Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  RD Sharma Solutions: Integers (Exercise 1.3)

Integers (Exercise 1.3) RD Sharma Solutions | Mathematics (Maths) Class 7 PDF Download

Q.1. Find the value of 36 ÷ 6 + 3

Ans: On applying the BODMAS rule, we get:

36  ÷  6  + 3

= 6 + 3  (On performing division)

 = 9


Q.2. Find the value of 24 + 15 ÷ 3

Ans: On applying the BODMAS rule, we get:

24 + 15 ÷ 3

= 24 + 5  (On performing division)

= 29


Q.3. Find the value of 120 − 20 ÷ 4

Ans: On applying the DMAS rule, we get:

120 − 20 ÷ 4

= 120 − 5 (On performing division)

= 115


Q.4. Find the value of 32 − (3 × 5) + 4

Ans: On applying the DMAS rule, we get:

32 − ( 3 × 5 ) + 4

= 32 − 15 + 4    (On performing multiplication)

=  36 − 15         (On performing addition)

= 21                  (On performing subtraction)


Q.5. Find the value of 3 − (5 − 6 ÷ 3)

Ans: On applying the DMAS rule, we get:

3 − ( 5 − 6 ÷ 3)

= 3 − ( 5 − 2)       (On performing division)

= 3 − 3                (On performing subtraction)

= 0


Q.6. Find the value of 21 − 12 ÷ 3 × 2

Ans: On applying the DMAS rule, we get:

21 − 12 ÷ 3 × 2

= 21 − 4 × 2         (On performing division)

= 21 − 8               (On performing multiplication)

= 13                      (On performing subtraction)


Q.7. Find the value of 16 + 8 ÷ 4 − 2 × 3

Ans: On applying the DMAS rule, we get:

16 + 8 ÷ 4 − 2 × 3

= 16 + 2 − 6            (On performing division and multiplication)

= 18 − 6

= 12


Q.8. Find the value of 28 − 5 × 6 + 2

Ans: On applying the DMAS rule, we get:

28 − 5 × 6 + 2

= 28 − 30 + 2 (On performing multiplication)

= 30 − 30       (On performing addition)

= 0                 (On performing subtraction)


Q.9. Find the value of (−20) × (−1) + (−28) ÷ 7

Ans: On applying the DMAS rule, we get:

(− 20) × (− 1) + (−28) ÷ 7

=  20 + (− 4)   (On performing division and multiplication)

= 20 − 4 

= 16


Q.10. Find the value of (−2) + (−8) ÷ (−4)

Ans: On applying the DMAS rule, we get:

(− 2) + (− 8) ÷ (− 4)

= (− 2) + 2  (On performing division)

= 0             (On performing addition)


Q.11. Find the value of (−15) + 4 ÷ (5 − 3)

Ans: On applying the BODMAS rule, we get:

(− 15) + 4 ÷ (5 − 3)

= (− 15) + 4 ÷ 2  (On simplifying brackets)

= (− 15) + 2        (On performing division)

= − 13


Q.12. Find the value of (−40) × (−1) + (−28) ÷ 7

Ans: On applying the BODMAS rule, we get:

(− 40) × (− 1) + (− 28) ÷ 7

=  40 + (− 4)     (On performing division and multiplication)

=  36 


Q.13. Find the value of (−3) + (−8) ÷ (−4) −2 × (−2)

Ans: On applying the BODMAS rule, we get:

(− 3) + (− 8) ÷ (− 4) − 2 × (− 2)

=  (− 3) + 2 + 4                (On performing division and multiplication)

= (− 3) + 6                       (On performing addition)

= 3                                  (On performing subtraction)


Q.14. Find the value of (−3) × (−4) ÷ (−2) + (−1).

Ans: On applying the BODMAS rule, we get:

(−3) × (−4) ÷ (−2) + (−1)

= (−3) × 2 + (−1)                    (On performing division)

=  −6 − 1                                (On performing multiplication)

= −7                                       (On performing addition)

The document Integers (Exercise 1.3) RD Sharma Solutions | Mathematics (Maths) Class 7 is a part of the Class 7 Course Mathematics (Maths) Class 7.
All you need of Class 7 at this link: Class 7
76 videos|345 docs|39 tests

Top Courses for Class 7

FAQs on Integers (Exercise 1.3) RD Sharma Solutions - Mathematics (Maths) Class 7

1. What are integers in mathematics?
Ans. Integers are a set of numbers that include positive numbers, negative numbers, and zero. They do not include fractions or decimals. In simpler terms, integers are whole numbers, both positive and negative, including zero.
2. How are positive and negative integers represented on a number line?
Ans. Positive integers are represented to the right of zero on a number line, while negative integers are represented to the left of zero. The distance from zero to any positive integer is the same as the distance from zero to its corresponding negative integer.
3. How do you add two integers with different signs?
Ans. When adding two integers with different signs, subtract the smaller absolute value from the larger absolute value and assign the sign of the number with the larger absolute value. For example, to add -5 and 8, we subtract 5 from 8 and assign the negative sign to the result, giving us -13.
4. How do you subtract integers?
Ans. To subtract integers, we add the opposite. This means that to subtract a number, we add its opposite. For example, to subtract 7 from -3, we add -7 to -3, which gives us -10.
5. How do you multiply and divide integers?
Ans. When multiplying integers, if the signs of the two numbers are the same (both positive or both negative), the product is positive. If the signs are different, the product is negative. When dividing integers, if the signs of the two numbers are the same, the quotient is positive. If the signs are different, the quotient is negative.
76 videos|345 docs|39 tests
Download as PDF
Explore Courses for Class 7 exam

Top Courses for Class 7

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

ppt

,

Sample Paper

,

MCQs

,

Summary

,

study material

,

Integers (Exercise 1.3) RD Sharma Solutions | Mathematics (Maths) Class 7

,

pdf

,

past year papers

,

practice quizzes

,

Previous Year Questions with Solutions

,

Integers (Exercise 1.3) RD Sharma Solutions | Mathematics (Maths) Class 7

,

Objective type Questions

,

Free

,

Exam

,

Integers (Exercise 1.3) RD Sharma Solutions | Mathematics (Maths) Class 7

,

Semester Notes

,

Extra Questions

,

video lectures

,

mock tests for examination

,

shortcuts and tricks

,

Important questions

,

Viva Questions

;