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Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10 PDF Download

1. Cube


For a Cube of  side a   we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = (a3) cu. units.
(ii) Lateral surface area = [4a2] sq. units.
(iii) Total surface area = [6a2] sq. units.

2. Cuboid

 For a Cuboid of length = l, breadth = b and height = h, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = (l × b × h) cu. units.
(ii) Lateral surface area = [2 (l + b) × h] sq. units.
(iii) Total surface area = [2 (lb + bh + hl] sq. units.

3. Cylinder


For a Cylinder of base radius = r and height (or length) = h, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = πr2h cu. units.
(ii) Curved surface area = 2πrh sq. units.
(iii) Total surface area = 2πr (h + r) sq. units.

4. Hollow Cylinder


For a Hollow Cylinder having external radius = R, internal radius = r and height = h, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume= [External volume] − [Internal volume]
=(πR2h − πr2h) cu. units = π(R2 − r2) cu. units.
(ii) Curved surface area= [External S.A.] + [Internal S.A.]
=[2πRh + 2πrh] sq. units = 2πh (R + r) sq. units
(iii) Total surface area= (curved S.A.) + (area of the base-ring)
= [(2πRh + 2πrh) + 2 (πR2 − πr2)] sq. units
= [(2πh (R + r) + 2π (R2 − r2)] sq. units

5. Cone


For a Cone of base radius = r, height = h and slant height l =√h2+r2we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 1/3 πr2h cu. units.
(ii) Curved surface area = πrl sq. units.
(iii) Total surface area = [Curved surface area] + [Area of base]
= [πrl + πr2] sq. units = πr (l + r) sq. units.

6. Sphere


For a Sphere of radius r, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 4/3 πr3 cu. units.
(ii) Curved surface area = 4πr2 sq. units.
(iii) Total surface area =4πr2sq. units.     

7. Hemisphere


For a Hemisphere of radius r, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 2/3 πr3 cu. units.
(ii) Surface area = 2πr2 sq. units.
(iii) Total surface area = 3πr2 sq. units.

The document Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10 is a part of the Class 10 Course Mathematics (Maths) Class 10.
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FAQs on Facts that Matter: Surface Areas & Volumes - Mathematics (Maths) Class 10

1. What is the formula for finding the surface area of a rectangular prism?
Ans. The formula for finding the surface area of a rectangular prism is given by: 2(lw + lh + wh), where l is the length, w is the width, and h is the height of the prism.
2. How do you calculate the volume of a cone?
Ans. The volume of a cone can be calculated using the formula: (1/3) πr²h, where r is the radius of the base and h is the height of the cone.
3. What is the formula for finding the surface area of a sphere?
Ans. The formula for finding the surface area of a sphere is given by: 4πr², where r is the radius of the sphere.
4. How can I find the volume of a cylinder?
Ans. The volume of a cylinder can be calculated using the formula: πr²h, where r is the radius of the base and h is the height of the cylinder.
5. How do I calculate the surface area of a pyramid?
Ans. The surface area of a pyramid can be calculated by adding the area of the base to the sum of the areas of the triangular faces. The formula can vary depending on the type of pyramid, such as a square pyramid or a triangular pyramid.
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