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# Ex 2.1 NCERT Solutions - Polynomials Class 10 Notes | EduRev

## Class 10 : Ex 2.1 NCERT Solutions - Polynomials Class 10 Notes | EduRev

The document Ex 2.1 NCERT Solutions - Polynomials Class 10 Notes | EduRev is a part of the Class 10 Course Mathematics (Maths) Class 10.
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Q.1. The graphs of y = p(x) are given in Fig. 2.10 below, for some polynomials p(x). Find the number of zeroes of p(x), in each case. Solutions:
Graphical method to find zeroes:
Total number of zeroes in any polynomial equation = total number of times the curve intersects x-axis.
(i) In the given graph, the number of zeroes of p(x) is 0 because the graph is parallel to x-axis does not cut it at any point.
(ii) In the given graph, the number of zeroes of p(x) is 1 because the graph intersects the x-axis at only one point.
(iii) In the given graph, the number of zeroes of p(x) is 3 because the graph intersects the x-axis at any three points.
(iv) In the given graph, the number of zeroes of p(x) is 2 because the graph intersects the x-axis at two points.
(v) In the given graph, the number of zeroes of p(x) is 4 because the graph intersects the x-axis at four points.
(vi) In the given graph, the number of zeroes of p(x) is 3 because the graph intersects the x-axis at three points.

Check out the NCERT Solutions of all the exercises of Polynomials:

Exercise 2.2 NCERT Solutions: Polynomials

Exercise 2.3 NCERT Solutions: Polynomials

Exercise 2.4 NCERT Solutions: Polynomials

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## Mathematics (Maths) Class 10

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