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Right Circular Cylinder - Surface Areas and Volumes, CBSE, Class 10, Mathematics | Extra Documents, Videos & Tests for Class 10 PDF Download

RIGHT CIRCULAR CYLINDER
Solids like circular pillars, circular pipes, circular pencils, measuring jars, road rollers and gas cylinders, etc., are said to be in cylindrical shape.

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
In mathematical terms, a right circular cylinder is a solid generated by the revolution of a rectangle about its sides.

Let the rectangle ABCD revolve about its side AB, so as to describe a right circular cylinder as shown in the figure. You must have observed that the cross-sections of a right circular cylinder are circles congruent and parallel to each other.

Cylinders Not Right Circular
There are two cases when the cylinder is not a right circular cylinder.

Case-I : In the following figure, we see a cylinder, which is certainly circular, but is not at right angles to the base. So we cannot say it is a right circular cylinder.

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Case-II : In the following figure, we see a cylinder with a non-circular base as the base is not circular. So we cannot call it a right circular cylinder.

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

 

REMARK : Unless stated otherwise, here in this chapter the word cylinder would mean a right circular cylinder.
The following are definitions of some terms related to a right circular cylinder :

(i) The radius of any circular end is called the radius of the right circular cylinder.
Thus, in the above figure, AD as well as BC is a radius of the cylinder.

(ii) The line joining the centres of circular ends of the cylinder, is called the axis of the right circular cylinder.
In the above figure, the line AB is the axis of the cylinder. Clearly, the axis is perpendicular to the circular ends.

REMARK : If the line joining the centres of circular ends of a cylinder is not perpendicular to the circular ends, then the cylinder is not a right circular cylinder.

(iii) The length of the axis of the cylinder is called the height or length of the cylinder.

(iv) The curved surface joining the two bases of a right circular cylinder is called its lateral surface.

Formulae
For a right circular cylinder of radius = r units & height = h units, we have :

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

The above formulae are applicable to solid cylinders only.

Hollow Right Circular Cylinders

Solids like iron pipes, rubber tubes, etc., are in the shape of hollow cylinders.

A solid bounded by two coaxial cylinders of the same height and different radii is called a hollow cylinder.

  Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Formulae
For a hollow cylinder of height h and with external and internal radii R and r respectively, we have :

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

 Ex.6 2.2 cu dm of brass is to be drawn into a cylindrical wire of diameter 0.50 cm. Find the length of the wire.
 Sol. 
Volume of brass = 2.2 cu dm = (2.2 × 10 × 10 × 10) cm3 = 2200 cm3. Let the required length of wire be x cm.
Then, its volume  Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation = 11200 cm = 112 m.

Hence, the length of wire is 112 m.

 Ex.7 A well with 14 m diameter is dug 8 m deep. The earth taken out of it has been evenly spread all around it to a width of 21 m to form an embankment. Find the height of the embankment.

Sol. Volume of earth dug out from the well Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Area of the embankmentMathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, PreparationMathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Height of the embankment = Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation = 53.3 cm.

Ex.8 The difference between the outside and inside surface of a cylindrical metallic pipe 14 cm long is 44 cm2. If the pipe is made of 99 cu cm of metal, find the outer and inner radii of the pipe.

Sol. Let, external radius = R cm and internal radius = r cm.

Then, outside surface Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Inside surface Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, PreparationMathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
External volume Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Internal volume Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
On dividing (ii) by (i), we get:

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Solving (i) and (iii), we get, R = 2.5 and r = 2.
Hence, outer radius = 2.5 cm and inner radius = 2 cm.

Ex.9 A solid iron rectangular block of dimensions 4.4 m, 2.6 m and 1 m is cast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. Find the length of the pipe.

Sol. Volume of iron = (440 x 260 x 100) cm3.

Internal radius of the pipe = 30 cm.

External radius of the pipe = (30 + 5) cm = 35 cm.

Let the length of the pipe be h cm.

Volume of iron in the pipe = (External volume) - (Internal volume)
Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, PreparationMathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation
Hence, the length of the pipe is 112 m.

Ex.10 A cylindrical pipe has inner diameter of 7 cm and water flows through it at 192.5 litres per minute. Find the rate of flow in kilometres per hour.

Sol. Volume of water that flows per hour = (192.50 × 60) litres = (192.5 × 60 × 1000) cm3.

Inner radius of the pipe = 3.5 cm.

Let the length of column of water that flows in 1 hour be h cm.
Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

Mathematics, Class X, Questions and Answers, Q and A, Important, CBSE, NCERT, Board Exam, Preparation

The document Right Circular Cylinder - Surface Areas and Volumes, CBSE, Class 10, Mathematics | Extra Documents, Videos & Tests for Class 10 is a part of the Class 10 Course Extra Documents, Videos & Tests for Class 10.
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FAQs on Right Circular Cylinder - Surface Areas and Volumes, CBSE, Class 10, Mathematics - Extra Documents, Videos & Tests for Class 10

1. What is a right circular cylinder?
Ans. A right circular cylinder is a three-dimensional geometric shape that consists of two parallel circular bases and a curved surface connecting the bases. The axis passing through the centers of the bases is perpendicular to the bases, giving the cylinder its "right" shape.
2. How do you calculate the surface area of a right circular cylinder?
Ans. The surface area of a right circular cylinder can be calculated by adding the areas of the two circular bases and the curved surface area. The formula for surface area is: Surface Area = 2πr^2 + 2πrh where r is the radius of the base and h is the height of the cylinder.
3. How do you calculate the volume of a right circular cylinder?
Ans. The volume of a right circular cylinder can be calculated by multiplying the area of the base by the height of the cylinder. The formula for volume is: Volume = πr^2h where r is the radius of the base and h is the height of the cylinder.
4. How can I find the radius of a right circular cylinder if the surface area and height are given?
Ans. To find the radius of a right circular cylinder when the surface area and height are given, you can use the formula for surface area and rearrange it to solve for the radius. The formula is: Surface Area = 2πr^2 + 2πrh If you know the surface area and height, you can substitute these values into the equation and solve for r.
5. Can the surface area of a right circular cylinder be greater than its volume?
Ans. No, the surface area of a right circular cylinder cannot be greater than its volume. In fact, for any given height, the volume of the cylinder will always be greater than its surface area. This is because the volume is calculated by multiplying the area of the base by the height, while the surface area also takes into account the curved surface area. Therefore, the volume will always be a larger quantity compared to the surface area.
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