JEE Main 2020 Chemistry September 6 Shift 2 Paper & Solutions | Mock Tests for JEE Main and Advanced 2025 PDF Download

 Page 1


JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 1
Date : 6
th
 September 2020
Time : 02 : 00 pm - 05 : 00 pm
Subject : Chemistry
1. Match the following :
Test/Method Reagent
(i) Lucas Test (a) C
6
H
5
SO
2
Cl/aq. KOH
(ii) Dumas method (b) HNO
3
/AgNO
3
(iii) Kjeldahl's method (c) CuO/CO
2
(iv) Hinsberg Test (d) Conc. HCl and ZnCl
2
(e) H
2
SO
4
(1) (i)-(d),(ii)-(c),(iii)-(e),(iv)-(a) (2) (i)-(b),(ii)-(a),(iii)-(c),(iv)-(d)
(3) (i)-(b),(ii)-(d),(iii)-(e),(iv)-(a) (4) (i)-(d),(ii)-(c),(iii)-(b)-(iv)-(e)
Sol. 1
By Theory
2. The IUPAC name of the following compound is:
OH
NH
2
O N
2
CHO
(1) 2-nitro-4-hydroxymethyl-5-amino benzaldehyde
(2) 3-amino-4-hydroxymethyl-5-nitro benzaldehyde
(3) 4-amino-2-formyl-5-hydroxymehtyl nitrobenzene
(4) 5-amino-4-hydroxymethyl-2-nitro benzaldehyde
Sol. 4
3. For the Given Cell;
? ? ? ? ? ? ? ?
2+ 2+
1 2
Cu s |Cu C M ||Cu C M |Cu s
Change in Gibbs energy ? ? ? G is negative, if :
(1) 
2 1
2 C C ? (2) 
1
2
2
C
C ?
(3) C
1
 = 2C
2
(4) C
1
 = C
2
Sol. 1
E = 0 – 
1
2
C 0.059
log
2 C
? ?
? ?
? ?
?G = – nFE
     = + nF × 
RT
nF
 × 2.303 Log 
1
2
C
C
? ?
? ?
? ?
log
1
2
C
C
? ?
? ?
? ?
 < 0
C
1
 < C
2
C
2
 = 
1
2C
Page 2


JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 1
Date : 6
th
 September 2020
Time : 02 : 00 pm - 05 : 00 pm
Subject : Chemistry
1. Match the following :
Test/Method Reagent
(i) Lucas Test (a) C
6
H
5
SO
2
Cl/aq. KOH
(ii) Dumas method (b) HNO
3
/AgNO
3
(iii) Kjeldahl's method (c) CuO/CO
2
(iv) Hinsberg Test (d) Conc. HCl and ZnCl
2
(e) H
2
SO
4
(1) (i)-(d),(ii)-(c),(iii)-(e),(iv)-(a) (2) (i)-(b),(ii)-(a),(iii)-(c),(iv)-(d)
(3) (i)-(b),(ii)-(d),(iii)-(e),(iv)-(a) (4) (i)-(d),(ii)-(c),(iii)-(b)-(iv)-(e)
Sol. 1
By Theory
2. The IUPAC name of the following compound is:
OH
NH
2
O N
2
CHO
(1) 2-nitro-4-hydroxymethyl-5-amino benzaldehyde
(2) 3-amino-4-hydroxymethyl-5-nitro benzaldehyde
(3) 4-amino-2-formyl-5-hydroxymehtyl nitrobenzene
(4) 5-amino-4-hydroxymethyl-2-nitro benzaldehyde
Sol. 4
3. For the Given Cell;
? ? ? ? ? ? ? ?
2+ 2+
1 2
Cu s |Cu C M ||Cu C M |Cu s
Change in Gibbs energy ? ? ? G is negative, if :
(1) 
2 1
2 C C ? (2) 
1
2
2
C
C ?
(3) C
1
 = 2C
2
(4) C
1
 = C
2
Sol. 1
E = 0 – 
1
2
C 0.059
log
2 C
? ?
? ?
? ?
?G = – nFE
     = + nF × 
RT
nF
 × 2.303 Log 
1
2
C
C
? ?
