Open App

Class 7 Exam > Class 7 Notes > Mathematics (Maths) Class 7 > RD Sharma Solutions: Exponents (Exercise 6.1)

Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7 PDF Download

Download, print and study this document offline

Please wait while the PDF view is loading

 Page 1


 
 
 
 
 
 
 
Exercise 6.1         Page No: 6.12 
 
1. Find the values of each of the following: 
(i) 13
2
 
(ii) 7
3
 
(iii) 3
4 
 
Solution: 
(i) Given 13
2
 
13
2 
= 13 × 13 =169 
 
(ii) Given 7
3 
7
3
 = 7 × 7 × 7 = 343 
 
(iii) Given 3
4
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
 
2. Find the value of each of the following: 
(i) (-7)
2
 
(ii) (-3)
4
 
(iii)  (-5)
5
 
 
Solution: 
(i) Given (-7)
2 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-7)
2
 = (-7) × (-7) 
= 49 
 
(ii) Given (-3)
4 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-3)
4
 = (-3) × (-3) × (-3) × (-3) 
= 81 
 
(iii) Given (-5)
5
 
Page 2


 
 
 
 
 
 
 
Exercise 6.1         Page No: 6.12 
 
1. Find the values of each of the following: 
(i) 13
2
 
(ii) 7
3
 
(iii) 3
4 
 
Solution: 
(i) Given 13
2
 
13
2 
= 13 × 13 =169 
 
(ii) Given 7
3 
7
3
 = 7 × 7 × 7 = 343 
 
(iii) Given 3
4
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
 
2. Find the value of each of the following: 
(i) (-7)
2
 
(ii) (-3)
4
 
(iii)  (-5)
5
 
 
Solution: 
(i) Given (-7)
2 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-7)
2
 = (-7) × (-7) 
= 49 
 
(ii) Given (-3)
4 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-3)
4
 = (-3) × (-3) × (-3) × (-3) 
= 81 
 
(iii) Given (-5)
5
 
 
 
 
 
 
 
 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-5)
5
 = (-5) × (-5) × (-5) × (-5) × (-5) 
= -3125 
 
3. Simplify: 
(i) 3 × 10
2
 
(ii) 2
2
 × 5
3
 
(iii) 3
3
 × 5
2
 
 
Solution: 
(i) Given 3 × 10
2 
3 × 10
2
 = 3 × 10 × 10 
= 3 × 100 
= 300 
 
(ii) Given 2
2
 × 5
3
  
2
2
 × 5
3
 = 2 × 2 × 5 × 5 × 5 
= 4 × 125 
= 500 
 
(iii) Given 3
3
 × 5
2
 
3
3 
× 5
2
 = 3 × 3 × 3 × 5 × 5 
= 27 × 25 
= 675 
 
4. Simply: 
(i)  3
2
 × 10
4
 
(ii)  2
4
 × 3
2
 
(iii) 5
2
 × 3
4
 
  
Solution: 
(i)  Given 3
2 
× 10
4
   
3
2 
× 10
4
 = 3 × 3 × 10 × 10 × 10 × 10 
= 9 × 10000 
= 90000 
 
Page 3


 
 
 
 
 
 
 
Exercise 6.1         Page No: 6.12 
 
1. Find the values of each of the following: 
(i) 13
2
 
(ii) 7
3
 
(iii) 3
4 
 
Solution: 
(i) Given 13
2
 
13
2 
= 13 × 13 =169 
 
(ii) Given 7
3 
7
3
 = 7 × 7 × 7 = 343 
 
(iii) Given 3
4
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
 
2. Find the value of each of the following: 
(i) (-7)
2
 
(ii) (-3)
4
 
(iii)  (-5)
5
 
 
Solution: 
(i) Given (-7)
2 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-7)
2
 = (-7) × (-7) 
= 49 
 
(ii) Given (-3)
4 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-3)
4
 = (-3) × (-3) × (-3) × (-3) 
= 81 
 
(iii) Given (-5)
5
 
 
 
 
 
 
 
 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-5)
5
 = (-5) × (-5) × (-5) × (-5) × (-5) 
= -3125 
 
