Class 10 Exam  >  Class 10 Notes  >  Extra Documents, Videos & Tests for Class 10  >  Probability Exercise 13.2

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10 PDF Download

Q.1: Suppose you drop a tie at random on the rectangular region shown in fig. below. What is the probability that it will land inside the circle with diameter 1 m?

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

Area of a circle with radius 0.5 m

A circle = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Area of rectangle = 3 x 2 = 6m2

Probability (geometric) = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

The probability that tie will land inside the circle with diameter 1m 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Q.2: In the accompanying diagram, a fair spinner is placed at the center O of the circle. Diameter AOB and radius OC divide the circle into three regions labeled X, Y and Z.��If Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10 = 45�. What is the probability that the spinner will land in the region X? 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

Given,

∠BOC = 450

 ∠AOC = 180 – 45 = 1350

Area of circle = πr2 

Area of region x = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

The probability that the spinner will land in the region 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Q.3: A target is shown in fig. below consists of three concentric circles of radii, 3, 7 and 9 cm respectively. A dart is thrown and lands on the target. What is the probability that the dart will land on the shaded region? 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

1st circle – with radius 3

2nd circle – with radius 7

3rd circle – with radius 9

Area of 1st circle = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Area of 2nd circle= Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Area of 3rd circle = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Area of shaded region = Area of 2nd circle – area of 1st circle 

= 49π-9π

= 40π

Probability that it will land on the shaded region = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Q.4: In below fig. points A, B, C and D are the centers of four circles that each has a radius of length one unit. If a point is selected at random from the interior of square ABCD. What is the probability that the point will be chosen from the shaded region? 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

Radius of circle = 1 cm

Length of side of square =1+ 1= 2 cm

Area of square = 2 x 2= 4 cm2

Area of shaded region = area of a square – 4 x area of the quadrant 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability that the point will be chosen from the shaded region = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Since geometrical probability, 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Q.5: In the fig. below, JKLM is a square with sides of length 6 units. Points A and B are the midpoints of sides KL and LM respectively. If a point is selected at random from the interior of the square. What is the probability that the point will be chosen from the interior of triangle JAB? 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

JKLM is a square with sides of length 6 units. Points A and B are the midpoints of sides KL and ML, respectively. If a point is selected at random from the interior of the square.

We have to find the probability that the point will be chosen from the interior of ΔJAB

Now,

Area of square JKLM is equal to 62 = 36 sq. units

Now, we have 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

= 9 units2

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

= 9 unit2

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

= 9/2 units2 

Now area of the triangle AJB 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10 36-9-9-9/2 

= 27/2 units2 

We know that Probability

Probability = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

= 3/8

Hence the Probability that the point will be chosen from the interior of ΔAJB is = 3/8.

Q.6: In the fig. below, a square dartboard is shown. The length of a side of the larger square is 1.5 times the length of a side of the smaller square. If a dart is thrown and lands on the larger square. What is the probability that it will land in the interior of the smaller square? 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Solution:

Let, the length of the side of smaller square = a

The a length of a side of bigger square = 1.5a

Area of smaller square =  a2

Area of bigger square = (1.5)2a2 = 2.25a2

Probability that dart will land in the interior of the smaller square = Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

= 4/9

Geometrical probability, 

Probability Exercise 13.2 | Extra Documents, Videos & Tests for Class 10

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