Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  Practice Questions: Integers

Class 7 Maths Chapter 1 Practice Question Answers - Integers

Q1. The value of 52−27 is
(a) 24
(b) 25
(c) 26
(d) −24

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: 52−27=25


Q2. (−60×−72) by (36×(−15))
(a) -8
(b) -16
(c) 8
(d) 16

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol:  Given,  
Class 7 Maths Chapter 1 Practice Question Answers - Integers

As there are 2 negative numbers in the numerator and 1 in the denominator, the answer will be negative.
Cancelling out the common factors and simplifying we get
Class 7 Maths Chapter 1 Practice Question Answers - Integers

= -4 x 2
= -8


Q3. Solve (−87)+(−35)=
(a) -122
(b) -65
(c) -35
(d) 87

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: It is given the expression, (-87) + (-35).

on solving brackets we get,

 = -87 - 35 (Both numbers are negative, so we add their absolute values, and the result remains negative.)

⇒ -122

So, the value of -87 + (-35) is -122.


Q4. Divide 96×(−25) by (−75)×(−16)
(a) -2
(b) 2
(c) -5
(d) 5

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 96×(−25)÷(−75)×(−16)
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
=−2400÷1200
=−2


Q5. Multiply: (−5)×8 and 3×(−2)
(a) 240
(b) 420
(c) -240
(d) -420

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (−5) × 8 = −40
3 × (−2) = −6
(W hen multiplying a positive and a negative number, the product will always be negative, regardless of the order of the signs.)
Hence, {(−5) × 8) × (3 × (−2)} = −40 × − 6
= 240


Q6. Multiply 4×(−3)×(−2) and 6×(−5)
(a) -720
(b) -70
(c) -270
(d) 720

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 4 × (−3) × (−2) × 6 × (−5)
Note: (When multiplying a positive and a negative number, the product will always be negative, regardless of the order of the signs.)

= 24 × −30
= −720


Q7. What value should come in place of question mark (?) in the questions given below ?
29 + 729 = ?

(a) 758
(b) 763
(c) 741
(d) 751

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 29 + 729 = 758

Q8. Evaluate:  (-16) × (-8) × (-81)(-18) × 32 
(a) −18
(b) 18
(c) 16
(d) −16

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol:

Simplify the expression:  (-16) × (-8) × (-81)(-18) × 32

The negative signs cancel each other, so we get: 
= 16 × 8 × 8118 × 32

Now simplify: 16 × 832 = 4, 
we get : 4 × 8118 = 4.5 × 4 = 18

Ans: 18.


Q9. Multiplication of a negative integer for even times gives a _____result 
(a) negative
(b) 0
(c) positive
(d) none

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol:  Multiplication 2 times: (−2) × (−2)=4
Multiplication 4 times: (−3) × (−3) × (−3) × (−3) = 9 × 9 = 81
Multiplication 6 times: (−1) × (−1) × (−1) × (−1) × (−1) × (−1) = 1 × 1 × 1 = 1
Hence, when a negative integer is multiplied even number of times, the result is a positive integer.


Q10. Evaluate (-4) × (6 + 7) and verify using the distributive property.
(a) 54
(b) -52
(c) -54
(d) 52

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)

Step 1: Simplify using the distributive property.

(-4) × (6 + 7) = (-4) × 13 = -52

Step 2: Break it down using the distributive property.

(-4) × (6 + 7) = [(-4) × 6] + [(-4) × 7]

= (-24) + (-28) = -52

Thus, the result is the same using both methods: -52.


Q11. 42(4 + 2) = (42 × 4) + (42 × 2) is an example of
(a) closure property
(b) commutative property
(c) associative property
(d) distributive property

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: 42(4 + 2) = (42 × 4) + (42 × 2) is an example of distributive property.
a(b + c) = (a × b) + (a × c) is the basic form of distributive property.


Q12. Sign of the product of 231 negative integers and 9 positive integers is 
(a) negative
(b) positive
(c) 0
(d) none

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: Since 231 is an odd number, the product of 231 negative integers will be negative. The product of all positive integers is a positive number. Hence, the product of 9 positive integers will be a positive integer.
Therefore, the product of the two integers (231 negative and 9 positive) of unlike signs will be negative.


Q13. Multiplication of a negative integer for even number of times gives a _________ number.
(a) negative
(b) 0
(c) positive
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: Observe −1×−1=1
Product of a pair of negative numbers is positive.
When even number of negative numbers are multiplied, the result is a positive number because every pair of negative terms will give a positive number.


Q14. Evaluate   Class 7 Maths Chapter 1 Practice Question Answers - Integers
(a) 9/4
(b) 9/8
(c) 9/2
(d) −9/2

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: 

Simplifying the expression: 5 × (-144) × (-27)(-15) × 18 × (-16)

The negative signs cancel out, leaving:

5 × 144 × 2715 × 18 × 16

First, simplify:

515 = 1/3

Now the expression becomes:

1 × 144 × 273 × 18 × 16

Simplify:

14418 = 8

Now the expression is

8 × 273 × 16

Simplify:

273 = 9

Now the expression is:

8 × 916 = 92


Q15. Which option shows the correct descending order ?

(a) 68788, 78688, 88687

(b) 78688, 68788, 88687

(c) 88687, 68788, 78688

(d) 88687, 78688, 68788

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: 

(a): 68788, 78688, 88687

Order: 68788 < 78688 < 88687 (not descending)

(b): 78688, 68788, 88687

Order: 78688 < 68788 < 88687 (not descending)

 (c): 88687, 68788, 78688

Order: 88687 > 68788 < 78688 (not descending)

 (d): 88687, 78688, 68788

Order: 88687 > 78688 > 68788 (descending)

Therefore, the correct answer is:

 (d): 88687, 78688, 68788

Q16. Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer, then answer the following:
An elevator descends into a mine shaft at the rate of 5 m/min. What will be its position after one hour? 

