Q1: State all 3 Newton’s law of motion.
Ans:
Q2: Explain inertia and momentum.
Ans :
Q3: Define force. What are different types forces?
Ans:
Q4: What is inertia? Explain different types of inertia.
Ans:
Types of inertia :
Q5: Give example to show the effects of force.
Ans:
(i) Place a ball in the ground. Kick it with your foot. The ball starts moving. The ball moves because of the force applied to it.
(ii) If ball is coming towards you, you can kick it in any direction. The direction of motion of the ball changes because of the force applied to it.
(iii) Place a rubber on the ground. Press it with your foot. It is found that the ball is no longer round but takes the shape of an egg, i.e. it is oblong. The shape of the ball has changed because of the force applied on the ball.
Q6: (a) What is friction?
(b) What are the advantages of friction? or Why is friction necessary?
Ans:
(a) The force which opposes the motion of one body over the surface of another is called friction or the force of friction.
(b) Friction is very desirable and an important force in our daily life.
Some advantages of friction are :
Q7: (i) What are the causes of friction?
(ii) How can friction between any two surfaces can be reduced? or Describe some method for reducing friction.
Ans: The friction rises due to the following factors :
Q8: When a force of 40 N is applied on a body it moves with an acceleration of 5 ms2. Calculate the mass of the body.
Ans:
Let m be the mass of the body.
Given : F = 40 N, a = 5 ms2
From the relation F = m a, we have
40 = m × 5
m = 40/5 = 8 kg
Q9: An object undergoes an acceleration of 8 ms–2 starting from rest. Find the distance travelled in 1 second.
Ans: Given,
Acceleration, a = 8 ms–2
Initial velocity, u = 0
Time interval, t = 1 s
Distance travelled, s = ?
Using the equation of motion,
s = ut + 1/2 at2, one gets
s = 0 × 1 + 1/2 × 8 × 12 = 4 m
The object travels a distance of 4 m.
Q10: Calculate the force required to impact to a car, a velocity of 30 ms–1 in 10 seconds. The mass of the car is 1,500 kg.
Ans:
Here
u = 0 ms–1;
v = 30 ms–1;
t = 10 s;
a = ?
Using v = u + at, we have
30 = 0 + a (10) a
= 3 ms–2
Now
F = ma
= 1,500 × 3 or F = 4,500 N
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