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__Projectile Motion in Inclined Plane__

**Ques 15: Find time of flight and range of the projectile along the inclined plane as shown in figure, (g = 10 m/s ^{2})**

(âˆµ Î± = 0Â°)

[as Î± = 0Â°]

or

Note:

(b) 20 ms

(c) 40 m

= (- g) - (- g)

= 0

(b) Initial velocity of 1st particle

Initial velocity of 2nd particle

âˆµ Initial velocity of 1st particle w.r.t. that of 2nd particle

(c) Horizontal velocity of 1st particle = 0 m/s

Horizontal velocity of 2nd particle

âˆ´ Horizontal velocity of 1st particle w.r.t. that of 2nd particle

Relative displacement of 1st particle w.r.t. 2nd particle at t = 2 s

âˆ´ Distance between the particles at t = 2 s = 40 m

(b) A parabola

= g - 0 = g

Horizontal velocity of stone

= v - v = 0

âˆ´ Path of the stone will be a straight line (downwards).

(b) As observed by man standing on ground

Vertical acceleration of stone = g

Horizontal velocity of stone = v

âˆ´ Path of the stone will be parabolic.

(a) Calculate the time taken by the stone to return to the floor.

(b) Sketch the path of the projectile as observed by an observer outdside the elevator.

(c) If the elevator was moving with a downward acceleration equal to g, how would the motion be altered?

(b) Dotted path [(in lift) acceleration upwards]

Full line path [In lift at rest or moving with constant velocity upwards or downwards].

(c) If lift is moving downward with acceleration g.

g

(u

x

âˆ´ u

Vertical motion:

or (u

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