3. Simplify: 
(i) 3 × 10
2
 
(ii) 2
2
 × 5
3
 
(iii) 3
3
 × 5
2
 
 
Solution: 
(i) Given 3 × 10
2 
3 × 10
2
 = 3 × 10 × 10 
= 3 × 100 
= 300 
 
(ii) Given 2
2
 × 5
3
  
2
2
 × 5
3
 = 2 × 2 × 5 × 5 × 5 
= 4 × 125 
= 500 
 
(iii) Given 3
3
 × 5
2
 
3
3 
× 5
2
 = 3 × 3 × 3 × 5 × 5 
= 27 × 25 
= 675 
 
4. Simply: 
(i)  3
2
 × 10
4
 
(ii)  2
4
 × 3
2
 
(iii) 5
2
 × 3
4
 
  
Solution: 
(i)  Given 3
2 
× 10
4
   
3
2 
× 10
4
 = 3 × 3 × 10 × 10 × 10 × 10 
= 9 × 10000 
= 90000 
 
 
 
 
 
 
 
 
(ii) Given2
4
 × 3
2
  
2
4
 × 3
2
 = 2 × 2 × 2 × 2 × 3 × 3 
= 16 × 9 
= 144 
 
(iii) Given 5
2
 × 3
4
  
5
2
 × 3
4
 = 5 × 5 × 3 × 3 × 3 × 3 
= 25 × 81 
= 2025 
 
5. Simplify: 
(i) (-2) × (-3)
3
 
(ii) (-3)
2
 × (-5)
3
 
(iii) (-2)
5
 × (-10)
2
 
 
Solution: 
(i) Given (-2) × (-3)
3
   
(-2) × (-3)
3
 = (-2) × (-3) × (-3) × (-3) 
= (-2) × (-27) 
= 54 
 
(ii) Given (-3)
2
 × (-5)
3
  
(-3)
2
 × (-5)
3
 = (-3) × (-3) × (-5) × (-5) × (-5) 
= 9 × (-125) 
= -1125 
 
(iii) Given (-2)
5
 × (-10)
2  
(-2)
5
 × (-10)
2 
= (-2) × (-2) × (-2) × (-2) × (-2) × (-10) × (-10)
 
= (-32) × 100 
= -3200 
 
6. Simplify: 
(i) (3/4)
2
 
(ii) (-2/3)
4
 
(iii) (-4/5)
5
 
 
Solution: 
Page 4


 
 
 
 
 
 
 
Exercise 6.1         Page No: 6.12 
 
1. Find the values of each of the following: 
(i) 13
2
 
(ii) 7
3
 
(iii) 3
4 
 
Solution: 
(i) Given 13
2
 
13
2 
= 13 × 13 =169 
 
(ii) Given 7
3 
7
3
 = 7 × 7 × 7 = 343 
 
(iii) Given 3
4
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
 
2. Find the value of each of the following: 
(i) (-7)
2
 
(ii) (-3)
4
 
(iii)  (-5)
5
 
 
Solution: 
(i) Given (-7)
2 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-7)
2
 = (-7) × (-7) 
= 49 
 
(ii) Given (-3)
4 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-3)
4
 = (-3) × (-3) × (-3) × (-3) 
= 81 
 
(iii) Given (-5)
5
 
 
 
 
 
 
 
 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-5)
5
 = (-5) × (-5) × (-5) × (-5) × (-5) 
= -3125 
 
3. Simplify: 
(i) 3 × 10
2
 
(ii) 2
2
 × 5
3
 
(iii) 3
3
 × 5
2
 
 
Solution: 
(i) Given 3 × 10
2 
3 × 10
2
 = 3 × 10 × 10 
= 3 × 100 
= 300 
 
(ii) Given 2
2
 × 5
3
  
2
2
 × 5
3
 = 2 × 2 × 5 × 5 × 5 
= 4 × 125 
= 500 
 
(iii) Given 3
3
 × 5
2
 
3
3 
× 5
2
 = 3 × 3 × 3 × 5 × 5 
= 27 × 25 
= 675 
 
4. Simply: 
(i)  3
2
 × 10
4
 
(ii)  2
4
 × 3
2
 
(iii) 5
2
 × 3
4
 
  
Solution: 
(i)  Given 3
2 
× 10
4
   
3
2 
× 10
4
 = 3 × 3 × 10 × 10 × 10 × 10 
= 9 × 10000 
= 90000 
 
 
 
