JEE Exam  >  JEE Notes  >  Chemistry for JEE Main & Advanced  >  Redox Titrations

Redox Titrations | Chemistry for JEE Main & Advanced PDF Download

Redox Titrations

Titration is a method used to figure out how strong or concentrated an unknown liquid is by slowly adding a known liquid strength to it.

Redox titrations involve the use of oxidizing and reducing agents to determine the concentration of a substance in a solution. The choice of reagents defines the type of redox titration. Redox Titrations | Chemistry for JEE Main & AdvancedRedox Titration Setup

Some Common Titration Methods


1. Dichrometry:

  • Potassium dichromate (K2Cr2O7) is the oxidizing agent.
  • Redox indicator (e.g., barium diphenylamine sulphonate) is employed to indicate the titration endpoint.
  • Example: Titration of iron(II) chloride with potassium dichromate.

6 FeCl2(aq) + K2Cr2O7(aq) + 14 HCl(aq)  ⟶ 6 FeCl3(aq) + 2 CrCl3(aq) + 2 KCl(aq) + 7 H2O(l)  

2. Permanganometry:

  • Potassium permanganate (KMnO4) acts as both the oxidizing agent and indicator.
  • No additional indicator is needed.
  • Example: Titration of iron(III) with potassium permanganate using phosphoric acid to mask interfering color.

3. Iodimetric Titrations:

  • Iodine (I2) is the oxidizing agent used to titrate reducing agents.
  • Typically performed in neutral or slightly basic/acidic solutions.
  • Example:  The estimation of sodium bisulphite 

Redox Titrations | Chemistry for JEE Main & AdvancedEstimation of Sodium Bisulphite

4. Iodometric Titrations:

  • Iodide ion (I-) acts as a weak reducing agent.
  • Different from iodimetric titrations which use iodine as the oxidizing agent.

Redox Titrations | Chemistry for JEE Main & AdvancedExample of Iodometric Titration

5. Bromatometry:

  • Potassium bromate (KBrO3)  serves as the oxidizing agent.
  • Used in titrations to determine concentrations.

Question for Redox Titrations
Try yourself:Which of the following is used as both the oxidizing agent and indicator in a redox titration?
View Solution

Redox Titration Experiment

Ever wondered how scientists test things in the lab? Let's take an example where they figure out how much hydrogen peroxide (H2O2) is in a store-bought bottle labeled 3%. They use a special solution called KMnO4 to do this. Here's how it works:

1. Weigh an empty flask with a precise balance.

2. Use a dropper to add 1.0 mL of the store-bought H2O2 into the flask and note the weight of the added liquid.

3. Pour 10mL of 3M H2SO4 and 50mL of water into the flask.

4. Load a tube with 50mL of a known solution (KMnO4) and write down how much is in the tube.

5. Place a white paper under the flask and slowly add the KMnO4 solution until the liquid in the flask changes color.

6. Note the amount of KMnO4 solution used by checking the difference between the initial and final levels in the tube.

7. Now, we can figure out the actual percentage of H2Oin the store-bought bottle using some calculations.

In simpler terms, you're basically mixing stuff in a flask, adding a colored liquid until the mix changes color, and then doing some math to find out what's in the store-bought H2O2.

Solved Examples of Redox Titrations

Q. In a titration of a 25.0 mL solution of Fe2+ with MnO4-, 16.7 mL of the 0.0152 M MnO4- was used. Find the concentration of Fe2+ 

Solution.

Step 1: Create a simple version of the equation that shows only the essential elements reacting. 

Redox Titrations | Chemistry for JEE Main & Advanced

Step 2: Figure out how many moles of MnO4- were involved in the reaction.

Redox Titrations | Chemistry for JEE Main & Advanced

Step 3. Find the concentration of Fe2+ in the sample.

Redox Titrations | Chemistry for JEE Main & Advanced

Q. Refer to the reactions below to observe how thiosulphate reacts differently with respect to iodine and bromine

2 S2O32– + I2 → S4O62– + 2I

S2O32– + 2Br2 + 5H2O → 2SO42– + 2Br + 10 H+

Select the statement that justifies the dual behavior of thiosulphate according to the above reactions.

  1. Iodine is a stronger oxidant than Bromine.
  2. Bromine is a stronger oxidant than iodine.
  3. Iodine undergoes reduction and bromine undergoes oxidation.
  4. Thiosulphate undergoes oxidation and reduction by bromine and iodine, respectively.

Solution. Option 2 is the correct answer. Bromine is a stronger oxidant than iodine. Bromine is a stronger oxidizing agent in comparison to iodine. Therefore, bromine oxidizes S of S2O32– to 2SO42– whereas I2 oxidizes S to S4O62–. Upon calculation, you will find that the oxidation number of S4O62– is less than 2SO42–.

The document Redox Titrations | Chemistry for JEE Main & Advanced is a part of the JEE Course Chemistry for JEE Main & Advanced.
All you need of JEE at this link: JEE
352 videos|596 docs|309 tests

Top Courses for JEE

352 videos|596 docs|309 tests
Download as PDF
Explore Courses for JEE exam

Top Courses for JEE

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Redox Titrations | Chemistry for JEE Main & Advanced

,

Free

,

Redox Titrations | Chemistry for JEE Main & Advanced

,

Semester Notes

,

Important questions

,

Viva Questions

,

study material

,

Objective type Questions

,

practice quizzes

,

MCQs

,

Exam

,

pdf

,

ppt

,

Sample Paper

,

Redox Titrations | Chemistry for JEE Main & Advanced

,

mock tests for examination

,

Previous Year Questions with Solutions

,

Extra Questions

,

video lectures

,

shortcuts and tricks

,

Summary

,

past year papers

;