We know area of triangle formed by three points is given by
(i) The vertices are given as (6, 3), (−3, 5), (4, −2).
(ii) The vertices are given as .
(iii) The vertices are given as .
Find the area of the quadrilaterals, the coordinates of whose vertices are
(i) (−3, 2), (5, 4), (7, −6) and (−5, −4)
(ii) (1, 2), (6, 2), (5, 3) and (3, 4)
(iii) (−4, −2, (−3, −5), (3, −2), (2, 3)
(i) Let the vertices of the quadrilateral be A (−3, 2), B (5, 4), C (7, −6), and D (−5, −4). Join AC to form two triangles ΔABC and ΔACD.
(ii) Let the vertices of the quadrilateral be A (1, 2), B (6, 2), C (5, 3), and D (3, 4). Join AC to form two triangles ΔABC and ΔACD.
(iii) Let the vertices of the quadrilateral be A (−4, −2), B (−3, −5), C (3, −2), and D (2, 3). Join AC to form two triangles ΔABC and ΔACD.
GIVEN: The four vertices of quadrilateral are (1, 2), (−5, 6), (7, −4) and D (k, −2) taken in order. If the area of the quadrilateral is zero
TO FIND: value of k
PROOF: Let four vertices of quadrilateral are A (1, 2) and B (−5, 6) and C (7, −4) and D (k, −2)
We know area of triangle formed by three points is given by
Now Area of ΔABC
Taking three points when A (1, 2) and B (−5, 6) and C (7, −4)
Also,
Now Area of ΔACD
Taking three points when A (1, 2) and C (7, −4) and D (k, −2)
Hence
GIVEN: The vertices of triangle ABC are A (−2, 1) and B (5, 4) and C (2, −3)
TO FIND: The area of triangle ABC and length if the altitude through A
PROOF: We know area of triangle formed by three points is given by
Now Area of ΔABC
Taking three points A (−2, 1) and B (5, 4) and C(2, −3)
We have
Now,
We know area of triangle formed by three points is given by
If three points are collinear the area encompassed by them is equal to 0.
The three given points are A(2, 5), B(4, 6) and C(8, 8). Substituting these values in the earlier mentioned formula we have,
= 0
Since the area enclosed by the three points is equal to 0, the three points need to be. The three given points are A(1, −1), B(2, 1) and C(4, 5). Substituting these values in the earlier mentioned formula we have,
= 0
Since the area enclosed by the three points is equal to 0, the three points need to be.
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