 
 
 
 
 
(ii) Given2
4
 × 3
2
  
2
4
 × 3
2
 = 2 × 2 × 2 × 2 × 3 × 3 
= 16 × 9 
= 144 
 
(iii) Given 5
2
 × 3
4
  
5
2
 × 3
4
 = 5 × 5 × 3 × 3 × 3 × 3 
= 25 × 81 
= 2025 
 
5. Simplify: 
(i) (-2) × (-3)
3
 
(ii) (-3)
2
 × (-5)
3
 
(iii) (-2)
5
 × (-10)
2
 
 
Solution: 
(i) Given (-2) × (-3)
3
   
(-2) × (-3)
3
 = (-2) × (-3) × (-3) × (-3) 
= (-2) × (-27) 
= 54 
 
(ii) Given (-3)
2
 × (-5)
3
  
(-3)
2
 × (-5)
3
 = (-3) × (-3) × (-5) × (-5) × (-5) 
= 9 × (-125) 
= -1125 
 
(iii) Given (-2)
5
 × (-10)
2  
(-2)
5
 × (-10)
2 
= (-2) × (-2) × (-2) × (-2) × (-2) × (-10) × (-10)
 
= (-32) × 100 
= -3200 
 
6. Simplify: 
(i) (3/4)
2
 
(ii) (-2/3)
4
 
(iii) (-4/5)
5
 
 
Solution: 
 
 
 
 
 
 
 
(i) Given (3/4)
2
 
(3/4)
2
 = (3/4) × (3/4)  
= (9/16) 
 
(ii) Given (-2/3)
4
 
(-2/3)
4
 = (-2/3) × (-2/3) × (-2/3) × (-2/3) 
= (16/81) 
 
(iii) Given (-4/5)
5 
(-4/5)
5
 = (-4/5) × (-4/5) × (-4/5) × (-4/5) × (-4/5) 
= (-1024/3125) 
 
7. Identify the greater number in each of the following: 
(i) 2
5
 or 5
2
 
(ii) 3
4
 or 4
3
 
(iii) 3
5
 or 5
3
 
 
Solution: 
(i) Given 2
5
 or 5
2
 
2
5
 = 2 × 2 × 2 × 2 × 2 
= 32 
5
2
 = 5 × 5 
= 25 
Therefore, 2
5
 > 5
2
 
 
(ii) Given 3
4
 or 4
3
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
4
3 
= 4 × 4 × 4 
= 64 
Therefore, 3
4
 > 4
3
 
 
(iii) Given 3
5 
or 5
3
 
3
5
 = 3 × 3 × 3 × 3 × 3 
= 243 
5
3
 = 5 × 5 × 5 
= 125 
Page 5


 
 
 
 
 
 
 
Exercise 6.1         Page No: 6.12 
 
1. Find the values of each of the following: 
(i) 13
2
 
(ii) 7
3
 
(iii) 3
4 
 
Solution: 
(i) Given 13
2
 
13
2 
= 13 × 13 =169 
 
(ii) Given 7
3 
7
3
 = 7 × 7 × 7 = 343 
 
(iii) Given 3
4
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
 
2. Find the value of each of the following: 
(i) (-7)
2
 
(ii) (-3)
4
 
(iii)  (-5)
5
 
 
Solution: 
(i) Given (-7)
2 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-7)
2
 = (-7) × (-7) 
= 49 
 
(ii) Given (-3)
4 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-3)
4
 = (-3) × (-3) × (-3) × (-3) 
= 81 
 
(iii) Given (-5)
5
 
 
 
 
 
 
 
