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6. Body is in equilibrium : -

We can say rigid body is in equillibrium when it is in

(a) Translational equilibrium

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Fnet x = 0 and Fnet y = 0 and

(b) Rotational equilibrium

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Note :

(i) If net force on the body is zero then net torque of the forces may or may not be zero.

example. 

A pair of forces each of same magnitude and acting in opposite direction on the rod.

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

(2) If net force on the body is zero then torque of the forces about each and every point is same

t about B Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

t about C Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Ex.18 Determine the point of application of third force for which body is in equillibrium when forces of 20 N & 30 N are acting on the rod as shown in figure 

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Sol. Let the magnitude of third force is F, is applied in upward direction then the body is in the equilibrium when

(i) Equilibrium of a Rigid Body | Physics for JEE Main & Advanced (Translational Equillibrium)

⇒ 20 + F = 30 ⇒ F = 10 N

So the body is in translational equilibrium when 10 N force act on it in upward direction.

(ii)

Let us assume that this 10 N force act. Then keep the body in rotational equilibrium So Tor que about C = 0

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

30 x 20 = 10 x 
x = 60 cm

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

so 10 N force is applied at 70 cm from point A to keep the body in equilibrium.

Ex.19 Determine the point of application of force, when forces are acting on the rod as shown in figure.

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Sol. Since the body is in equillibrium so we conclude Equilibrium of a Rigid Body | Physics for JEE Main & Advanced and torque about any point is zero i.e.,

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Let us assume that we apply F force downward at A angle q from the horizontal, at x distance from B

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced
⇒ Fnet x = 0 which gives
F2 = 8 N
From Fnet y = 0 ⇒ 5 + 6 = F+ 3
⇒ F1 = 8 N
If body is in equilibrium then torque about point B is zero,
⇒    3 x 5 + F1 x - 5 x 10 = 0
⇒    15 + 8x - 50 = 0
Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Ex.20 A uniform rod length l, mass m is hung from two strings of equal length from a ceiling as shown in figure. Determine the tensions in the strings ? 

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Sol. Let us assume that tension in left and right string is TA and TB respectively. Then

Rod is in equilibrium then  Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

From Equilibrium of a Rigid Body | Physics for JEE Main & Advanced
mg = TA + TB ...(1)
Equilibrium of a Rigid Body | Physics for JEE Main & Advanced
Equilibrium of a Rigid Body | Physics for JEE Main & Advanced

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Ladder Problems : 

Ex.21 A stationary uniform rod of mass `m', length `l' leans against a smooth vertical wall making an angle q with rough horizontal floor. Find the normal force & frictional force that is exerted by the floor on the rod? 

Equilibrium of a Rigid Body | Physics for JEE Main & Advanced 

Sol. As the rod is stationary so the linear acceleration and angular acceleration of rod is zero.

The document Equilibrium of a Rigid Body | Physics for JEE Main & Advanced is a part of the JEE Course Physics for JEE Main & Advanced.
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FAQs on Equilibrium of a Rigid Body - Physics for JEE Main & Advanced

1. What is the concept of equilibrium in a rigid body?
Ans. Equilibrium in a rigid body refers to a state where the body is at rest or moving with a constant velocity, with no net force or net torque acting on it. In other words, the forces and torques acting on the body are balanced, resulting in a stable condition.
2. How can we determine if a rigid body is in equilibrium?
Ans. To determine if a rigid body is in equilibrium, we need to check two conditions: the sum of all forces acting on the body should be zero, and the sum of all torques acting on the body should also be zero. If these conditions are satisfied, the body is in equilibrium.
3. What are the types of equilibrium in a rigid body?
Ans. There are three types of equilibrium in a rigid body: stable equilibrium, unstable equilibrium, and neutral equilibrium. In stable equilibrium, a body returns to its original position when slightly displaced. In unstable equilibrium, a body moves away from its original position when slightly displaced. In neutral equilibrium, a body remains in its new position when slightly displaced.
4. How can we calculate the sum of forces and torques in a rigid body?
Ans. To calculate the sum of forces in a rigid body, we add up all the individual forces acting on the body, taking into account their magnitudes and directions. To calculate the sum of torques, we consider the moment arm (perpendicular distance) of each force and the force's magnitude, and then sum up all the torques.
5. What are some examples of equilibrium in everyday life?
Ans. Equilibrium is present in many everyday situations. Some examples include a chair at rest on the ground, a book sitting on a table, or a ladder leaning against a wall without sliding or toppling over. These objects are in equilibrium because the forces and torques acting on them are balanced, resulting in a stable condition.
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