? ?
? ?
log
1
2
C
C
? ?
? ?
? ?
 < 0
C
1
 < C
2
C
2
 = 
1
2C
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 2
4. Reaction of an inorganic sulphite X with dilute H
2
SO
4
 generates compound Y. Reaction
of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound
Z. Y and Z, repectively, are :
(1) SO
2
 and NaHSO
3
(2) S and Na
2
SO
3
(3) SO
2 
and Na
2
SO
3
(4) SO
3
 and NaHSO
3
Sol. 1
Na SO +dilute H SO  Na SO + H SO
2 3 2 4         2 4 2 3
H O + SO 
2 2
(Y)
NaOH
Na SO
2 3
SO + H O
2 2
NaHSO
3
(Z)
(x)
Ans. (1) Y = SO
2
Z = NaHSO
3
5. The value of K
C
 is 64 at 800 K for the reaction N
2
(g) + 3H
2
(g)  2NH
3
(g)
The value of K
C 
for the following reaction is :
NH
3
(g) ? ? ? ?
2 2
1 3
N g + H g
2 2
(1) 1/4 (2) 8 (3) 1/8 (4) 1/64
Sol. 3
K
C
 = 
1/2
(64)
?
K
C
 = 
1
8
6. The correct match between Item - I (Starting material) and Item - II (reagent) for the
preparation of benzaldehyde is :
Item - I Item - II
(I) Benzene (P) HCl and SnCl
2
.H
3
O
+
(II) Benzonitrile (Q) H
2
, Pd- BaSO
4
, and quinoline
(III) Benzoyl Chloride (R) CO, HCl and AlCl
3
(1) (I) - (R), (II) - (P) and (III) - (Q)
(2) (I) - (P), (II) - (Q) and (III) - (R)
(3) (I) - (Q), (II) - (R) and (III) - (P)
(4) (I) - (R), (II) - (Q) and (III) - (P)
Page 3


JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 1
Date : 6
th
 September 2020
Time : 02 : 00 pm - 05 : 00 pm
Subject : Chemistry
1. Match the following :
Test/Method Reagent
(i) Lucas Test (a) C
6
H
5
SO
2
Cl/aq. KOH
(ii) Dumas method (b) HNO
3
/AgNO
3
(iii) Kjeldahl's method (c) CuO/CO
2
(iv) Hinsberg Test (d) Conc. HCl and ZnCl
2
(e) H
2
SO
4
(1) (i)-(d),(ii)-(c),(iii)-(e),(iv)-(a) (2) (i)-(b),(ii)-(a),(iii)-(c),(iv)-(d)
(3) (i)-(b),(ii)-(d),(iii)-(e),(iv)-(a) (4) (i)-(d),(ii)-(c),(iii)-(b)-(iv)-(e)
Sol. 1
By Theory
2. The IUPAC name of the following compound is:
OH
NH
2
O N
2
CHO
(1) 2-nitro-4-hydroxymethyl-5-amino benzaldehyde
(2) 3-amino-4-hydroxymethyl-5-nitro benzaldehyde
(3) 4-amino-2-formyl-5-hydroxymehtyl nitrobenzene
(4) 5-amino-4-hydroxymethyl-2-nitro benzaldehyde
Sol. 4
3. For the Given Cell;
? ? ? ? ? ? ? ?
2+ 2+
1 2
Cu s |Cu C M ||Cu C M |Cu s
Change in Gibbs energy ? ? ? G is negative, if :
(1) 
2 1
2 C C ? (2) 
1
2
2
C
C ?
(3) C
1
 = 2C
2
(4) C
1
 = C
2
Sol. 1
E = 0 – 
1
2
C 0.059
log
2 C
? ?
? ?
? ?
?G = – nFE
     = + nF × 
RT
nF
 × 2.303 Log 
1
2
C
C
? ?
? ?
? ?
log
1
2
C
C
? ?
? ?
? ?