 
We know that (-a) 
even number
= positive number 
(-a)
 odd number 
= negative number 
We have, (-5)
5
 = (-5) × (-5) × (-5) × (-5) × (-5) 
= -3125 
 
3. Simplify: 
(i) 3 × 10
2
 
(ii) 2
2
 × 5
3
 
(iii) 3
3
 × 5
2
 
 
Solution: 
(i) Given 3 × 10
2 
3 × 10
2
 = 3 × 10 × 10 
= 3 × 100 
= 300 
 
(ii) Given 2
2
 × 5
3
  
2
2
 × 5
3
 = 2 × 2 × 5 × 5 × 5 
= 4 × 125 
= 500 
 
(iii) Given 3
3
 × 5
2
 
3
3 
× 5
2
 = 3 × 3 × 3 × 5 × 5 
= 27 × 25 
= 675 
 
4. Simply: 
(i)  3
2
 × 10
4
 
(ii)  2
4
 × 3
2
 
(iii) 5
2
 × 3
4
 
  
Solution: 
(i)  Given 3
2 
× 10
4
   
3
2 
× 10
4
 = 3 × 3 × 10 × 10 × 10 × 10 
= 9 × 10000 
= 90000 
 
 
 
 
 
 
 
 
(ii) Given2
4
 × 3
2
  
2
4
 × 3
2
 = 2 × 2 × 2 × 2 × 3 × 3 
= 16 × 9 
= 144 
 
(iii) Given 5
2
 × 3
4
  
5
2
 × 3
4
 = 5 × 5 × 3 × 3 × 3 × 3 
= 25 × 81 
= 2025 
 
5. Simplify: 
(i) (-2) × (-3)
3
 
(ii) (-3)
2
 × (-5)
3
 
(iii) (-2)
5
 × (-10)
2
 
 
Solution: 
(i) Given (-2) × (-3)
3
   
(-2) × (-3)
3
 = (-2) × (-3) × (-3) × (-3) 
= (-2) × (-27) 
= 54 
 
(ii) Given (-3)
2
 × (-5)
3
  
(-3)
2
 × (-5)
3
 = (-3) × (-3) × (-5) × (-5) × (-5) 
= 9 × (-125) 
= -1125 
 
(iii) Given (-2)
5
 × (-10)
2  
(-2)
5
 × (-10)
2 
= (-2) × (-2) × (-2) × (-2) × (-2) × (-10) × (-10)
 
= (-32) × 100 
= -3200 
 
6. Simplify: 
(i) (3/4)
2
 
(ii) (-2/3)
4
 
(iii) (-4/5)
5
 
 
Solution: 
 
 
 
 
 
 
 
(i) Given (3/4)
2
 
(3/4)
2
 = (3/4) × (3/4)  
= (9/16) 
 
(ii) Given (-2/3)
4
 
(-2/3)
4
 = (-2/3) × (-2/3) × (-2/3) × (-2/3) 
= (16/81) 
 
(iii) Given (-4/5)
5 
(-4/5)
5
 = (-4/5) × (-4/5) × (-4/5) × (-4/5) × (-4/5) 
= (-1024/3125) 
 
7. Identify the greater number in each of the following: 
(i) 2
5
 or 5
2
 
(ii) 3
4
 or 4
3
 
(iii) 3
5
 or 5
3
 
 
Solution: 
(i) Given 2
5
 or 5
2
 
2
5
 = 2 × 2 × 2 × 2 × 2 
= 32 
5
2
 = 5 × 5 
= 25 
Therefore, 2
5
 > 5
2
 
 
(ii) Given 3
4
 or 4
3
 
3
4
 = 3 × 3 × 3 × 3 
= 81 
4
3 
= 4 × 4 × 4 
= 64 
Therefore, 3
4
 > 4
3
 
 
(iii) Given 3
5 
or 5
3
 
3
5
 = 3 × 3 × 3 × 3 × 3 
= 243 
5
3
 = 5 × 5 × 5 
= 125 
 
 
 
 
 
 
 
