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Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10 PDF Download

Class X
Mathematics – Standard (041)
Sample Question Paper 2019-20

Max. Marks: 80
Duration : 3 hrs

General Instructions:
(i) All the questions are compulsory.
(ii) The question paper consists of 40 questions divided into 4 sections A, B, C, and D.
(iii) Section A comprises of 20 questions of 1 mark each. Section B comprises of 6 questions of 2 marks each. Section C comprises of 8 questions of 3 marks each. Section D comprises of 6 questions of 4 marks each.
(iv) There is no overall choice. However, an internal choice has been provided in two questions of 1 mark each, two questions of 2 marks each, three questions of 3 marks each, and three questions of 4 marks each. You have to attempt only one of the alternatives in all such questions.
(v) Use of calculators is not permitted.

Section A

Q.1. If an event that cannot occur, then its probability is :    (1 Mark)
(a) 1
(b) 3/4
(c) 1/2
(d) 0
Ans.(d)
An event that cannot occur has 0 probability, such an event is called impossible event.

Q.2. The smallest rational number by which 1/7 should be multiplied so that its decimal expansion terminates after one place of decimal is:    (1 Mark)
(a) 7
(b) 7/10
(c) 7/100
(d) 1/10

Ans. (b)
[Here, 1/7 is non - terminating decimal expansion
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10 which terminates after one place of decimal]

Q.3. The distance between two parallel tangents to a circle of radius 7 cm, is    (1 Mark)
(a) 49 cm 
(b) 7 cm 
(c) 14 cm 
(d) 28 cm
Ans. (c) The distance between two parallel tangents to a circle of radius 7 cm is 2 x 7 = 1 4 qm.

Q.4. The zeroes of the quadratic polynomial x2 - 13x + 40 are    (1 Mark)
(a) 8, 5
(b) - 8, - 5
(c) 8, -5
(d) -8, 5
Ans. 
(a)

The zeroes of the given polynomial are given by the equation
x2 - 13x + 40 = 0
⇒ x2 - 5x - 8x + 40 - 0
⇒ x(x - 5) - 8(x - 5) = 0
⇒ (x - 5)(x - 8) = 0
⇒ x = 5 = 0 or x - 8 = 0
⇒ x = 5 or x = 8
Hence, the zeroes of the Polynomial are 5 and 8.

Q.5. (sec A + tan A) (1 - sin A) =    (1 Mark)
(a) sec A 
(b) sin A 
(c) cosec A 
(d) cos A
Ans. (d)
(sec A + tan A) (1 - sin A)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.6. If p sin (90° - θ) cot (90° - θ) = cos (90° - θ), then x =    (1 Mark)
(a) 0 
(b) 1 
(c) - 1 
(d) 2
Ans. (b)
[Here, p sin (90° - θ) cot (90° - θ)
= cos (90° - θ) ⇒ cos θ.tan θ = sin θ
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.7. Which of the following is a solution of 2x2 - 5x - 3 = 0 ?    (1 Mark)
(a) x = 0 
(b) x = 1 
(c) x = 3 
(d) x = 2
Ans.  (c) Given, 2x2 - 5x - 3 = 0
Splitting the middle term we get,
2x2 - 6x+ x - 3 = 0
⇒ 2x (x - 3) + 1 (x - 3) = 0
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, x = 3 is the solution.

Q.8. The probability of a sure event is __________.    (1 Mark)
Ans. 1

Q.9. If the zeroes of the quadratic polynomial ax2 + bx + c, a ≠ 0 are equal, then :    (1 Mark)
(a) c and a have opposite signs 
(b) c and b have opposite signs 
(c) c and a have the same sign 
(d) c and b have the same sign
Ans. : For equal roots b2 - 4ac = 0 or b2 = 4ac
b2 is always positive so 4ac must be positive , i.e., product of a and c must be positive, i.e., a and c must have same sign either positive or negative.

