Class 7 Exam  >  Class 7 Notes  >  RD Sharma Solutions for Class 7 Mathematics  >  RD Sharma Solutions - Ex - 10.1, Unitary Method, Class 7, Math

Ex - 10.1, Unitary Method, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics PDF Download

Question 1:

20 chocolates cost Rs 320. Find the cost of 35 such chocolates.

Answer 1:

Cost of 20 chocolates  = Rs. 320
Cost of 1 chocolate    =  Rs. 320 ÷ 20 =  16
So, cost of 35 chocolates = 35  ×  16 = Rs. 560

 

Question 2:

The cost of 40 metres of cloth is Rs 200. Find the cost of 50 metres of cloth.

Answer 2:

Cost of 40 metres of cloth = Rs. 200
Therefore, cost of 1 metre of cloth = Rs. 200÷40 = Rs. 5200÷40 = Rs. 5
Hence, cost of 50 metres of cloth = Rs. 5(50) = Rs. 250

 

Question 3:

A car can cover a distance of 522 km on 36 litres of petrol. How far can it travel on 14 litres of petrol?

Answer 3:

Distance covered by the car on 36 litres  = 522 km
Distance covered by the car on 1 litre = 522 ÷ 36 
Distance covered by the car on 14 litres = (522 ÷ 36) × 14  = 203 km 

 

Question 4:

Travelling 900 km by rail costs Rs 280. What would be the fare for a journey of 360 km when a person travels by the same class?

Answer 4:

Fare for 900 km of rail travel = Rs. 280
Fare for 1 km =  Rs. 280 ÷  900
Therefore, fare for 360 km = (280 ÷ 900) × 360 =  Rs. 112

 

Question 5:

If 6 oil tankers can be filled by a pipe in 4 1/212 hours, how long does the pipe take to fill 4 such oil tankers?

Answer 5:

Time taken by the pipe to fill 6 oil tankers = 4 1/2 = 9/2 hours
Time taken to fill 1 oil tanker =  92×16 = 34hours92×16 = 34hours
Therefore, the pipe will be able to fill 4 oil tankers in 34×4 = 3 hours.34×4 = 3 hours.

 

Question 6:

3/4 of the salary per month is Rs 600. What is the salary per month?

Answer 6:

Let the salary be Rs. x.
Then, 3/4 of the salary per month = Rs. 600.
That is, (3/4) x = 600
⇒ = (4 × 600) ÷ 3 = Rs. 800
So, the salary = Rs. 800.

 

Question 7:

The cost of 32 tables is Rs 23520. Find the number of such tables that can be purchased for Rs 51450.

Answer 7:

With Rs. 23520, we can buy 32 tables.
Therefore, with Re. 1, we can buy 3223520 3223520  tables.
Hence, the number of tables that we can purchase with Rs. 51450 = 223520×51450223520×51450 = 70.

 

Question 8:

The yield of wheat from 6 hectares is 280 quintals. Find the number of hectares required for a yield of 225 quntals.

Answer 8:

Yield of wheat from 6 hectares = 280 quintals
Yield of wheat from 1 hectare = 280 ÷ 6 =  46.66 quintals
Number of hectares required for a yield of 225 quintals = 225 ÷ 46.66 = 4.8 hectares
So, 4.8 hectares is required for a yield of 225 quintals.

 

Question 9:

Fifteen post cards cost Rs 2.25. What will be the cost of 36 post cards? How many postcards can we buy in Rs 45?

Answer 9:

Cost of 15 postcards = Rs. 2.25
Cost of 1 postcard = Rs. 2.25 ÷ 15  =  Rs. 0.15
Cost of 36 postcards = 36 × (2.25 ÷ 15) =  Rs. 5.4
Number of postcards that can be bought for Rs. 45 = 45 ÷ 0.15 = 300

 

Question 10:

A rail journey of 75 km costs Rs 215. How much will a journey of 120 km cost?

Answer 10:

Fare for a rail journey of 75 km = Rs. 215
Fare for 1 km = Rs. 215 ÷ 75 =  Rs. 2.86
Fare for 120 km = Rs. 120  × 2.86 = Rs. 343.2

 

Question 11:

If the sales tax on a purchase wirth Rs 60 is Rs 4.20. What will be the sales tax on the purchase worth of Rs 150?

Answer 11:

Sales tax on purchase worth Rs. 60 = Rs. 4.20 
Sales tax on purchase worth Re. 1 = 4.20 ÷  60
Therefore, sales tax on purchase worth Rs. 150 = Rs. 150 × (4.20 ÷ 60) = Rs. 10.5.

Question 12:

52 packets of 12 pencils each, cost Rs 499.20. Find the cost of 65 packets of 10 pencils each.

Answer 12:

Cost of 52 packets of 12 pencils each = Rs. 499.20
Cost of 1 packet of 12 pencils = Rs. 499.20 ÷ 52 = Rs. 9.6
Therefore, cost of 12 pencils = Rs. 9.6
So, cost of 1 pencil = Rs. 9.6 ÷ 12 = Rs. 0.8
Cost of 10 pencils = Rs. 10 × (9.6 ÷ 12) = Rs. 8
Therefore, cost of 1 packet of 10 pencils each = Rs. 8
Hence, cost of 65 packets of 10 pencils each =  65  × Rs. 8 = Rs. 520

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FAQs on Ex - 10.1, Unitary Method, Class 7, Math RD Sharma Solutions - RD Sharma Solutions for Class 7 Mathematics

1. What is the unitary method in mathematics?
Ans. The unitary method is a technique used in mathematics to solve problems involving proportionality. It involves finding the value of one unit and then using that value to find the value of a given quantity.
2. How do you solve problems using the unitary method?
Ans. To solve problems using the unitary method, first, determine the value of one unit. Then, use this value to find the value of the desired quantity by multiplying or dividing accordingly.
3. Can you give an example of solving a problem using the unitary method?
Ans. Sure! Let's say it takes 4 hours for a machine to produce 60 units of a product. To find out how many units the machine can produce in 10 hours, we can set up a proportion: 4 hours / 60 units = 10 hours / x units. Cross-multiplying, we get 4x = 600. Dividing both sides by 4, we find that the machine can produce 150 units in 10 hours.
4. What are some real-life applications of the unitary method?
Ans. The unitary method can be applied to various real-life situations. For example, it can be used to calculate the amount of ingredients needed to make a recipe for a different number of servings, to determine the cost of a certain number of items based on their individual prices, or to find out the time it takes for a certain number of workers to complete a job.
5. Are there any alternative methods to solve proportionality problems?
Ans. Yes, there are alternative methods to solve proportionality problems. Some other methods include the cross-multiplication method, the rule of three method, and the direct variation method. These methods can be used depending on the specific problem and personal preference.
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