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**Ashu had 24 pages to write. By the evening, he had completed 25% of his work. How many pages were left?**

Total number of pages Ashu had to write = 24

Number of pages Ashu completed by the evening = 25% of 24 = (25/100) Ã— 24 = 600/100 = 6

Pages left for completion = 24 - 6 = 18 pages

**A box contains 60 eggs. Out of which are rotten ones. How many eggs are rotten?**

Total eggs in the bag = 60

Rotten eggs =

**Rohit obtained 45 marks out of 80. What per cent marks did he get.**

Marks obtained by Rohit = 45/80

Percentage of marks that Rohit obtained = (45/80) Ã— 100 =

**Mr Virmani saves 12% of his salary. If he receives Rs 15900 per month as salary, find his monthly expenditure.**

Mr. Virmani's salary = Rs. 15900 per month

Mr. Virmani's savings = 12% of Rs. 15900 = (12/100) Ã— 15900 = Rs. 1908

Mr. Virmani's monthly expenditure = Rs. (15900 - 1908) = Rs. 13992

**A lawyer willed his 3 sons Rs 250000 to be divided into portions 30%, 45% and 25%. How much did each of them inherit?**

Total amount with the lawyer = Rs. 250000

First son's inheritance = 30% of 250000 = (30/100) Ã— 250000 = 7500000/100 = Rs. 75000

Second son's inheritance = 45% of 250000 = (45/1000) Ã— 250000 = 11250000/100 = Rs. 112500

Third son's inheritance = 25% of 250000 = (25/100) Ã— 250000 = 6250000/100 = Rs. 62500

**Rajdhani College has 2400 students, 40% of whom are girls. How many boys are there inthe college?**

Total number of students in Rajdhani College = 2400

Number of girls = 40% of 2400 = (40/100) Ã— 2400 = 96000/100 = 960

Number of boys = 2400 - 960 = 1440 boys

**Aman obtained 410 marks out of 500 in CBSE XII examination while his brother Anish gets 536 marks out of 600 in IX class examination. Find whose performance is better?**

Aman's marks in CBSE XII = 410/500

Percentage of marks obtained by Aman = (410/500) Ã— 100 = 82

Anish's marks in CBSE IX = 536/600

Percentage of marks obtained by Anish = (536/600) Ã— 100 = 89.33

So, Anish's performance (89.33%) is better than Aman's (82%).

**Rahim obtained 60 marks out of 75 in Mathematics. Find the percentage of marks obtained by Rahim in Mathematics.**

Marks obtained by Rahim in mathematics = 60/75

Percentage of marks obtained by Rahim = (60/75) Ã— 100 = 80

That is, 80%.

**In an orchard, ** **of the trees are apple trees. If the number of trees in the orchard is 240, find the number of other type of trees in the orchard.**

Let the number of apple trees be 'x'.

Number of trees in the orchard = 240

Number of apple trees = of x

According to the given condition,

Number of other types of trees = Total number of trees - number of apple trees = 240 - 40 = 200 trees

**Ram scored 553 marks out of 700 and Gita scored 486 marks out of 600 in science. Whose performance is better?**

Marks scored by Ram = 553/700

Percentage of marks scored by Ram = (553/700) Ã— 100 = 0.79 Ã— 100 = 79

Marks scored by Gita = 486/600

Percentage of marks scored by Gita = (486/600) Ã— 100 = 0.81 Ã— 100 = 81

Gita's performance (81%) is better than Ram's (79%).

**Out of an income of Rs 15000, Nazima spends Rs 10200. What per cent of her income does she save?**

Nazima's total income = Rs. 15000

Amount Nazima spends = Rs. 10200

Amount Nazima saves = Rs. (15000 - 10200) = Rs. 4800

Percentage of income Nazima saves = (4800/10200) Ã— 100 = 480000/10200 = 32

Nazima saves 32% of her income.

**45% of the students in a school are boys. If the total number of students in the school is 880, find the number of girls in the school.**

Total number of students in the school = 880

Number of boys in the school = 45% of 880

= (45/100) Ã— 880

= 39600/100 = 396

Number of girls in the school = 880 - 396 = 484

**Mr. Sidhana saves 28% of his income. If he saves Rs 840 pr month, find his monthely income.**

Let Mr. Sidhana's monthly income be *x.*

Monthly savings = Rs. 840

28% of *x = *Rs. 840

â‡’ (28/100) Ã— *x = *Rs. 840

â‡’ 28*x* = Rs. 84000

â‡’ *x* = Rs. (84000/28) = Rs. 3000

Mr. Sidhana's monthly income = Rs. 3000

**In an examination, 8% of the students fail. What percentage of the students pass? If 1650 students appeared in the examination, how many passed?**

Total number of students who appeared for the examination = 1650

Number of students who failed = 8% of 1650

= (8/100) Ã—1650

= (8 Ã— 1650)/100

= 13200/100 = 132

Number of students who passed = 1650 - 132 = 1518

Percentage of students who passed = (1518/1650) Ã— 100 = 0.92 Ã— 100 = 92

That is, 92% of the students passed the examination.

**In an examination, 9% of the candidates passed and 46 failed. How many candidates appeared?**

Let the total number of candidates be *x.*

Number of candidates who failed = 46

Number of candidates who passed = 92% of *x *

According to the given condition,

92% of *x = x - *46

â‡’ (92/100) *x = x - *46

â‡’ 92*x** = *100*x** - *4600

â‡’ -8*x** = - *4600

â‡’ *x = *4600/8 =

Number of candidates who appeared for the examination = 575