Therefore, 3
5
 > 5
3
 
  
8. Express each of the following in exponential form: 
(i) (-5) × (-5) × (-5) 
(ii) (-5/7) × (-5/7) × (-5/7) × (-5/7) 
(iii) (4/3) × (4/3) × (4/3) × (4/3) × (4/3) 
 
Solution: 
(i) Given (-5) × (-5) × (-5) 
Exponential form of (-5) × (-5) × (-5) = (-5)
3
 
 
(ii) Given (-5/7) × (-5/7) × (-5/7) × (-5/7) 
Exponential form of (-5/7) × (-5/7) × (-5/7) × (-5/7) = (-5/7)
4
 
 
(iii) Given (4/3) × (4/3) × (4/3) × (4/3) × (4/3) 
Exponential form of (4/3) × (4/3) × (4/3) × (4/3) × (4/3) = (4/3)
5
 
 
9. Express each of the following in exponential form: 
(i) x × x × x × x × a × a × b × b × b 
(ii) (-2) × (-2) × (-2) × (-2) × a × a × a 
(iii) (-2/3) × (-2/3) × x × x × x 
 
Solution: 
(i) Given x × x × x × x × a × a × b × b × b 
Exponential form of x × x × x × x × a × a × b × b × b = x
4
a
2
b
3
 
 
(ii) Given (-2) × (-2) × (-2) × (-2) × a × a × a 
Exponential form of (-2) × (-2) × (-2) × (-2) × a × a × a = (-2)
4
a
3
 
 
(iii) Given (-2/3) × (-2/3) × x × x × x 
Exponential form of (-2/3) × (-2/3) × x × x × x = (-2/3)
2 
x
3
 
 
10. Express each of the following numbers in exponential form: 
(i) 512 
(ii) 625 
(iii) 729 
Solution:

	Mathematics (Maths) Class 7 76 videos\|345 docs\|39 tests

Mathematics (Maths) Class 7

76 videos|345 docs|39 tests

Join Course for Free

Top Courses for Class 7

View all

FAQs on Exponents (Exercise 6.1) RD Sharma Solutions - Mathematics (Maths) Class 7

1. What are exponents?

Ans. Exponents are mathematical notation that represents how many times a number, known as the base, is multiplied by itself. It is written as a superscript to the right of the base number. For example, in the expression 2^3, 2 is the base and 3 is the exponent. It means that 2 is multiplied by itself three times, resulting in 8.

2. How do exponents work?

Ans. Exponents work by indicating how many times a number should be multiplied by itself. The base number is multiplied by itself the number of times specified by the exponent. For example, in the expression 5^2, the base number 5 is multiplied by itself two times, resulting in 25.

3. What is the rule for multiplying exponents with the same base?

Ans. When multiplying exponents with the same base, you add the exponents together. For example, if you have 2^3 * 2^2, you can rewrite it as 2^(3+2), which simplifies to 2^5. Therefore, 2^3 * 2^2 is equal to 32.

4. What is the rule for dividing exponents with the same base?

Ans. When dividing exponents with the same base, you subtract the exponent of the divisor from the exponent of the dividend. For example, if you have 4^5 / 4^3, you can rewrite it as 4^(5-3), which simplifies to 4^2. Therefore, 4^5 / 4^3 is equal to 16.

5. How do you simplify expressions with exponents?

Ans. To simplify expressions with exponents, you apply the rules of exponents. This includes combining like terms by adding or subtracting the exponents, multiplying exponents with the same base by adding the exponents, and dividing exponents with the same base by subtracting the exponents. By simplifying the expressions, you can obtain a single term or a simplified form of the expression.

Related Exams

Class 7

About this Document

	4.85/5 Rating
	Nov 24, 2024 Last updated

Document Description: RD Sharma Solutions: Exponents (Exercise 6.1) for Class 7 2024 is part of Mathematics (Maths) Class 7 preparation. The notes and questions for RD Sharma Solutions: Exponents (Exercise 6.1) have been prepared according to the Class 7 exam syllabus. Information about RD Sharma Solutions: Exponents (Exercise 6.1) covers topics like and RD Sharma Solutions: Exponents (Exercise 6.1) Example, for Class 7 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Exponents (Exercise 6.1).

