Class 6 Exam > Class 6 Notes > Mathematics (Maths) Class 6 > RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2)
Ratio, Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1 Exercise 9.2 page: 9.9 1. Which ratio is larger in the following pairs? (i) 3: 4 or 9: 16 (ii) 15: 16 or 24: 25 (iii) 4: 7 or 5: 8 (iv) 9: 20 or 8: 13 (v) 1: 2 or 13: 27 Solution: (i) 3: 4 or 9: 16 It can be written as 3: 4 = 3/4 and 9: 16 = 9/16 LCM of 4 and 16 is 16 Multiplying both numerator and denominator of the term ¾ by 4 to make the denominator 16 3/4 = (3/4) × (4/4) = 12/16 and 9/16 We know that 12 > 9 So we get 12/16 > 9/16 We can write it as 3/4 > 9/16 Hence, 3: 4 > 9: 16. (ii) 15: 16 or 24: 25 It can be written as 15: 16 = 15/16 and 24: 25 = 24/25 LCM of 16 and 25 is 400 Multiplying both the terms by relevant numbers to make denominator as 400 15/16 = (15/16) × (25/25) = 375/400 and 24/25 = (24/25) × (16/16) = 384/400 We know that 384 > 375 So we get 384/400 > 375/400 We can write it as 24/25 > 15/16 Hence, 24: 25 > 15: 16. (iii) 4: 7 or 5: 8 It can be written as 4: 7 = 4/7 and 5: 8 = 5/8 LCM of 7 and 8 is 56 Multiplying both the terms by relevant numbers to make denominator as 56 4/7 = (4/7) × (8/8) = 32/56 and 5/8 = (5/8) × (7/7) = 35/56 We know that 35 > 32 So we get 35/56 > 32/56 We can write it as 5/8 > 4/7 Hence, 5: 8 > 4: 7. (iv) 9: 20 or 8: 13 It can be written as 9: 20 = 9/20 and 8: 13 = 8/13 Page 2 Exercise 9.2 page: 9.9 1. Which ratio is larger in the following pairs? (i) 3: 4 or 9: 16 (ii) 15: 16 or 24: 25 (iii) 4: 7 or 5: 8 (iv) 9: 20 or 8: 13 (v) 1: 2 or 13: 27 Solution: (i) 3: 4 or 9: 16 It can be written as 3: 4 = 3/4 and 9: 16 = 9/16 LCM of 4 and 16 is 16 Multiplying both numerator and denominator of the term ¾ by 4 to make the denominator 16 3/4 = (3/4) × (4/4) = 12/16 and 9/16 We know that 12 > 9 So we get 12/16 > 9/16 We can write it as 3/4 > 9/16 Hence, 3: 4 > 9: 16. (ii) 15: 16 or 24: 25 It can be written as 15: 16 = 15/16 and 24: 25 = 24/25 LCM of 16 and 25 is 400 Multiplying both the terms by relevant numbers to make denominator as 400 15/16 = (15/16) × (25/25) = 375/400 and 24/25 = (24/25) × (16/16) = 384/400 We know that 384 > 375 So we get 384/400 > 375/400 We can write it as 24/25 > 15/16 Hence, 24: 25 > 15: 16. (iii) 4: 7 or 5: 8 It can be written as 4: 7 = 4/7 and 5: 8 = 5/8 LCM of 7 and 8 is 56 Multiplying both the terms by relevant numbers to make denominator as 56 4/7 = (4/7) × (8/8) = 32/56 and 5/8 = (5/8) × (7/7) = 35/56 We know that 35 > 32 So we get 35/56 > 32/56 We can write it as 5/8 > 4/7 Hence, 5: 8 > 4: 7. (iv) 9: 20 or 8: 13 It can be written as 9: 20 = 9/20 and 8: 13 = 8/13 LCM of 20 and 13 is 260 Multiplying both the terms by relevant numbers to make denominator as 260 9/20 = (9/20) × (13/13) = 117/260 and 8/13 = (8/13) × (20/20) = 160/260 We know that 160 > 117 So we get 160/260 > 117/260 We can write it as 8/13 > 9/20 Hence, 8: 13 > 9: 20. (v) 1: 2 or 13: 27 It can be written as 1: 2 = 1/2 and 13: 27 = 13/27 LCM of 2 and 27 is 54 Multiplying both the terms by relevant numbers to make denominator as 54 1/2 = (1/2) × (27/27) = 27/54 and 13/27 = (13/27) × (2/2) = 26/54 We know that 27 > 26 So we get 27/54 > 26/54 We can write it as 1/2 > 13/27 Hence, 1: 2 > 13: 27. 2. Give two equivalent ratios of 6: 8. Solution: The given ratio = 6: 8 It can be written as = 6/8 Dividing the fraction by 2 we get 6/8 = (6/8) ÷ (2/2) = 3/4 Hence, 3: 4 is an equivalent ratio of 6: 8 Multiply the fraction by 2 we get 6/8 = (6/8) × (2/2) = 12/16 Hence, 12: 16 is an equivalent ratio of 6: 8 So, 3: 4 and 12: 16 are the equivalent ratios of 6: 8. 3. Fill in the following blanks: 12/20 = ?/5 = 9/ ? Solution: It is given that 12/20 = ?/5 = 9/ ? We know that LCM of 20 and 5 is 20 It can be written as 20/4 = 5 Dividing the fraction by 4 12/20 = (12/20) × (4/4) = 3/5 So the first number is 3 and the ratio is 3/5. In the same way, Page 3 Exercise 9.2 page: 9.9 1. Which ratio is larger in the following pairs? (i) 3: 4 or 9: 16 (ii) 15: 16 or 24: 25 (iii) 4: 7 or 5: 8 (iv) 9: 20 or 8: 13 (v) 1: 2 or 13: 27 Solution: (i) 3: 4 or 9: 16 It can be written as 3: 4 = 3/4 and 9: 16 = 9/16 LCM of 4 and 16 is 16 Multiplying both numerator and denominator of the term ¾ by 4 to make the denominator 16 3/4 = (3/4) × (4/4) = 12/16 and 9/16 We know that 12 > 9 So we get 12/16 > 9/16 We can write it as 3/4 > 9/16 Hence, 3: 4 > 9: 16. (ii) 15: 16 or 24: 25 It can be written as 15: 16 = 15/16 and 24: 25 = 24/25 LCM of 16 and 25 is 400 Multiplying both the terms by relevant numbers to make denominator as 400 15/16 = (15/16) × (25/25) = 375/400 and 24/25 = (24/25) × (16/16) = 384/400 We know that 384 > 375 So we get 384/400 > 375/400 We can write it as 24/25 > 15/16 Hence, 24: 25 > 15: 16. (iii) 4: 7 or 5: 8 It can be written as 4: 7 = 4/7 and 5: 8 = 5/8 LCM of 7 and 8 is 56 Multiplying both the terms by relevant numbers to make denominator as 56 4/7 = (4/7) × (8/8) = 32/56 and 5/8 = (5/8) × (7/7) = 35/56 We know that 35 > 32 So we get 35/56 > 32/56 We can write it as 5/8 > 4/7 Hence, 5: 8 > 4: 7. (iv) 9: 20 or 8: 13 It can be written as 9: 20 = 9/20 and 8: 13 = 8/13 LCM of 20 and 13 is 260 Multiplying both the terms by relevant numbers to make denominator as 260 9/20 = (9/20) × (13/13) = 117/260 and 8/13 = (8/13) × (20/20) = 160/260 We know that 160 > 117 So we get 160/260 > 117/260 We can write it as 8/13 > 9/20 Hence, 8: 13 > 9: 20. (v) 1: 2 or 13: 27 It can be written as 1: 2 = 1/2 and 13: 27 = 13/27 LCM of 2 and 27 is 54 Multiplying both the terms by relevant numbers to make denominator as 54 1/2 = (1/2) × (27/27) = 27/54 and 13/27 = (13/27) × (2/2) = 26/54 We know that 27 > 26 So we get 27/54 > 26/54 We can write it as 1/2 > 13/27 Hence, 1: 2 > 13: 27. 