Q.1. ; 10 If B =A-1 then value of α is
Ans. 5
B = A-1;
AB = I
10I = 10AB =
=
∴ α = 5
Q.2. If then is divisible by
Ans. 2008
=
∴ = 2(2009)2(2010)
which is divisible by 2008.
Q.3. If p, q, r are in A.P., then the determinant
Ans. 0
Applying R1 ⇒ R1- R3 and 2q = p + r
=
=
= 0
Q.4. For a 3 ´ 3 matrix A, if det A = 4, then det (Adj A) equals
Ans. 16
Since A Adj A = | A | I
=
∴ det (A Adj A)
=
∴ |A| |Adj A| = |A|3
∴ |Adj A| = |A|2 = (4)2 = 16
Q.5. If x > m, y > n, z > r (x, y, z > 0) such that then find the greatest value of .
Ans. 8
⇒
Now AM ≥ GM
⇒
Q.6. If the system of equations x + ay = 0, az + y = 0, ax + z= 0 has infinite solutions then | a|=
Ans. 1
x = -ay;
ax + z =0 ⇒ -a2y + z = 0
az + y =0 ⇒ a3y+ y =0
∴ a = -1 ; | a |= 1
Q.7. The value of l for which the system of equations 2x - y + 2z = 2, x - 2y + z = -4, x + y + lz = 4 has no solution is
Ans. 1
2x - y + 2z = 2; y = 2(x + z -1)
x - 2y + z = -4 ⇒ x + z + 4 = 4(x + z) - 4
3( x +z )= 8
x + y + λz = 4
x + λz = 2/3
(1 - λ) z = 2
∴ λ = 1
Q.8. Find c2 + x2 + y2 if the matrix A given by is orthogonal.
Ans. 1
It is given that the matrix A is orthogonal. Therefore,
Comparing the element in the 3rd column of 3rd row, we get c2 + x2 + y2 = 1.
Q.9. ; f (100) = ?
Ans. 0
Take x from R2 ,R3
x - 1 from R3
x + 1 from C3
f (100) = 0
Q.10. The number of value of t for which the system of equations
(a – t)x + by + cz = 0
bx + (c – t)y + az = 0
and cx + ay + (b – t) z = 0 has non trivial solution
Ans. 3
System of equation have a non-trivial solution if Δ = 0
∴ Δ = p0t3 + p1t2 + p2t + p3, p0, p1, p2, p3 ∈ R.
Hence Δ is cubic polynomial in t.
Hence number of values of t is 3.
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