Table of contents | |
Real Numbers | |
Classification of Real Numbers | |
Fundamental Theorem of Arithmetic | |
HCF and LCM by Prime Factorisation Method | |
Revisiting Irrational Numbers |
Real numbers are all the numbers that can be found on the number line. This includes both rational numbers (like 7, -3, 0.5, and 4/3) and irrational numbers (like √2) . They encompass integers, fractions, and decimals, representing a continuous, unbroken set of values.
Rational numbers such as integers (-2, 0, 1), fractions (1/2, 2.5) and irrational numbers such as √3, π(22/7), etc., are all real numbers.
To understand the fundamental theorem of Arithmetic, first, it is important to know what are composite numbers and prime numbers.
Composite Numbers are those numbers that have at least one factor other than one and the number itself.
Consider a number, 10. Now, the factors of 10 are 1, 2, 5 and 10. So it is a composite number.
Prime Numbers are those numbers that have exactly two factors: 1 and the number itself.
Let us take one more number 23. Now, the factors of 23 are 1 and 23. That means it has two factors 1 and the number itself, which is called a prime number.
Prime and Composite Numbers
Theorem: Fundamental Theorem of Arithmetic states that every composite number can be expressed as a product of primes, and this factorization is unique, apart from the order in which the prime factors occur.
Any composite number can be written as a product of primes in one way only as long as we are not particular about the order in which the primes occur.
Let us consider an example here: we will use a tree diagram to show the factors of 270.
270 = 2 x 33 x 5
Here, in the prime factorization of 270, the prime numbers appearing in both cases are the same, only the order in which they appear is different.
Therefore, the prime factorization of 270 is unique except for the order in which the primes occur.
Example 1: Check whether 15n can end with the digit zero for any natural number n.
Sol:
Example 2: Explain, why (7 × 6 × 5 × 4 × 3 × 2 × 1) + 5 and (3 × 5 × 13 × 46) + 23 is a composite number?
Sol:
For any two positive integers a and b,
HCF (a, b) × LCM (a, b) = a × b
Example 3: Find the LCM and HCF of 120 and 144 by the fundamental arithmetic theorem.
Sol:
120 = 23 × 3 × 5
144 = 24 × 32
Now, HCF is the product of the smallest power of each common prime factor in the numbers.
HCF (120, 144) = 23 × 3 = 8 × 3 = 24
LCM is the product of the greatest power of each prime factor involved in the numbers.
LCM (120,144) = 24 × 32 × 5 = 16 × 9 × 5 = 720
Example 4: If two positive integers p and q can be expressed as p = ab2 and q = a3b, where a, b are prime numbers, find the LCM (p, q).
Sol:
Given: p = ab2 and q = a3b
LCM is the product of the greatest power of each prime factor involved in the numbers.
LCM (p, q) = a3 × b2 = a3b2
Example 5: Write the HCF and LCM of the smallest odd composite number and the smallest odd prime number.
Sol:
The smallest odd composite number is 9, and the smallest odd prime number is 3.
9 = 32
3 = 31
Now, the smallest power of the common prime factor is 31.
HCF (9, 3) = 3
The greatest power of the common prime factor is 32.
LCM (9, 3) = 32 = 9
Example 6: If HCF (253,440) = 11 and LCM (253,440)= 253 × R. Find the value of R.
Sol:
We know that,
HCF (a, b) × LCM (a, b) = a × b
∴ HCF (253, 440) × LCM (253, 440) = 253 × 440
11 × 253 × R = 253 × 440
R = 253 x 440 / 253 x 11
R = 40
Example 7: Ravi and Shikha drive around a circular sports field. Ravi takes 16 min to complete one round, while Shikha completes the round in 20 min. If both start at the same point, at the same time, and go in the same direction, then how much time will they meet at the starting point?
Sol:
Time taken by Ravi to drive one round of the circular field = 16 min. Time taken by Shikha to drive one round of the circular field =20 min.
The time after which they will again meet at the starting point will be equal to the LCM of 16 min and 20 min.
16 = 24
20 = 22 × 5
LCM(16, 20) = 24 × 5 = 16 × 5 = 80
Therefore, Ravi and Shikha will meet again at the starting point after 80 min.
Irrational numbers are those numbers that cannot be written in the form p/q, where p and q are integers and q ≠0. E.g.,√2, √3, √15
The square roots of all the numbers do not give an irrational number.
For example, √2 is an irrational number, but √4 = 2, which is rational.
Therefore, the square roots of all prime numbers are irrational.
If p is a prime number, then √p is an irrational number.
Theorem : If a prime number p divides a2, then p divides a, where a is a positive integer.
Theorem: Prove that √2 is an irrational number.
Sol:
Example 8: Show that 3√2 is an irrational number.
Sol:
Example 9: Show that 5 − √3 is irrational.
Sol:
126 videos|457 docs|75 tests
|
1. What are the different classifications of real numbers? |
2. What is the Fundamental Theorem of Arithmetic? |
3. How can we find the HCF and LCM using the Prime Factorisation Method? |
4. Can you explain irrational numbers with examples? |
5. Why is understanding real numbers important in mathematics? |
|
Explore Courses for Class 10 exam
|