Introduction of RD Sharma Solutions: Exponents (Exercise 6.1) in English is available as part of our Mathematics (Maths) Class 7 for Class 7 & RD Sharma Solutions: Exponents (Exercise 6.1) in Hindi for Mathematics (Maths) Class 7 course. Download more important topics related with notes, lectures and mock test series for Class 7 Exam by signing up for free. Class 7: Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7

Description

Full syllabus notes, lecture & questions for Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7 - Class 7 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 7 | Best notes, free PDF download

Information about RD Sharma Solutions: Exponents (Exercise 6.1)

In this doc you can find the meaning of RD Sharma Solutions: Exponents (Exercise 6.1) defined & explained in the simplest way possible. Besides explaining types of RD Sharma Solutions: Exponents (Exercise 6.1) theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Exponents (Exercise 6.1) tests, examples and also practice Class 7 tests

	Mathematics (Maths) Class 7 76 videos\|345 docs\|39 tests

Mathematics (Maths) Class 7

76 videos|345 docs|39 tests

Join Course for Free

Download as PDF

Explore Courses for Class 7 exam

Top Courses for Class 7

Explore Courses

Signup for Free!

Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.

Start learning for Free

10M+ students study on EduRev

mock tests for examination

Previous Year Questions with Solutions

Important questions

MCQs

Free

video lectures

Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7

Semester Notes

Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7

Exam

shortcuts and tricks

study material

Exponents (Exercise 6.1) RD Sharma Solutions | Mathematics (Maths) Class 7

pdf

Sample Paper

past year papers

Viva Questions

Extra Questions

practice quizzes

Objective type Questions

ppt

Summary

;

Additional Information about RD Sharma Solutions: Exponents (Exercise 6.1) for Class 7 Preparation

RD Sharma Solutions: Exponents (Exercise 6.1) Free PDF Download

The RD Sharma Solutions: Exponents (Exercise 6.1) is an invaluable resource that delves deep into the core of the Class 7 exam. These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective. With the help of these notes, you can grasp complex subjects quickly, revise important points easily, and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner, allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material, or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Exponents (Exercise 6.1) now and kickstart your journey towards success in the Class 7 exam.

Importance of RD Sharma Solutions: Exponents (Exercise 6.1)

The importance of RD Sharma Solutions: Exponents (Exercise 6.1) cannot be overstated, especially for Class 7 aspirants. This document holds the key to success in the Class 7 exam. It offers a detailed understanding of the concept, providing invaluable insights into the topic. By knowing the concepts well in advance, students can plan their preparation effectively. Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.

RD Sharma Solutions: Exponents (Exercise 6.1) Notes

RD Sharma Solutions: Exponents (Exercise 6.1) Notes offer in-depth insights into the specific topic to help you master it with ease. This comprehensive document covers all aspects related to RD Sharma Solutions: Exponents (Exercise 6.1). It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation. Practice papers and question papers enable you to assess your progress effectively. Additionally, the paper analysis provides valuable tips for tackling the exam strategically. Access to Toppers' notes gives you an edge in understanding complex concepts. Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Exponents (Exercise 6.1) Notes on EduRev are your ultimate resource for success.

RD Sharma Solutions: Exponents (Exercise 6.1) Class 7 Questions

The "RD Sharma Solutions: Exponents (Exercise 6.1) Class 7 Questions" guide is a valuable resource for all aspiring students preparing for the Class 7 exam. It focuses on providing a wide range of practice questions to help students gauge their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation. The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level. Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.

Study RD Sharma Solutions: Exponents (Exercise 6.1) on the App

Students of Class 7 can study RD Sharma Solutions: Exponents (Exercise 6.1) alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Exponents (Exercise 6.1), students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc. The EduRev App will make your learning easier as you can access it from anywhere you want. The content of RD Sharma Solutions: Exponents (Exercise 6.1) is prepared as per the latest Class 7 syllabus.

Education Revolution

Signup to see your scores go up within 7 days!

Access 1000+ FREE Docs, Videos and Tests

Continue with Google

Takes less than 10 seconds to signup