Q.10. The equation of the perpendicular bisector of AB, where A and B are the points (3, 6) and (- 3, 4) is :    (1 Mark)
(a) 3x + y - 5 = 0 
(b) x + 3y - 5 = 0 
(c) x - 3y + 5 = 0 
(d) - x - 3y + 5 = 0 
Ans. (a) 3x + y - 5 = 0
[Here, PA = PB, where P(x, y) is any point on the perpendicular bisector of AB.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.11. Suppose 0 < θ, φ < 90° and sin θ and cos φ will be equal, when θ and φ both are equals to......    (1 Mark)
Ans. (π/4) sin θ and cos will be equal, when
θ = φ = π/4

Q.12. The probability of face card of spade from a pack of cards is 3/52.    (1 Mark)
Ans. True
Total number of outcomes = 52
Number of favourable events = 3 as there are only 3 face cards of spade i.e., J, Q, K.
∴ P(Face cards of space) = 3/52.

Q.13. If one root of 7x2 + 16x + k = 0 is the reciprocal of the other root then find value of k.    (1 Mark)
Ans. Let α and 1/α be the roots of the given quadratic polynomial.
∴  Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒ k = 7

Q.14. If 2x, x + 10 and 3x + 2 are in AP, then x = ..........    (1 Mark)
Ans. [x + 10 - 2x = 3x + 2 - (x + 10)
10 - x = 3x + 2 - x - 10
⇒ 3x = 18 ⇒ x = 6]

Q.15. The arithmetic mean between two numbers a and b is .......    (1 Mark)
Ans. AM between a and b Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.16. Find the value(s) of k for which the quadratic equation 3x2 + kx + 3 = 0 has real and equal roots.    (1 Mark)
Ans. The given equation is 3x2 + kx + 3 = 0
Comparing it with the standard equation ax2 + bx + c, we have
a = 3, b = k, c = 3
The roots will be real and equal if discriminant,
D = b2 - 4ac = 0
i.e., k2 - 4 x 3 x 3 = 0
⇒ k2 = 36
⇒ k = ± 6
Hence, the roots of the equation are real and equal for k = ± 6.

Q.17. Find the distance of the point (- 4, - 7) from the y-axis.    (1 Mark)
Ans. Points are (- 4, - 7) and (0, - 7)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.18. Find the sum of all numbers between 250 and 1000 which are exactly divisible by 3.    (1 Mark)
Ans. Numbers between 250 and 1000, which are exactly divisible by 3 are :
252, 255, 258, ..., 999
Using a + (n - 1)d = an, we have
252 + (n - 1)3 = 999
(n - 1)3 = 999 - 252
= 747
= n - 1 = 747/3 = 249
∴ n = 249 + 1 = 250
Now, required sum of all such numbers
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.19. Find the nature of the roots of the equation 3x2 +6a + 1 = 0.
Or
Find the values of t, so that (t + 4)x2 + (t + 1)x +1 = 0 has real and equal roots.    (1 Mark)

Ans. Given, 3a+ 6x + 1 = 0
a = 3,b = 6 andc = 1
Discriminant, D = b2 - 4ac
= (6)2 - 4 x 3 x 1
= 36 - 12 = 24 >0
Hence, the given equation has two distinct real roots.
Or
Discriminant = b2 - 4ac
= (t + 1)2 - 4(t + 4) x 1
= t2 - 2t - 15
For equal roots, discriminant = 0
∴ t2 - 2t - 15 = 0
⇒ t2 - 5t + 3t - 15 = 0
⇒ t = 5 or t = - 3
Hence, the value of t is 5, - 3.