 < 0
C
1
 < C
2
C
2
 = 
1
2C
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 2
4. Reaction of an inorganic sulphite X with dilute H
2
SO
4
 generates compound Y. Reaction
of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound
Z. Y and Z, repectively, are :
(1) SO
2
 and NaHSO
3
(2) S and Na
2
SO
3
(3) SO
2 
and Na
2
SO
3
(4) SO
3
 and NaHSO
3
Sol. 1
Na SO +dilute H SO  Na SO + H SO
2 3 2 4         2 4 2 3
H O + SO 
2 2
(Y)
NaOH
Na SO
2 3
SO + H O
2 2
NaHSO
3
(Z)
(x)
Ans. (1) Y = SO
2
Z = NaHSO
3
5. The value of K
C
 is 64 at 800 K for the reaction N
2
(g) + 3H
2
(g)  2NH
3
(g)
The value of K
C 
for the following reaction is :
NH
3
(g) ? ? ? ?
2 2
1 3
N g + H g
2 2
(1) 1/4 (2) 8 (3) 1/8 (4) 1/64
Sol. 3
K
C
 = 
1/2
(64)
?
K
C
 = 
1
8
6. The correct match between Item - I (Starting material) and Item - II (reagent) for the
preparation of benzaldehyde is :
Item - I Item - II
(I) Benzene (P) HCl and SnCl
2
.H
3
O
+
(II) Benzonitrile (Q) H
2
, Pd- BaSO
4
, and quinoline
(III) Benzoyl Chloride (R) CO, HCl and AlCl
3
(1) (I) - (R), (II) - (P) and (III) - (Q)
(2) (I) - (P), (II) - (Q) and (III) - (R)
(3) (I) - (Q), (II) - (R) and (III) - (P)
(4) (I) - (R), (II) - (Q) and (III) - (P)
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 3
Sol. 1
+ CO + HCl
AlCl
3
CH=O
(Gattermann - koch aldehyde synthesis)
SnCl + HCl
2
CH=O
(stephen's reaction)
H O
3
+
H /Pd-BaSO
2 4
CH=O
(Rosenmund reduction)
C
O
Cl
CN
7. For a d
4
 metal ion in an octahedral field, the correct electronic configuration is :
(1) 
2 2
g 2g o
e t when  < P ? (2) 
4 o
2 g o
e when  < P
g
t ?
(3) 
3 1
2g o
e when  > P
g
t ? (4) 
3 1
2g o
e when  < P
g
t ?
Sol. 4
d
4
 ? 
3 1
2g g
t e – ?
0
 < P
8. The correct match between Item - I and Item - II is :
Item - I Item - II
(a) Natural rubber (I) 1,3-butadiene + styrene
(b) Neoprene (II) 1,3-butadiene + acrylonitrile
(c) Buna-N (III) Chloroprene
(d) Buna-S (IV) Isoprene
(1) (a) - (III), (b) - (IV), (c) - (I), (d) - (II)
(2) (a) - (IV), (b) - (III), (c) - (II), (d) - (I)
(3) (a) - (IV), (b) - (III), (c) - (I), (d) - (II)
(4) (a) - (III), (b) - (IV), (c) - (II), (d) - (I)
Sol. 2
By Theory
9. Which one of the following statement is not true ?
(1) Lactose contains a -glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
(2) Lactose is a reducing sugar and it gives Fehling's test.
(3) On acid hydrolysis, lactose gives one molecule of D(+)-glucose and one molecule of
D(+)-galactose.
(4) Lactose(C
11
H
22
O
11
) is a disaccharide and it contains 8 hydroxyl groups.
Sol. 1
Lactose contains ?-glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
Page 4


JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 1
Date : 6
th
 September 2020
Time : 02 : 00 pm - 05 : 00 pm
Subject : Chemistry
1. Match the following :
Test/Method Reagent
(i) Lucas Test (a) C
6
H
5
SO
2
Cl/aq. KOH
(ii) Dumas method (b) HNO
3
/AgNO
3
(iii) Kjeldahl's method (c) CuO/CO
2
(iv) Hinsberg Test (d) Conc. HCl and ZnCl
2
(e) H
2
SO
4
(1) (i)-(d),(ii)-(c),(iii)-(e),(iv)-(a) (2) (i)-(b),(ii)-(a),(iii)-(c),(iv)-(d)
(3) (i)-(b),(ii)-(d),(iii)-(e),(iv)-(a) (4) (i)-(d),(ii)-(c),(iii)-(b)-(iv)-(e)
Sol. 1
By Theory
2. The IUPAC name of the following compound is:
OH
NH
2
O N
2
CHO
(1) 2-nitro-4-hydroxymethyl-5-amino benzaldehyde
(2) 3-amino-4-hydroxymethyl-5-nitro benzaldehyde
(3) 4-amino-2-formyl-5-hydroxymehtyl nitrobenzene
(4) 5-amino-4-hydroxymethyl-2-nitro benzaldehyde
Sol. 4
3. For the Given Cell;
? ? ? ? ? ? ? ?