2. Give two equivalent ratios of 6: 8. Solution: The given ratio = 6: 8 It can be written as = 6/8 Dividing the fraction by 2 we get 6/8 = (6/8) ÷ (2/2) = 3/4 Hence, 3: 4 is an equivalent ratio of 6: 8 Multiply the fraction by 2 we get 6/8 = (6/8) × (2/2) = 12/16 Hence, 12: 16 is an equivalent ratio of 6: 8 So, 3: 4 and 12: 16 are the equivalent ratios of 6: 8. 3. Fill in the following blanks: 12/20 = ?/5 = 9/ ? Solution: It is given that 12/20 = ?/5 = 9/ ? We know that LCM of 20 and 5 is 20 It can be written as 20/4 = 5 Dividing the fraction by 4 12/20 = (12/20) × (4/4) = 3/5 So the first number is 3 and the ratio is 3/5. In the same way, Consider 2/3 + 3/5 = 9/ ? We know that 9/3 = 3 Multiply the fraction by 3 3/5 = (3/5) × (3/3) = 9/15 So the second number is 15 and the ratio is 9/15.Read More
|
94 videos|347 docs|54 tests
|
Related Exams
About this Document
|
4.91/5 Rating |
|
Nov 23, 2024 Last updated |
Document Description: RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) for Class 6 2024 is part of Mathematics (Maths) Class 6 preparation.
The notes and questions for RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) have been prepared according to the Class 6 exam syllabus. Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) covers topics
like and RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Example, for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2).
Introduction of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) in English is available as part of our Mathematics (Maths) Class 6
for Class 6 & RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) in Hindi for Mathematics (Maths) Class 6 course.
Download more important topics related with notes, lectures and mock test series for Class 6
Exam by signing up for free. Class 6: Ratio, Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6
Description
Full syllabus notes, lecture & questions for Ratio, Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6 - Class 6 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 6 | Best notes, free PDF download
Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2)
In this doc you can find the meaning of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) defined & explained in the simplest way possible. Besides explaining types of
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) tests, examples and also practice Class 6
tests
|
Explore Courses for Class 6 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Summary
,Ratio
,Objective type Questions
,mock tests for examination
,Extra Questions
,Free
,Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6
,Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6
,shortcuts and tricks
,study material
,Semester Notes
,Viva Questions
,video lectures
,Exam
,practice quizzes
,ppt
,Previous Year Questions with Solutions
,Proportion & Unitary Method (Exercise 9.2) RD Sharma Solutions | Mathematics (Maths) Class 6
,Ratio
,Ratio
,Sample Paper
,MCQs
,Important questions
,past year papers
,
Additional Information about RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) for Class 6 Preparation
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Free PDF Download
The RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) is an invaluable resource that delves deep into the core of the Class 6 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) now and kickstart your journey towards success in the Class 6 exam.
Importance of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2)
The importance of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) cannot be overstated, especially for Class 6 aspirants.
This document holds the key to success in the Class 6 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Notes
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2).
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Notes on EduRev are your ultimate resource for success.
RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Class 6 Questions
The "RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) Class 6 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 6 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) on the App
Students of Class 6 can study RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2),
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RD Sharma Solutions: Ratio, Proportion & Unitary Method (Exercise 9.2) is prepared as per the latest Class 6 syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup