JEE Advanced (Single Correct Type): Compounds Containing Nitrogen | Chapter-wise Tests for JEE Main & Advanced PDF Download

Q.1. What is the most basic aromatic amine’s common name?
(a) Benzenamine
(b) Benzylamine
(c) Aniline
(d) Aminobenzene

Correct Answer is option (c)
The simplest amine is aniline, which has the formula C6H5NH2. This name is also recognised by the IUPAC. The IUPAC designation for it is benzenamine, although it’s also known as aminobenzene.

Q.2. What is the correct name for a molecule that has two amino groups in opposing (para) locations around a benzene ring?
(a) Benzenediamine
(b) Benzene-1,4-diamine
(c) p-Aminoaniline
(d) 4-Aminobenzenamine

Correct Answer is option (b)
Both amino groups (in para positions to one other) are given equal weight and the primary complex is given the prefix di. The prefix is also numbered 1 and 4, indicating the places in the benzene ring where amino groups are present.

Q.3. When acetamide is converted to methylamine, what is the name of the reaction?
(a) Friedel-Craft’s reaction
(b) Hofmann reaction
(c) Hoffmann bromamide degradation reaction
(d) Hinsberg reaction

Correct Answer is option (c)
When bromine is added to an amide in an aqueous or ethanolic sodium hydroxide solution, the amide degrades, resulting in the creation of primary amine. Hoffmann bromamide degradation reaction is a reaction that involves the degradation of an amide.

Q.4. For which of the following is the Hinsberg approach used?
(a) Preparation of primary amines
(b) Separation of amine mixtures
(c) Preparation of tertiary amines
(d) Preparation of secondary amines

Correct Answer is option (b)
The Hinsberg reaction is a test for primary, secondary, and tertiary amine detection. The amine is thoroughly shaken with Hinsberg reagent in the presence of aqueous alkali in this test (either KOH or NaOH). A substrate is treated with a reagent containing an aqueous sodium hydroxide solution and benzenesulfonyl chloride.

Q.5. Which of the following is the IUPAC name of the chemical in which an ethyl group replaces one hydrogen of ammonia?
(a) Ethanamine
(b) Aminoethane
(c) Ethylamine
(d) Ethane amine

Correct Answer is option (a)
According to the common system and the second system, CH₃CH₂NH₂ is known as ethylamine and aminoethane, respectively. In the IUPAC system, the amine is substituted for the ‘e’ of the alkane.

Q.6. The aromatic primary amine with the formula C₇H₉N has an incorrect name.
(a) Phenylaminomethane
(b) Benzylamine
(c) Benzenamine
(d) Phenylmethanamine

Correct Answer is option (c)
The phenyl group C₆H₅ must be present with CH₄N because it is an aromatic molecule. Because it’s a primary amine, the NH₂ group can be separated, leaving CH₂. The compound’s formula is C₆H₅CH₂NH₂, which stands for benzylamine. C₆H₅NH₂ is the formula for benzenamine.

Q.7. Which test can tell the difference between p-chloroaniline and anilinium hydrochloride?
a) Sandmeyer reaction
b) Carbylamine test
c) AgNO₃
d) NaHCO₃

Correct Answer is option (d)
An acid salt, anilinium hydrochloride, liberates CO₂ from NaHCO₃. However, because p-chloro aniline is basic rather than acidic, it does not release CO₂. Because p-chloro aniline lacks ionic chlorine, it does not produce white precipitate when combined with AgNO₃.

Q.8. By reacting with which of the following, primary amines can be separated from secondary and tertiary amines?
(a) Chloroform alone
(b) Methyl iodide
(c) Chloroform and alcoholic KOH
(d) Zinc dust

Correct Answer is option (c)
Secondary and tertiary amines do not react with CHCl₃ and alc. KOH generates isocyanide, whereas primary amine does.

Q.9. Which of the following statements concerning methylamine is correct?
(a) Methylamine is stronger base than NH₃ 
(b) Methylamine is less basic than NH₃
(c) Methylamine is slightly acidic
(d) Methylamine forms salts with alkali

Correct Answer is option (a)
Due to the +I effect, the presence of an alkyl group enhances the electron density of the nitrogen atom. As a result, basic nature grows.

Q.10. Which of these substances has a lower melting point than amine?
(a) Alcohol
(b) Ether
(c) Carboxylic acid
(d) Phosphine

Correct Answer is option (d)
The characteristics of primary and secondary amines are influenced by hydrogen bonding. As a result, amines have greater melting and boiling points than the comparable phosphines but are often lower than the corresponding alcohols and carboxylic acids, ether.

Q.11. In the above process product A is

(a) Fluorobenzene
(b) Benzene
(c) 1,4-difluorobenzene
(d) 1,3-difluorobenzene

Correct Answer is option (a)
This is Baltz Schiemann reaction.  

Q.12. Treatment of NH₃ with excess of ethyl chloride gives:  
(a) Diethylamine
(b) Ethane
(c) Tetraethylammonium chloride  
(d) Methylamine

Correct Answer is option (c)

Q.13. Reduction of nitrobenzene in the presence of Zn/NH₄Cl gives
(a) hydrazobenzene
(b) aniline
(c) azobenzene
(d) N-phenyl hydroxyl amine

Correct Answer is option (d) 

Q.14. Which among the following amines will give carbylamine reaction?
(a) CH₃–CH₂–NH₂
(b) CH₃–NH–CH₃
(c) (C₆H5)₃N
(d) CH₃–CH₂–NH–OH

Correct Answer is option (a)
Carbylamine test is responded by only 1° aliphatic/aromatic amines.

Q.15. The base with lowest pK_a value is
(a) NC-CH₂NH₂ 
(b) Et₃N
(c) NH₃ 
(d) HO-CH₂CH₂NH₂

Correct Answer is option (c)
Low value of pK_a means stronger acid or weaker base. Thus as basicity decreases pK_a value decreases. Due to presence of strong electron withdrawing (-I effect), NCCH₂NH₂ is the weakest base as it has the lowest electron density on N-atom. Hence, NCCH₂CH₂ has the lowest pK_a value.