2+ 2+
1 2
Cu s |Cu C M ||Cu C M |Cu s
Change in Gibbs energy ? ? ? G is negative, if :
(1) 
2 1
2 C C ? (2) 
1
2
2
C
C ?
(3) C
1
 = 2C
2
(4) C
1
 = C
2
Sol. 1
E = 0 – 
1
2
C 0.059
log
2 C
? ?
? ?
? ?
?G = – nFE
     = + nF × 
RT
nF
 × 2.303 Log 
1
2
C
C
? ?
? ?
? ?
log
1
2
C
C
? ?
? ?
? ?
 < 0
C
1
 < C
2
C
2
 = 
1
2C
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 2
4. Reaction of an inorganic sulphite X with dilute H
2
SO
4
 generates compound Y. Reaction
of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound
Z. Y and Z, repectively, are :
(1) SO
2
 and NaHSO
3
(2) S and Na
2
SO
3
(3) SO
2 
and Na
2
SO
3
(4) SO
3
 and NaHSO
3
Sol. 1
Na SO +dilute H SO  Na SO + H SO
2 3 2 4         2 4 2 3
H O + SO 
2 2
(Y)
NaOH
Na SO
2 3
SO + H O
2 2
NaHSO
3
(Z)
(x)
Ans. (1) Y = SO
2
Z = NaHSO
3
5. The value of K
C
 is 64 at 800 K for the reaction N
2
(g) + 3H
2
(g)  2NH
3
(g)
The value of K
C 
for the following reaction is :
NH
3
(g) ? ? ? ?
2 2
1 3
N g + H g
2 2
(1) 1/4 (2) 8 (3) 1/8 (4) 1/64
Sol. 3
K
C
 = 
1/2
(64)
?
K
C
 = 
1
8
6. The correct match between Item - I (Starting material) and Item - II (reagent) for the
preparation of benzaldehyde is :
Item - I Item - II
(I) Benzene (P) HCl and SnCl
2
.H
3
O
+
(II) Benzonitrile (Q) H
2
, Pd- BaSO
4
, and quinoline
(III) Benzoyl Chloride (R) CO, HCl and AlCl
3
(1) (I) - (R), (II) - (P) and (III) - (Q)
(2) (I) - (P), (II) - (Q) and (III) - (R)
(3) (I) - (Q), (II) - (R) and (III) - (P)
(4) (I) - (R), (II) - (Q) and (III) - (P)
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 3
Sol. 1
+ CO + HCl
AlCl
3
CH=O
(Gattermann - koch aldehyde synthesis)
SnCl + HCl
2
CH=O
(stephen's reaction)
H O
3
+
H /Pd-BaSO
2 4
CH=O
(Rosenmund reduction)
C
O
Cl
CN
7. For a d
4
 metal ion in an octahedral field, the correct electronic configuration is :
(1) 
2 2
g 2g o
e t when  < P ? (2) 
4 o
2 g o
e when  < P
g
t ?
(3) 
3 1
2g o
e when  > P
g
t ? (4) 
3 1
2g o
e when  < P
g
t ?
Sol. 4
d
4
 ? 
3 1
2g g
t e – ?
