Class 7 Maths Chapter 7 Practice Question Answers - Comparing Quantities

Q1. A shopkeeper prefers to sell his goods at the cost price but uses a weight of 800 gm instead of 1 kg weight. He earns of profit of
(a) 2%
(b) 8%
(c) 20%
(d) 25%
Ans: (d)
Sol: Let CP of 1gm = Re1
Given : he sells 800gm instead of 1000gm(1kg)
So, CP of 800gm = 800Rs.
SP of 800gm= CP of 1000gm = 1000Rs.
Profit=1000 − 800 = Rs.200
Profit % = 200/800 x 100
= 25

Q2. Opposite of profit of Rs.250 is
(a) profit of Rs.50
(b) loss of Rs.250
(c) loss of Rs.150
(d) none
Ans: (b)
Sol: Opposite of profit of Rs.250 is Loss of Rs.250
∴ Option B is correct.

Q3. If the amount repaid is Rs. 450 and the principal is Rs. 415, then interest is equal to
(a) Rs. 25
(b) Rs. 35
(c) Rs.45
(d) Rs. 50
Ans: (b)
Sol: Amount (A) = Rs.450
Principal (P) = Rs.415
A = I + P
I = A − P = 450 − 415 = Rs.35

Q4. To make a cup of tea, the ratio of water to milk is 3:1. To make 4 cups of tea the ratio of water to milk is :
(a) 4 : 3
(b) 12 : 1
(c) 12 : 4
(d) : 12
Ans: (c)
Sol: A cup of tea has Water to Milk Ratio
W:M=3:1
where W and M are Water and Milk
Now, 4 cups will have 4 times the Water and milk of a single cup.
So, the ratio will be
= 3 x 4 / 1 x 4
= 12/4 or 12 : 4

Q5. The percentage of unshaded portion in the following figure is ____

(a) 25%

(b) 50%

(c) 75%

(d) 100%
Ans: (c)
Sol: (3/4)^th of the portion is shaded in the given figure.
Therefore, percentage of unshaded portion = 3/4 x 100
= 75%

Q6. Hari bought a pen for Rs. 125 and sold it for Rs. 120. The loss is
(a) Rs. 245
(b) Rs. 5
(c) Rs. 15
(d) none
Ans: (b)
Sol:
⇒  Cost price of pen is Rs.125
⇒  Selling price of pen is Rs.120
⇒  Loss = Costprice − sellingprice
⇒  Loss = 125 − 120 = Rs.5

Q7. 0.9 percent can be expressed as
(a) 0.009
(b) 0.09
(c) 0.0009
(d) 0.9
Ans: (a)
Sol:  0.9% = 0.9 / 100
= 0.009

Q8. 80% of a non-leap year =.......days
(a) 288
(b) 256
(c) 292
(d) 270
Ans: (c)
Sol: A non-leap year has =365 days
80% of a non-leap year = 80/100 x 365
292 days

Q9. If the selling price of 50 articles is equal to the cost price of 40 articles then the loss and gain percent is
(a) 20% gain
(b) 20% loss
(c) 25% loss
(d) 25% gain
Ans: (b)
Sol: Let (c) P of one article = 1 Rs.
Then (c) P of 40 article = 40 Rs.
According to the question
S.P of 50 article = (c) P of 40 article = 40 Rs.
We assume that (c) P of one article  = 1Rs.
then (c) P of 50 article = 50 Rs.
Loss=50 -  40=10 Rs.
Loss % = 10/50 x 100
= 20%

Q10. A, B and C enter into partnership A invests 3 times as much as B invests and B invests two-third of what C invests At the end of the year the profit earned is Rs 6600 What is the share of B?
(a) Rs 3600
(b) Rs 1800
(c) Rs 1200
(d) None of these
Ans: (c)
Sol: Let C invest x Rs.
Then according to the question B invest = 2x/3 Rs.
A invest = 2x/3 x 3 = 2x Rs.
Then, x + 2x/3 + 2x = 6600
⇒ 3x + 2x + 6x = 19800
⇒ 11x = 19800
⇒ x = 1800
Then B's share = 2/3 x 1800
= 1200 Rs.

Q11. A man bought a number of clips at 3 for a rupee and an equal number at 2 for a rupee At what price per dozen should he sell them to make a profit of 20%?
(a) Rs 4
(b) Rs 5
(c) Rs 6
(d) Rs 7
Ans: (c)
Sol: Let he bought 1 dozen clips of each kind.
(c) P of 2 dozen = 1/3 x 12 + 1/2 x 12 = 10Rs
S.P of 2 dozen = 120% of 10 =0120/100 x 10 = 12Rs
Hence S.P per dozen=6  Rs.

