If a point is said lie on a line represented by, then the given equation of the line should hold true when the values of the co-ordinates of the points are substituted in it.
Here it is said that the point (3, a) lies on the line represented by the equation.
Substituting the co-ordinates of the values in the equation of the line we have,
Thus the value of ‘a’ satisfying the given conditions is.
We have to find the distance between and .
In general, the distance between A and B is given by,
So,
It is given that mid-point of line segment joining A (6, 5) and B (4, y) is P (2, 6)
In general to find the mid-point of two pointsand we use section formula as,
So,
Now equate the y component to get,
So,
It is given that distance between P (3, 0) and is 5.
In general, the distance between A and B is given by,
So,
On further simplification,
We will neglect the negative value. So,
It is given that mid-point of line segment joining A (6, 5) and B (4, y) is
In general to find the mid-point of two pointsand we use section formula as,
So,
Now equate the y component to get,
So,
It is given that mid-point of line segment joining A (6,−5) and B (−2, 11) is
In general to find the mid-point of two pointsand we use section formula as,
So,
Now equate the y component to get,
Let ABCD be a parallelogram in which the co-ordinates of the vertices are A (1, 2);
B (4, 3) and C (6, 6). We have to find the co-ordinates of the forth vertex.
Let the forth vertex be
Since ABCD is a parallelogram, the diagonals bisect each other. Therefore the mid-point of the diagonals of the parallelogram will coincide.
Now to find the mid-point of two pointsand we use section formula as,
The mid-point of the diagonals of the parallelogram will coincide.
So,
Therefore,
Now equate the individual terms to get the unknown value. So,
Similarly,
So the forth vertex is
(sin2θ+cos2θ=1)
Thus, the distance between the given points is √2 units.
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5 videos|292 docs|59 tests
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