0
 < P
8. The correct match between Item - I and Item - II is :
Item - I Item - II
(a) Natural rubber (I) 1,3-butadiene + styrene
(b) Neoprene (II) 1,3-butadiene + acrylonitrile
(c) Buna-N (III) Chloroprene
(d) Buna-S (IV) Isoprene
(1) (a) - (III), (b) - (IV), (c) - (I), (d) - (II)
(2) (a) - (IV), (b) - (III), (c) - (II), (d) - (I)
(3) (a) - (IV), (b) - (III), (c) - (I), (d) - (II)
(4) (a) - (III), (b) - (IV), (c) - (II), (d) - (I)
Sol. 2
By Theory
9. Which one of the following statement is not true ?
(1) Lactose contains a -glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
(2) Lactose is a reducing sugar and it gives Fehling's test.
(3) On acid hydrolysis, lactose gives one molecule of D(+)-glucose and one molecule of
D(+)-galactose.
(4) Lactose(C
11
H
22
O
11
) is a disaccharide and it contains 8 hydroxyl groups.
Sol. 1
Lactose contains ?-glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 4
O
CH –OH
2
OH
OH
OH
O
O
CH –OH
2
OH
OH
OH
Structure of Lactose
10. The element that can be refined by distillation is :
(1) tin (2) gallium
(3) zinc (4) nickel
Sol. 3
Zinc ? Refined by distillation
11. Match the following compounds (Column-I) with their uses (Column-II) :
S. No. Column – I S. No. Column – II
(I) Ca(OH)
2
(A) Casts of statues
(II) NaCl (B) White wash
(III)
4 2
1
CaSO . H O
2
(C) Antacid
(IV) CaCO
3
(D) Washing soda preparation
(1) (I)-(B),(II)-(C),(III)-(D),(IV)-(A) (2) (I)-(C),(II)-(D),(III)-(B),(IV)-(A)
(3) (I)-(B),(II)-(D),(III)-(A),(IV)-(C) (4) (I)-(D),(II)-(A),(III)-(C),(IV)-(B)
Sol. 3
(i) Ca(OH)
2
 ? used in white wash due to its disinfectant nature
(ii) CaCO
3
? it used as an Antacid
(iii) CaSO
4
 .
1
2
H
2
O ? Formaking casts of statues and busts
(iii) Preparation of wasing soda (sodium carbonate)
(1) 2NH
3
 + H
2
O + CO
2
 
? ? ? ?
(NH
4
)
2
CO
3
(2) (NH
4
)
2
CO
3
 + H
2
O + CO
2
 
? ? ? ?
2NH
4
HCO
3
(3) NH
4
HCO
3
 + NaCl 
? ? ? ?
NH
4
Cl + NaHCO
3
(4) 2NaHCO
3
 
? ? ? ?
Na
2
CO
3
 + CO
2
 + H
2
O
Ans. (3)
12. Mischmetal is an alloy consisting mainly of :
(1) lanthanoid and actinoid metals (2) lanthanoid metals
(3) actinoid metals (4) actinoid and transition metals
Sol. 2
Misch metal - well known alloy is mischmetal which consists of Lanthanoid metal
(~ 95%) and iron (~ 5%) and Traces of S, C, Ca and Al
Page 5


JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 1
Date : 6
th
 September 2020
Time : 02 : 00 pm - 05 : 00 pm
Subject : Chemistry
1. Match the following :
Test/Method Reagent
(i) Lucas Test (a) C
6
H
5
SO
2
Cl/aq. KOH
(ii) Dumas method (b) HNO
3
/AgNO
3
(iii) Kjeldahl's method (c) CuO/CO
2
(iv) Hinsberg Test (d) Conc. HCl and ZnCl
2
(e) H
2
SO
4
(1) (i)-(d),(ii)-(c),(iii)-(e),(iv)-(a) (2) (i)-(b),(ii)-(a),(iii)-(c),(iv)-(d)
(3) (i)-(b),(ii)-(d),(iii)-(e),(iv)-(a) (4) (i)-(d),(ii)-(c),(iii)-(b)-(iv)-(e)
Sol. 1
By Theory
2. The IUPAC name of the following compound is:
OH
NH
2
O N
2
CHO
(1) 2-nitro-4-hydroxymethyl-5-amino benzaldehyde
(2) 3-amino-4-hydroxymethyl-5-nitro benzaldehyde
(3) 4-amino-2-formyl-5-hydroxymehtyl nitrobenzene
(4) 5-amino-4-hydroxymethyl-2-nitro benzaldehyde
Sol. 4
3. For the Given Cell;
? ? ? ? ? ? ? ?