Q.20. Find the value of ‘a’ so that the point (3, a) lies on the line represented by 2x - 3y = 5.    (1 Mark)
Ans. The point (3, a) lies on the line given by the equation 2x - 3y = 5
The coordinates of the point satisfy the above equation.
2 x 3 - 3 x a = 5
⇒ - 3a = - 1
⇒ a = 1/3

Section B

Q.21. Explain whether 3 x 12 x 101 + 4 is a prime number or a composite number.    (2 Mark)
Ans. 3 x 12 x 101 + 4= 4(3 x 3 x 101 + 1)
= 4(909 + 1) ................
= 4(910)
= 2 x 2 x 2 x 5 x 7 x 13
= a composite number
[∵ Product of more than two prime factors]

Q.22. Prove that the segment joining the points of contact of two parallel tangents passes through the centre.    (2 Mark)
Ans. Let P be the point of contact and l be the tangent at the point P on the circle with centre O.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Since OP is the radius of the circle and 1 is tangent.
∴ OP ⊥ l
Similarly, OQ ⊥ m
Since l and m are two parallel tangents.
∴ Perpendicular at P and Q passes through the centre of the circle.

Q.23. A teacher of Class X write some information about the tour on blackboard as follows: 
Beginning at 8:30 am, tours of the national capital and the white house begin at a tour agency. Tours for the national capital leave every 15 min. Tours for the white house leave every 20 min. How many minutes after do the tours leave at the same time ?    (2 Mark)
Ans. Required time = LCM (15, 20).
By using prime factorisation method,
Now, 15 = 3 x 5
and 20 = 2 x 2 x 5 = 2 2 x 5
∴ LCM (15, 20) = 22 x 3 x 5 = 60 min
In every 60 min, tour leaves at the same time.

Q.24. Find the HCF of 612 and 1314 using prime factorisation. 
Or 
Show that any positive odd integer is of the form 6m + 1 or 6m + 3 or 6m + 5, where m is some integer    (2 Mark)
Ans. We have
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
∴ HCF = 21 x 32 = 2 x 9 = 18
Or
Let a be any odd positive integer.
When a is divided by 6, remainder will be one of 0, 1, 2, 3, 4, 5.
a = 6m + 0 i.e., 6m or 6m +1 or 6m + 2 or 6m + 3 or 6m + 4 or 6m + 5
When a = 6m, which is even positive integer as it is divisible by 2.
When a = 6m + 2 = 2(3m + 1), which is even positive integer as it is divisible by 2.
When a = 6m + 4 = 2(3m + 2), which is even positive integer as it is divisible by 2.
Hence, every odd positive integer is of the form 6m + 1 or 6m + 3 or 6m + 5.

Q.25. Find the ratio in which y-axis divides the line segment joining the points A(5, -6) and B(-1, -4). Also find the co-ordinates of the point of division.    (2 Mark)
Ans. Let the point on y-axis be (0, y) and AP :PB = k: 1.
Therefor Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, required ratio is 5 :1
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, point on y- axis is Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.26. Due to heavy floods in a state, thousands were rendered homeless. 50 schools collectively offered to the state government to provide place and the canvas for 1500 tents to be fixed by the government and decided to share the whole expenditure equally. The lower part of each tent is cylindrical of base radius 2.8 m and height 3.5 m, with conical upper part of same base radius but of height 2.1 m. If the canvas used to make the tents cost Rs. 120 per sq. m, find the amount shared by each school to set-up the tents.[Use π = 22/7]    (2 Mark)
Ans. Here, radius of base of cylindrical portion = radius of base of conical portion (r)
= 2.8 m
Height of cylindrical portion = 3,5 m
Height of conical portion = 2.1 m
∴ Slant height of conical portion
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Area of canvas used to make the tent
=C.S.A. of cylindrical portion + C.S.A. of conical portion
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Section C

