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Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET PDF Download

Change of basis

Consider an n x n matrix A and think of it as the standard representation of a transformation TA : Rn → Rn. If we pick a different basis {v1,... vn} of Rn, what matrix B represents TA with respect to that new basis?

Write V = [v1 v2 ... vn] and consider the diagram

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

which says the new matrix is B = V -1AV .

Remark: This is an instance of the more general change of coordinates formula. Start with a linear transformation T : V → W . Let A be the "old" basis of V and Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET the "new" basis. Let B be the "old" basis of Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET the "new" basis. Then the diagram 

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET
gives the change of coordinates formula

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Example: Let A = Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET viewed as a linear transformation R2 → R2. Find the matrix B representing the same transformation with respect to the basis  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Write V = [v1 v2]. Then we have

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

What this means is that the transformation A : R2 → R2 is determined by

Av1 = 4v1 + 0v2 = 4v1 (first column of B)

Av2 = 0v1 - 1v2 = v2 (second column of B).

Let us check this explicitly:

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Similar matrices

The change of basis formula B = V-1AV suggests the following de nition.

De nition: A matrix B is similar to a matrix A if there is an invertible matrix S such that B = S-1AS .

In particular, A and B must be square and A; B ; S all have the same dimensions n x n. The idea is that matrices are similar if they represent the same transformation V → V up to a change of basis.

Example: In the example above, we have shown that  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET is similar to Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Exercise: Show that similarity of matrices is an equivalence relation.

Trace of a matrix

How can we tell if matrices are similar? There is an easy necessary (though not sucient) condition.

Denition: The trace of an n x n matrix A is the sum of its diagonal entries:

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Examples:  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Proposition: For any two n x n matrices A and B, we have tr(AB) = tr(BA).

Proof:

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Example:

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Corollary: Similar matrices have the same trace.

Proof: Homework #8.5.

Example: In the example above, we have tr  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

Warning! The converse does not hold. In other words, matrices with the same trace are rarely similar.

Example: The matrices 

Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

all have trace 0, but none of them is similar to another, since they have different ranks (respectively 0, 1, 2).

In fact, for any number a ∈ R the matrix  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET has trace 0. However, if we pick a number  b ≠ +a, then Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET is not similar to  Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

In chapter 4, we will learn better tools to tell whether or not two matrices are similar.

The document Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences | Mathematics for IIT JAM, GATE, CSIR NET, UGC NET is a part of the Mathematics Course Mathematics for IIT JAM, GATE, CSIR NET, UGC NET.
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FAQs on Change of Basis - Matrix Algebra, CSIR-NET Mathematical Sciences - Mathematics for IIT JAM, GATE, CSIR NET, UGC NET

1. What is the concept of change of basis in matrix algebra?
Ans. Change of basis is a concept in matrix algebra that refers to the transformation of a vector from one coordinate system to another. It involves finding the representation of a vector in terms of a different set of basis vectors. This transformation is represented by a change of basis matrix, which allows us to express the vector coordinates in the new basis.
2. How is the change of basis matrix calculated?
Ans. To calculate the change of basis matrix, we need to consider the new basis vectors and express them in terms of the original basis vectors. These expressions form the columns of the change of basis matrix. By taking the original basis vectors as columns, and expressing them in the new basis, we obtain the inverse of the change of basis matrix. In short, the change of basis matrix is calculated by expressing the new basis vectors in terms of the original basis vectors.
3. What is the significance of change of basis in the context of CSIR-NET Mathematical Sciences exam?
Ans. Change of basis is a fundamental concept in linear algebra, which is a crucial topic in the CSIR-NET Mathematical Sciences exam. It allows us to simplify computations, analyze transformations, and solve systems of linear equations. Understanding change of basis is important for effectively solving problems related to linear transformations, eigenvalues, eigenvectors, and diagonalization, which are frequently tested in the exam.
4. Can you provide an example of a change of basis problem in matrix algebra?
Ans. Sure! Let's consider a 2-dimensional vector space with two basis vectors: v1 = [1, 0] and v2 = [0, 1]. Now, we want to express a vector u = [3, 4] in terms of a new basis vectors w1 = [1, 1] and w2 = [-1, 1]. To find the change of basis matrix, we need to express w1 and w2 in terms of v1 and v2. Let's say w1 = a*v1 + b*v2 and w2 = c*v1 + d*v2. By solving the system of equations, we find that the change of basis matrix is [[1, -1], [1, 1]]. We can then multiply this matrix with the vector u to obtain the coordinates of u in the new basis.
5. How does change of basis relate to the concept of similarity in matrix algebra?
Ans. Change of basis is closely related to the concept of similarity in matrix algebra. When two matrices are similar, it means that they represent the same linear transformation under different coordinate systems. The change of basis matrix allows us to transform a matrix to a different basis, resulting in a similar matrix. Similar matrices share several important properties, such as having the same eigenvalues, determinant, and trace. Understanding change of basis is therefore crucial in studying the similarity of matrices.
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