is always equal to 180 degrees. This property is known as the angle sum property of triangles. It holds true for all types of triangles, whether they are acute-angled, obtuse-angled, or right-angled.
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