Q.27. Find the roots of the quadratic equation :    (3 Mark)
a2b2x2 + b2x - a2x - 1 = 0
Ans. Given, a2b2x2 + b2x - a2x - 1 = 0
⇒ b2x(a2x + 1) - 1(a2x + 1) = 0
⇒ (b2x - 1)(a2x + 1) = 0
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.28. A spiral is made-up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2 .0 c m , ... as shown in figure. What is the total length of such a spiral made-up of 13 consecutive semicircles ?    (3 Mark)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Ans. Since radii of semicircles are 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm ...
Now, length of first semicircle (l1)
= Perimeter of first semicircle
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Now, length of second semicircle (l2)
= Perimeter of second semicircle
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Similarly, we can get the length of other
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
and so on upto 13 semicircles.
Let S be total length of all semicircles.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.29. Find the value of p for which the points A (- 1, 3), B (2, p) and C (5, -1) are collinear. Also, find the ratio in which B divides AC.
Or 
The two opposite vertices of a square are (-1,2) and (3,2). Find the coordinates of the other two vertices.    (3 Mark)
Ans. If the given points A (-1, 3), B(2, p) and C(5, -1) are coilinear, then area of the triangle formed by these points is 0.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒ x1(y2 - y3)+x2(y3 - y1) + x3(y1 - y2) = 0
⇒ -1(p + 1)+2(-1-3) + 5(3-p) = 0
⇒ - p - 1 - 8 + 15 - 5p = 0
⇒ - 6p + 6 = 0 ⇒ p = 1
Thus, for p = 1, the given points are coliinear.
Now, let S(2,p) = B(2,1) divides the line segment joining the points A and C internally in the ratio k:1.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
By using internal section formula, we get
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒  Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
[comparing x-coordinate from both sides]
⇒ 5k - 1 = 2k + 2
⇒ 5k - 2k = 2 + 1
⇒ 3k = 3 ⇒ k = 1
Hence, the required ratio is 1:1.
Or
Let PQRS be a square with opposite vertices P (- 1,2) and R (3,2). Again, iet the coordinates of other vertices Q be (x, y).
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
∵ All sides of a square’are equal,
∴ PQ = QR
⇒ PQ2 = QR2 [squaring both sides]
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, other two vertices of the square are (1,0) and (1, 4).

Q.30. A part of monthly hostel charges in a college hostel are fixed and the remaining depends on the number of days one has taken food in the mess. When a student A takes food for 25 days, he has to pay Rs. 4,500, whereas a student B who takes food for 30 days, has to pay Rs. 5,200. Find the fixed charges per month and the cost of food per day.    (3 Mark)
Ans. Let the fixed hostel charges be Rs. x and the cost of food per day be Rs. y.
∴ Total charges for 25 days = Fixed hostel charges + Food charges for 25 days
= Rs. (x + 25y) = Rs. 4500 (Given)
∴  x+ 25y = 4500 ...(1)
Similarly, x + 30y = 5200    ...(2)
Subtracting (1) from (2), we get
5y = 70
⇒ y = 140
Putting the value of y from (3) in (1), we get     ...(3)
x + 25 x 140 = 4500
   x + 3500 = 4500
   x = 4500 - 3500 = 1000
∴ Fixed hostel charges = Rs. 11000 and cost of food per day = Rs. 140.

Q.31. The points A(1, - 2), B(2,3), C(k, 2) and D(- 4, - 3) are the vertices of a parallelogram. Find the value of k.    (3 Mark)
Ans.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Diagonals of parallelogram bisect each other
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.32. If tan A = 2, evaluate : sec A sin A + tan2A - cosec A.
Or
If A + B = 90°, then prove that:    (3 Mark)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Ans. We know that, cosec2A = 1 + cot2A
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.33. In the figure, ABC is a quadrant of a circle of radius 14 cm and a semi-circle is drawn with AC as a diameter. Find the area of the shaded region.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Or
A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see the figure).    (3 Mark)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Find 
(i) the area of the part of the field in which the horse can graze. 
(ii) the increase in the grazing area if the rope were 10m long instead of 5 m.[take, π = 3.14]    (3 Mark)
Ans. In right angled ΔABC,
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
∴ Radius of semi-circle, ACQA = 7√2 cm
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Now, area of shaded portion = Area of APCQA
= Area of semi-circle ACQA - (Area of quadrant BAPC - Area of ΔABC)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
= 154 - 154 + 98
= 98 cm2
Or
Given, length of rope = 5 m
Radius of arc = 5 m
(i) Area of the field the horse can graze
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
(ii) If length of rope = 10 m = r1 (say)
Then, area of the field graze by the horse,
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
∴ Required increase in the grazing area
= A2 - A1 = 78.5 m2 -  19.625 m2 
= 58.875 m2