2+ 2+
1 2
Cu s |Cu C M ||Cu C M |Cu s
Change in Gibbs energy ? ? ? G is negative, if :
(1) 
2 1
2 C C ? (2) 
1
2
2
C
C ?
(3) C
1
 = 2C
2
(4) C
1
 = C
2
Sol. 1
E = 0 – 
1
2
C 0.059
log
2 C
? ?
? ?
? ?
?G = – nFE
     = + nF × 
RT
nF
 × 2.303 Log 
1
2
C
C
? ?
? ?
? ?
log
1
2
C
C
? ?
? ?
? ?
 < 0
C
1
 < C
2
C
2
 = 
1
2C
JEE Main 2020 Paper
         6
th
 September 2020 | (Shift-2), Chemistry     Page | 2
4. Reaction of an inorganic sulphite X with dilute H
2
SO
4
 generates compound Y. Reaction
of Y with NaOH gives X. Further, the reaction of X with Y and water affords compound
Z. Y and Z, repectively, are :
(1) SO
2
 and NaHSO
3
(2) S and Na
2
SO
3
(3) SO
2 
and Na
2
SO
3
(4) SO
3
 and NaHSO
3
Sol. 1
Na SO +dilute H SO  Na SO + H SO
2 3 2 4         2 4 2 3
H O + SO 
2 2
(Y)
NaOH
Na SO
2 3
SO + H O
2 2
NaHSO
3
(Z)
(x)
Ans. (1) Y = SO
2
Z = NaHSO
3
5. The value of K
C
 is 64 at 800 K for the reaction N
2
(g) + 3H
2
(g)  2NH
3
(g)
The value of K
C 
for the following reaction is :
NH
3
(g) ? ? ? ?
2 2
1 3
N g + H g
2 2
(1) 1/4 (2) 8 (3) 1/8 (4) 1/64
Sol. 3
K
C
 = 
1/2
(64)
?
K
C
 = 
1
8
6. The correct match between Item - I (Starting material) and Item - II (reagent) for the
preparation of benzaldehyde is :
Item - I Item - II
(I) Benzene (P) HCl and SnCl
2
.H
3
O
+
(II) Benzonitrile (Q) H
2
, Pd- BaSO
4
, and quinoline
(III) Benzoyl Chloride (R) CO, HCl and AlCl
3
(1) (I) - (R), (II) - (P) and (III) - (Q)
(2) (I) - (P), (II) - (Q) and (III) - (R)
(3) (I) - (Q), (II) - (R) and (III) - (P)
(4) (I) - (R), (II) - (Q) and (III) - (P)
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Sol. 1
+ CO + HCl
AlCl
3
CH=O
(Gattermann - koch aldehyde synthesis)
SnCl + HCl
2
CH=O
(stephen's reaction)
H O
3
+
H /Pd-BaSO
2 4
CH=O
(Rosenmund reduction)
C
O
Cl
CN
7. For a d
4
 metal ion in an octahedral field, the correct electronic configuration is :
(1) 
2 2
g 2g o
e t when  < P ? (2) 
4 o
2 g o
e when  < P
g
t ?
(3) 
3 1
2g o
e when  > P
g
t ? (4) 
3 1
2g o
e when  < P
g
t ?
Sol. 4
d
4
 ? 
3 1
2g g
t e – ?
0
 < P
8. The correct match between Item - I and Item - II is :
Item - I Item - II
(a) Natural rubber (I) 1,3-butadiene + styrene
(b) Neoprene (II) 1,3-butadiene + acrylonitrile
(c) Buna-N (III) Chloroprene
(d) Buna-S (IV) Isoprene
(1) (a) - (III), (b) - (IV), (c) - (I), (d) - (II)
(2) (a) - (IV), (b) - (III), (c) - (II), (d) - (I)
(3) (a) - (IV), (b) - (III), (c) - (I), (d) - (II)
(4) (a) - (III), (b) - (IV), (c) - (II), (d) - (I)
Sol. 2
By Theory
9. Which one of the following statement is not true ?
(1) Lactose contains a -glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
(2) Lactose is a reducing sugar and it gives Fehling's test.
