The document Ex 7.2 NCERT Solutions- Coordinate Geometry Class 10 Notes | EduRev is a part of the Class 10 Course Mathematics (Maths) Class 10.

All you need of Class 10 at this link: Class 10

**Q.1. Find the coordinates of the point which divides the join of (-1, 7) and (4, -3) in the ratio 2 : 3.****Sol.** Let P(x, y) be the point.

y = 3

Then, the coordinates of point are (1,3)**Q.2. Find the coordinates of the points of trisection of the line segment joining (4, -1) and (-2, -3).****Sol.** Let points P and Q trisect the line joining the points.

âˆ´ AP = PQ = QB

P divides AB in the ratio 1:2 and Q divides AB in the ratio 2:1**Q.3. To conduct Sports Day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1 m each. 100 flower pots have been placed at a distance of 1 m from each other along AD, as shown in the figure. Niharika runs 1/4 th the distance AD on the 2nd line and posts a green flag. Preet runs 1/5 th the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?****Sol. **

Coordinates of green flag are P(2, 25)

The coordinates of red flag are Q(8, 20)

The distance between two points is

Position of the blue flag = mid-point of PQ

âˆ´ The blue flag is in the 5th line, at a distance of 22.5 m.**Q.4. Find the ratio in which the line segment joining the points (-3, 10) and (6, -8) is divided by (-1, 6).****Sol.** Let the required ratio be k : 1

âˆ´ The required ratio is 2:7.**Q.5. Find the ratio in which the line segment joining A (1, -5) and B (-4, 5) is divided by the x-axis. Also find the coordinates of the point of division.****Sol.** Let P(x, 0) divide the line segment AB in the ratio k : 1

0 = 5k - 5 â‡’ 5k = 5 k = 1

Hence the required ratio is 1 : 1, at point **Q.6. If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.****Sol.**

Mid-point of AC = Mid-point of BD**Q.7. Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, -3) and B is (1, 4).****Sol.** Let the coordinates of A be (x, y). O (2, - 3) is the mid-point of AB

â‡’ x + 1 = 4, â‡’ y + 4 = -6

â‡’ x = 4 - 1, â‡’ y = -6 - 4

â‡’ x = 3, â‡’ y = -10

Hence, the coordinates of A are (3, -10).**Q.8. If A and B are (-2, -2) and (2, -4), respectively, find the coordinates of P such that **** and P lies on the line segment AB.****Sol.**

Hence, the coordinates of P are **Q.9. Find the coordinates of the points which divide the line segment joining A (-2, 2) and B (2, 8) into four equal parts.****Sol.** P, Q, R divide AB into four equal parts

Now, Q is the mid-point of AB.

P is the mid-point of AQ, then the coordinates of P are

R is the mid-point of QB, the coordinates of R are**Q.10. Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4) and (-2, -1) taken in order. [Hint: Area of a rhombus = 1/2 (product of its diagonals)]****Sol.** Let points be A (3,0), B(4, 5), C(-1, 4) and D(-2, -1)

Offer running on EduRev: __Apply code STAYHOME200__ to get INR 200 off on our premium plan EduRev Infinity!

178 videos|268 docs|103 tests

### Distance Formula

- Video | 09:39 min
### Example: Sectional Formula

- Video | 12:32 min
### Test: Distance Formula

- Test | 20 ques | 20 min
### Sectional Formula

- Video | 14:06 min

- Ex 7.1 NCERT Solutions - Coordinate Geometry
- Doc | 2 pages
- NCERT Exemplar - Coordinate Geometry
- Doc | 2 pages