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JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced PDF Download

27. How many grams of silver could be plated out on a serving tray by electrolysis of a solution containing silver in +1 oxidation state for a period of 8.0 hours at a current of 8.46 amperes? What is the area of the tray if the thickness of the silver plating is 0.00254 cm? Density of silver is 10.5 g/cm3.
  (1997 - 3 Marks)

Ans:  34.02 g, 1275.6 cm2

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced


28. Calculate the equilibrium constant for the reaction

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 Ans:  7.6 × 1012

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

29. Calculate the equilibrium constant for the reaction,  JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced The standard reduction potentials in acidic conditions are 0.77 V and 0.54 V respectively for  JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced  couples. (1998 - 3 Marks)

Ans:  6.26 × 107

Solution :

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

30. Find the solubility product of a saturated solution of Ag2CrO4 in water at 298 K if the emf of the cell Ag | Ag+ (satd. Ag2CrO4soln.)||Ag+(0.1M)|Ag is 0.164 V at 298 K.                          (1998 - 6 Marks)

Ans:  2.44 × 10–12

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

31. A cell, Ag | Ag+||Cu2+|Cu, initiallly contains 1 M Ag+ and 1 M Cu2+ ions. Calculate the change in the cell potential after the passage of 9.65 A of current for 1 h. (1999 - 6 Marks)

Ans: 0.010 V

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
After the passage of 9.65 ampere for 1 hr i.e. 9.65 x 60 x 60 Coulomb charge,during which the cell reactions are reversed, the Ag metal passes in solution state and Cu2+ ions are discharged. The reactions during the passage of current are:

 JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced


32. Copper sulphate solution (250 mL) was electrolysed using a platinum anode and a copper cathode. A constant current of 2 mA was passed for 16 minutes. It was found that after electrolysis the absorbance of the solution was reduced to 50% of its original value. Calculate the concentration of copper sulphate in the solution to begin with.            (2000 - 3 Marks)

 Ans:  7.95 × 10–5 mol L–1

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

33. The following electrochemical cell has been set up.  JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced   If an ammeter is connected between the two platinum electrodes, predict the direction of flow of current. Will the current increase or decrease with time? (2000 - 2 Marks)

Ans:  Ce electrode to iron electrode, decrease

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

34. The standard potential of the following cell is 0.23 V at 15°C and 0.21 V at 35°C.                       ( 2001 - 10 Marks)
  Pt | H2 (g) | HCl(aq) | AgCl(s) | Ag(s)

(i) Write the cell reaction.
(ii) Calculate DH° and DS° for the cell reaction by assuming that these quantities remain unchanged in the range 15°C to 35°C.
(iii) Calculate the solubility of AgCl in water at 25°C.
Given : The standard reduction potential of the Ag+(aq) /Ag(s) couple is 0.80 V at 25°C.

Ans:  (ii) – 22195 J mole, –49987 J/mole; (iii) 1.24 × 10–5 mol/L

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

35. Two students use same stock solution of ZnSO4 and a solution of CuSO4. The emf of one cell is 0.03 V higher than the other. The conc. of CuSO4 in the cell with higher emf value is 0.5 M. Find out the conc. of CuSO4 in the other cell (2.203 RT/F = 0.06). (2003 - 2 Marks)

Ans: 0.05 M

Solution :
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

36. Find the equilibrium constant for the reaction,
 In2+ +   Cu2+     →    In3+ +Cu+  at  298 K
 given :

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced                 (2004 - 4 Marks)

Ans: 1010

Solution : 
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

37. (a) For the reaction

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

Given :

SpeciesJEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
Ag+ (aq)+77
Cl- (aq)-129
AgCl (s)-109

Write the cell representation of above reaction and calculate JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advancedat 298 K. Also find the solubility product of AgCl.

(b) If 6.539 × 10–2 g of metallic zinc is added to 100 ml saturated solution of AgCl. Find the value of JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced  How many moles of Ag will be precipitated in the above
 reaction. Given that
 Ag+ + e- →   Ag ; Eº = 0.80V ;
 Zn2+ + 2e- → Zn ; Eº = -0.76V               (2005 - 6 Marks)
 (It was given that Atomic mass of Zn = 65.39)

Ans:  (a) 0.59 V, 10–10 (b) 52.9, 10–6

Solution : 
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

 

NOTE: As the value of equilbrium constant is very high so the reaction moves in forward direction completely.
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

38. We have taken a saturated solution of AgBr. Ksp of AgBr is 12 × 10–14. If 10–7 mole of AgNO3 are added to 1 litre of this solution find conductivity (specific conductance) of this solution in terms of 10–7 S m–1 units. Given, Molar conductance of Ag+, Br and NO3– are 6×10–3 Sm2mol–1, 8×10–3 Sm2mol–1 and 7×10–3 Sm2mol–1.

Ans: 55

Solution : 

JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced
JEE Advanced (Subjective Type Questions): Electrochemistry- 3 | Chapter-wise Tests for JEE Main & Advanced

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