(3) On acid hydrolysis, lactose gives one molecule of D(+)-glucose and one molecule of
D(+)-galactose.
(4) Lactose(C
11
H
22
O
11
) is a disaccharide and it contains 8 hydroxyl groups.
Sol. 1
Lactose contains ?-glycosidic linkage between C
1
 of galactose and C
4
 of glucose.
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 September 2020 | (Shift-2), Chemistry     Page | 4
O
CH –OH
2
OH
OH
OH
O
O
CH –OH
2
OH
OH
OH
Structure of Lactose
10. The element that can be refined by distillation is :
(1) tin (2) gallium
(3) zinc (4) nickel
Sol. 3
Zinc ? Refined by distillation
11. Match the following compounds (Column-I) with their uses (Column-II) :
S. No. Column – I S. No. Column – II
(I) Ca(OH)
2
(A) Casts of statues
(II) NaCl (B) White wash
(III)
4 2
1
CaSO . H O
2
(C) Antacid
(IV) CaCO
3
(D) Washing soda preparation
(1) (I)-(B),(II)-(C),(III)-(D),(IV)-(A) (2) (I)-(C),(II)-(D),(III)-(B),(IV)-(A)
(3) (I)-(B),(II)-(D),(III)-(A),(IV)-(C) (4) (I)-(D),(II)-(A),(III)-(C),(IV)-(B)
Sol. 3
(i) Ca(OH)
2
 ? used in white wash due to its disinfectant nature
(ii) CaCO
3
? it used as an Antacid
(iii) CaSO
4
 .
1
2
H
2
O ? Formaking casts of statues and busts
(iii) Preparation of wasing soda (sodium carbonate)
(1) 2NH
3
 + H
2
O + CO
2
 
? ? ? ?
(NH
4
)
2
CO
3
(2) (NH
4
)
2
CO
3
 + H
2
O + CO
2
 
? ? ? ?
2NH
4
HCO
3
(3) NH
4
HCO
3
 + NaCl 
? ? ? ?
NH
4
Cl + NaHCO
3
(4) 2NaHCO
3
 
? ? ? ?
Na
2
CO
3
 + CO
2
 + H
2
O
Ans. (3)
12. Mischmetal is an alloy consisting mainly of :
(1) lanthanoid and actinoid metals (2) lanthanoid metals
(3) actinoid metals (4) actinoid and transition metals
Sol. 2
Misch metal - well known alloy is mischmetal which consists of Lanthanoid metal
(~ 95%) and iron (~ 5%) and Traces of S, C, Ca and Al
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13. For a reaction,
? ? ? ? ? ?
2 2 n
4M s +nO g 2M O s ?
the free energy change is plotted as a function of temperature. The temperature below
which the oxide is stable could be inferred from the plot as the point at which :
(1) the free energy change shows a change from negative to positive value.
(2) the slope changes from positive to zero
(3) the slope changes from positive to negative.
(4) the slope changes from negative to positive.
Sol. 1
?G = ?H – T ?S
?G = –ve (stable oxide)
?G = +ve (unstable oxide)
14. The increasing order of the boiling points of the major products A,B and C of the
following reaction will be :
(a) 
+HBr
(C H CO)
6 5 2
A
O
(b) 
+ HBr B
(c) 
+ HBr 
C
(1) A < B < C (2) C < A < B
(3) A < C < B (4) B < C < A
Sol. 4
+ HBr
Br
(a)
+ HBr
(b)
Br
+ HBr
Br
(c)
(C H COO)
6 5 2
B.P ? 
1
Branching
15. The average molar mass of chlorine is 35.5g mol
-1
. The ratio of 
35
Cl to 
37
Cl in naturally
occurring chlorine is close to :
(1) 1 : 1 (2) 3 : 1
(3) 2 : 1 (4) 4 : 1
Sol. 2
35x 37y
35.5
x y
?
?
?
1.5y = –0.5x
x/y = 3/1