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# Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced Notes | Study Maths 35 Years JEE Main & Advanced Past year Papers - JEE

## Document Description: Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced for JEE 2022 is part of Maths 35 Years JEE Main & Advanced Past year Papers preparation. The notes and questions for Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced have been prepared according to the JEE exam syllabus. Information about Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced covers topics like and Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced Example, for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Matrix-Match Type Questions: Miscellaneous (Sets, Relations, Statistics & Mathematica | JEE Advanced.

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Each question contains statements given in two columns, which have to be matched. The statements in Column-I are labelled A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any given statement in Column-I can have correct matching with ONE OR MORE statement(s) in ColumnII. The appropriate bubbles corresponding to the answers to these questions have to be darkened as illustrated in the following example :

If the correct matches are A-p, s and t; B-q and r; C-p and q; and D-s then the correct darkening of bubbles will look like the given.

Q. Match the statements given in Column-I with the intervals/union of intervals given in Column-II.             (2011)

Column-I                                                                                                                        Column-II

(A) The set : z is a complex number, |z| = 1 z ≠ ± 1}is                          (p) (-∞, - 1) ∪ (1,∞)

(B) The domain of the function f (x) =                                        (q) (-∞, - 0) ∪ (0,∞)

(C) If  then the set                                    (r) [2, ∞)

(s) (-∞, -1]U[1,∞)

(D) If f (x) = x3/2 (3x – 10), x ≥ 0 then f (x) is increasing in                                         (t) (-∞, 0]∪ [2,∞)

Ans. Sol. A → (s), B → (t), C → (r) D → (r)

et z = x + iy where and x2 +  y2 = 1 and x ≠ ± 1

Then Re = Re

where

∴ A  → s

(B) For the domain of f (x)

We should have

Let 3x = t then

and

and

Also t = 3x can not be – ve
∴ t ∈ (0, 3) ∪ [9,∞) and t ∈ (0,1] ∪ [3,∞)
Þ x ∈ (-∞,1) ∪ [2,∞) and x ∈ (-∞, 0] ∪ (1,∞)
Combining the two, we get x ∈ (-∞, 0] ∪ [2,∞)

∴ B → t

(C)

∴ C → r

(D) f (x) = x3/2 (3x - 10),x ≥ 0

For f(x) to be increasing f'(x) ≥ 0

but x ≥ 0 ⇒ x ≥ 2

∴ f (x) is incresing on [2,∞) ∴ D → r.

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## Maths 35 Years JEE Main & Advanced Past year Papers

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## Maths 35 Years JEE Main & Advanced Past year Papers

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