(a) 250
(b) 200
(c) 100
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: Since, the elevator going down, so the distance covered by it will be represented by a negative integer.
Change in position of elevator in one minute = −5 m
Position of the elevator after 60 minutes
= (−5) × 60

= −300  m
That means the position of the elevator will be 300 m below ground level.


Q17. Which of the following options shows the given number sentence?
-13 + (-3) = -16

(a) When two positive integers are added, we get a positive integer.
(b) When two negative integers are added, we get a negative integer.
(c) The subtraction of an integer is the same as the addition of its additive inverse.
(d) All of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: We are given that −13+(−3)=−16.
The LHS is the sum of the negative integers and the RHS is a negative integer. Thus, the correct answer is option B


Q18. The value of −5×−2×−2×−3  is
(a) 80
(b) 65
(c) 60
(d) -60

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: As there are 4 negative numbers, which is an even number, the product will be positive.
So, −5×− 2×− 2×− 3
= 60


Q19. Divide 96×(−25) by (−75)×(−16)
(a) -2
(b) 2
(c) -5
(d) 5

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 96 × (−25) ÷ (−75) × (−16)
Note: When multiplying two numbers with the same sign (both positive or both negative), the result is always positive. If one number is positive and the other is negative, the product is always negative, regardless of the order.
= −2400 ÷ 1200
= −2


Q20. The value of −5×−12 × 2×−3 is
(a) -360
(b) -380
(c) -400
(d) 360

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: As there are 3 negative numbers, which is an odd number, the product will be negative.
So, −5×−12 × 2×−3
=−360


Q21. Divide (−54)×(64) by (−27)×(−128)
(a) -1
(b) 1
(c) 5
(d) -4

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (−54) × (64) ÷ (−27) × (−128)
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
The answer will be positive if the product or quotient is positive (two positives or two negatives in the equation) or negative (one positive and one negative in the equation).
= −3456 ÷ 3456
= −1


Q22. Evaluate:(+48)+(−53)
(a) +5
(b) -5
(c) 5
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: (+48) + (−53)

To evaluate (+48)+(53), subtract the absolute values because the signs are different:

4853=(−548 - 53 = -54)

So, the result is 5-5


Q23. Fill in the blank:68 × ____ = −68
(a) 0
(b) 1
(c) -1
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: 68 × (−1)=−68


Q24. (-12) × (-3) × (+4) × (-6) =
(a) -144
(b) -908
(c) +864
(d) -864

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: Multiplying them in pairs.
There are 3 negative signs. So, the resultant of 3 multiplications would be negative.
Consider,
(−12) × (−3) × (+4) × (−6) = (−12×−3) × (4×−6)
=36×(−24)
=−864
Hence, Option D is correct.


Q25. Fill in the blank:−112 × _______ = +112
(a) +1
(b) 0
(c) -1
(d) +112

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: −112 × (−1)
= +112


Q26. (+13) + (−12) is equal to
(a) +1
(b) + 13
(c) - 1
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (+13) + (−12)
Two different signs (+ and − in either order) ( + and − in either order ) become a negative sign (−)
= +1


Q27. (+132) ÷ (−12)
(a) +101
(b) −101
(c) +11
(d) −11

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: (132) ÷ (−12)
The answer will be positive if the product or quotient is positive (two positives or two negatives in the equation) or negative (one positive and one negative in the equation).
= 132 / -12
= 12 x 11 / -12
=  -1 x 11
= - 11
Option D is correct.


Q28. If the dividend and divisor have like signs then the quotient will be_____.
(a) Positive
(b) Negative
(c) Zero
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: If the dividend and divisor have same  signs then the quotient will be positive.
For eg. 132/12 = 11
and -132/-12 = 11


Q29. Positive of a negative integer is____.
(a) Negative
(b) Positive
(c) Zero
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: Positive of a negative integer is negative.
Example: +(−40) = −40


Q30. The product of any number and "0" is ___
(a) 1
(b) 0
(c) number itself
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: The product of any number and zero is zero.
Theorem: 0 × a = 0 for any integer a.
So option B is the correct answer.

The document Class 7 Maths Chapter 1 Practice Question Answers - Integers is a part of the Class 7 Course Mathematics (Maths) Class 7.
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FAQs on Class 7 Maths Chapter 1 Practice Question Answers - Integers

1. What are integers and how are they represented on a number line?
Ans.Integers are whole numbers that can be positive, negative, or zero. They are represented on a number line with zero in the center, positive integers to the right, and negative integers to the left.
2. How do you add and subtract integers?
Ans.To add integers, if they have the same sign, you add their absolute values and keep the sign. If they have different signs, you subtract the smaller absolute value from the larger one and take the sign of the integer with the larger absolute value. To subtract integers, you can add the opposite of the integer you are subtracting.
3. What are the properties of integers?
Ans.The properties of integers include closure (the sum or product of two integers is an integer), commutative (the order of addition or multiplication does not change the result), associative (the way integers are grouped does not affect the sum or product), and distributive (multiplication distributes over addition).
4. How do you multiply and divide integers?
Ans.To multiply integers, if the signs are the same, the result is positive; if the signs are different, the result is negative. For division, the same rule applies: if the signs are the same, the result is positive; if different, the result is negative.
5. What is the importance of understanding integers in real-life situations?
Ans.Understanding integers is important in real life as they are used to represent various scenarios such as temperatures (above and below zero), financial transactions (profits and losses), and scoring in games (positive and negative scores). Knowing how to work with integers helps in making informed decisions in these contexts.
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