Q.34. A girl empties, a cylindrical bucket full of sand, of base radius 18 cm and height 32 cm on the floor to form a conical heap of sand. If the height of this conical heap is 24 cm, then find its slant height correct to one place of decimal.    (3 Mark)
Ans. Radius of cylindrical bucket, r = 18 cm and height of cylindrical bucket, h = 32 cm
∴ Volume of the sand in the cylindrical bucket = πr2h = (18)2 x 32π cm3 = (18 x 18 x 32)π cm3 
Height of conical heap, H = 24 cm
Let R be the radius of the conical heap.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Volume of the cylindrical bucket = Volume of the conical heap
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒ R2 = (18 x 18 x 4)
⇒ R = 36 cm
Slant height l of the conical heap is given by
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, the slant height of the heap = 43.2 cm

Section D

Q.35. The following table gives the weight of 120 articles :
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Change the distribution to a 'more than type' distribution and draw its give.    (4 Mark)
Ans.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.36. In the given figure, the line segment PQ is parallel to AC of ΔABC and it divides the triangle into two parts of equal area. Find the ratio AP/AB.    (4 Mark)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Ans. In ΔABC, PQ || AC
∠A = ∠P and ∠C = ∠Q
In ΔBPQ and ΔBAC [∵ corr. angles]
∠B = ∠B [common]
∴ ΔBPQ ~ ΔBAC
[by AAA similarity rule]
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.37. Prove that the line segments joining the mid-points of the sides of a triangle form four triangles, each of which is similar to the original triangle.
Or
In ΔPQR, PS⊥ R and (PS)2 = QS x RS.
Prove that ΔPQR is a right angled triangle.    (4 Mark)
Ans. Let D, E and F are the mid-points of sides BC, CA and AB respectively of ΔABC.DE, EF and FD are joined.
To prove ΔAFE, ΔFBD, ΔEDC and ΔDEF are similar to ΔABC.
Proof In ΔABC, F and E are the mid-points of sides AB and AC, respectively
FE ║ BC
[segment joining the mid-points of any two sides of triangles is parallel to the third side]
Similarly, DF ║ CA and DE ║ BA
In ΔAFE and ΔABC,
∠A = ∠A [common angle]
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
∠AFE = ∠B [corresponding angles]
∴  ΔAFE ∼ ∠ABC ...(i)
[by AA similarity criterion]
Similarly, we can prove
ΔFBD ∼ ΔABC ...(ii)
and ΔEDC ∼ ΔABC      ...(iii).
Now, in ΔDEF and ΔABC,
∠D = ∠A
[opposite angles of parallelogram AFDE]
∠DEF = ∠B
[opposite angles of parallelogram BDEF]
∴  ΔDEF - ΔABC     ......(iv)
[by AA similarity criterion]
From Eqs. (i), (ii), (iii) and (iv), we conclude that each of ΔAFE, ΔFBD, ΔFDC and ΔDEF is similar to ΔABC. Hence proved.
Or
In right angled ΔPSQ and ΔPSR,
(PQ)2 = (PS)2 + (QS)2 .......(i)
and (PR)2 = (PS)2 + (SR) ...(ii)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
On adding Eqs, (i) and (ii), we get (PQ)2 + (PR)2 = 2 (PS)2 + (QS)2 + (SR)2
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, ΔPQR is a right angled triangle, right angled at P.