Q12. The list price of a parker pen is Rs 160 and a customer buys it for Rs 122.40 after two successive discounts. If first is 10% then the second is
(a) 18%
(b) 17%
(c) 16%
(d) 15%
Ans: (d)
Sol: Total discount = Rs160 − Rs122.40 = Rs37.60
1^st discount =10%ofRs160 = Rs16.
2^nd discount = Rs37.60 − Rs16 = Rs21.60
Balance after firsr discount = Rs160 − Rs16 = Rs144.
If 2^nd discount is x%, then x% of Rs 144 = Rs21.60,
So x = 15.

Q13. Equivalent of 6/20 is
(a) 6%
(b) 20%
(c) 26%
(d) 30%
Ans: (d)
Sol: Given fraction is 6/20
Equivalent percentage is
= 6/20 x 100
= 30%

Q14. Ranga buys a car for Rs 1,00,000 and spends Rs 20,000 on repairs. He rents it and earns Rs 4,000 per month. After 8 months, he sells the car for Rs 1,00,000. His total earning in rupees is
(a) 15,000
(b) 18,000
(c) 20,000
(d) 12,000
Ans: (d)
Sol: Total investment = 1,00,000 + 20,000 = 1,20,000
His earning in 8 months = 4,000 × 8 = 32,000
Total earnings =1,00,000 + 32,000 − 1,20,000
= 1,32,000 − 1,20,000
= Rs12,000

Q15. A trader marked the price of his commodity so as to include a profit of 25%. He allowed a discount of 16% on the MP. His actual profit was
(a) 5%
(b) 9%
(c) 16%
(d) 25%
Ans: (a)
Sol: Let the CP of the commodity is Rs. 100.
Therefore, expected MP of the commodity is Rs. 125.
According to the question,
Discount = 125 x 16 / 100 = Rs. 20
Therefore,
SP = 125 − 20=Rs. 105
Therefore,
Actual Profit = (105 - 100) / 100 x 100
= 5%
Therefore, net profit is 5%.

Q16. If the simple interest on a certain sum of money @ 4% for 5 years is Rs. 800, find the sum.
(a) Rs. 4000
(b) Rs. 9000
(c) Rs. 12000
(d) None of the above
Ans: (a)
Sol:  We have,
Rate = 4%, Time = 5 years & Simple interest = Rs. 800

Hence, answer is Rs. 4000

Q17. A and B invest Rs 200 and Rs 300 respectively in a business for a period for three years and two years respectively. Then the profit will be divided into the ratio of
(a) 4 : 3
(b) 2 : 3
(c) 1 : 1
(d) 6 : 5
Ans: (c)
Sol: Ratio in which they should share their profits = Raito of investments × Time period
= 200 x 3 / 300 x 2 = 600/600
= 1 : 1

Q18. Jayant sold two books at Rs 14 each. On one he gains 20% and on the other loses 20%. Then he made
(a) no profit no loss
(b) loss of 4%
(c) gain of 1%
(d) none of these
Ans: (b)
Sol: on the first article Jayant gains 20%
so if CP is 100, selling price will be 120 and profit will be Rs20
when selling price is 120 profit is 20
when selling price is 14 profit is= 20/120 x 14 = 2.33
cost price =selling price-profit
=14-2.33
=Rs11.67
on second article he losses 20%
so if CP is 100, selling price will be 80 and Loss will be Rs20
when selling price is 80 loss is 20
when selling price is 14 loss is = 20/80 x 14 = 3.5
cost price is =selling price+loss
=14+3.5
=17.5
total selling price=14 + 14 = Rs28
total cost price=17.5+11.67 = Rs29.17
net loss = 29.17-28 = Rs1.17
loss percentage = 1.17/29.17 x 100 = 4
he makes a loss of 4%

Q19. The list price of a parker pen is Rs 160 and a customer buys it for Rs 122.40 after two successive discounts. If first is 10% then the second is
(a) 18%
(b) 17%
(c) 16%
(d) 15%
Ans: (d)
Sol: Total discount = Rs160 − Rs122.40 = Rs37.60
1^st discount =10% of Rs160 = Rs16.
2^nd discount = Rs37.60 − Rs16 = Rs21.60
Balance after firsr discount = Rs160 − Rs16 = Rs144.
If 2^nd discount is x%, then x%ofRs144=Rs21.60,
so x = 15.

Q20. When the price of eggs is reduced by 20% it enables a man to buy 20 more eggs for Rs 40. Then the reduced price per egg is:
(a) 38 paise
(b) 40 paise
(c) 42 paise
(d) 44 paise
Ans: ()
Sol: Let's say Price per egg = x
Number of eggs  bought for Rs40 = 40/x
Reduced price of egg = x−20% of x
 ⇒ x − 0.2x = 0.8x
Number of eggs that can be bought= 40/0.8x
As per question,

Reduced price = 2 x 20/100 = 0.40 paise
Hence, the reduced price per egg will be 40 paise as 20% of Rs 2 is 40paise.