Q.38. A boy standing on a horizontal plane finds a bird flying at a distance of 100 m from him at an elevation of 30°. A girl standing on the roof of a 20 m high building, finds the elevation of the same bird to be 45°. The boy and the girl are on the opposite sides of the bird. Find the distance of the bird from the girl.    [Given √2 = 1.414]
Or
The angle of elevation of an aeroplane from a point A on the ground is 60°. After a flight of 30 seconds, the angle of elevation changes to 30°. If the plane is flying at a constant height of 3600√3 metres, find the speed of the aeroplane.    (4 Mark)

Ans. Let A be the position of the bird; C be the position of the boy standing on horizontal plane and E be the position of the girl standing on the roof of building of height DE = 20 m. Draw AB ⊥ on horizontal from A and draw EF ⊥ from E on AB. Then,

AC = 100 m, ∠ACB = 30° and ∠AEF = 45°
From right ΔACB, we have
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒ 1/2 = AB/100
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Hence, distance of the bird from the girl = 42.42 m.
Or
Let P and Q be initial and final positions of the aeroplane. Let ABC be the horizontal line through point of observation A It is given that the angles of elevation of the plane in two positions P and Q from the point A are 60° and 30° respectively. Draw Pi? and QC perpendiculars from P and Q on the horizontal. The plane is flying at a constant height 3600√3m.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Distance travelled by the plane = PQ = BC = AC -AB = (10800- 3600) m = 7200 m
Time taken by the plane in travelling from P to Q = 30 seconds.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

Q.39. The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is 29/20. Find the original fraction.    (4 Mark)
Ans. Let the denominator be x, then numerators = x - 3
So, the fraction = x-3/x
By the given condition, new fraction Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
= x-1/x+2
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
⇒ 20[(x-3) (x + 2) + x (x - 1)] - 29(x2 + 2x)
⇒  20(x2 - x - 6 + x2 - x) 29x2 + 58x 1
⇒ 11x2 - 98x - 120 = 0
⇒ 11x2 - 110x + 12x - 120 = 0
(11x + 12) (x - 10) = 0 or x = 10
The fraction is 7/10

Q.40. Find the mean, mode and median for the following data :    (4 Mark)
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Ans.
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Median : We have
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Mode : We have
Modal class = 20 - 30 [∵ Max. frequency 36 belongs to 20 - 30]
l = 20, h = 10, f1 = 36, f0 = 26 and f2 = 34
Now
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10
Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10

The document Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 | CBSE Sample Papers For Class 10 is a part of the Class 10 Course CBSE Sample Papers For Class 10.
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FAQs on Class 10 Mathematics: CBSE Sample Question Paper (2019-20) - 10 - CBSE Sample Papers For Class 10

1. What is the format of the CBSE Sample Question Paper for Class 10 Mathematics?
Ans. The CBSE Sample Question Paper for Class 10 Mathematics follows the same format as the actual board exam. It consists of various sections, including objective type questions, short answer questions, and long answer questions. The paper is designed to assess the students' understanding and application of mathematical concepts.
2. How can I access the CBSE Sample Question Paper for Class 10 Mathematics (2019-20)?
Ans. The CBSE Sample Question Paper for Class 10 Mathematics (2019-20) can be accessed from the official website of the Central Board of Secondary Education (CBSE). The board releases the sample papers every year to help students understand the exam pattern and practice for the upcoming board exams.
3. Are the CBSE Sample Question Papers for Class 10 Mathematics relevant for the current academic year?
Ans. Yes, the CBSE Sample Question Papers for Class 10 Mathematics (2019-20) are specifically designed for the current academic year. These sample papers are based on the latest syllabus and exam pattern prescribed by the CBSE board. Students can rely on these sample papers for effective exam preparation.
4. Can practicing CBSE Sample Question Papers for Class 10 Mathematics help in scoring better marks in the board exams?
Ans. Yes, practicing CBSE Sample Question Papers for Class 10 Mathematics can significantly improve your chances of scoring better marks in the board exams. These sample papers provide you with a variety of questions that cover the entire syllabus. By solving these papers, you can enhance your problem-solving skills, time management, and accuracy, which are crucial for performing well in the exams.
5. Are the CBSE Sample Question Papers for Class 10 Mathematics sufficient for exam preparation?
Ans. While the CBSE Sample Question Papers for Class 10 Mathematics are an excellent resource for exam preparation, they should not be the sole means of your preparation. It is essential to thoroughly study the textbook, understand the concepts, and practice additional reference books and previous years' question papers. A comprehensive approach will help you grasp the subject better and improve your performance in the board exams.
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