Perimeter and Area Class 7 Notes Maths Chapter 9

It refers to the length of the outline of the enclosed figure.

Area

It refers to the surface of the enclosed figure.

Area and Perimeter of Square

Square is a quadrilateral, with four equal sides.
Area = Side × Side
Perimeter = 4 × Side
Example: Find the area and perimeter of a square-shaped cardboard whose length is 5 cm.

Sol: Area of square = (side)²
= (5)²
= 25 cm²
Perimeter of square = 4 × side
= 4 × 5
= 20 cm

Area and Perimeter of Rectangle

The rectangle is a quadrilateral, with equal opposite sides.
Area = Length × Breadth
Perimeter = 2(Length + Breadth)

Example: What is the length of a rectangular field if its width is 20 ft and Area is 500 ft²?
Sol: Area of rectangular field = length × width
500 = l × 20
l = 500/20
l = 25 ft

Clear all your Class 7 doubts with EduRev Join for Free

Join for Free

Triangles as Parts of Rectangles

If we draw a diagonal of a rectangle then we get two equal sizes of triangles. So the area of these triangles will be half of the area of a rectangle.
The area of each triangle = 1/2 (Area of the rectangle)
Likewise, if we draw two diagonals of a square then we get four equal sizes of triangles .so the area of each triangle will be one-fourth of the area of the square.
The area of each triangle = 1/4 (Area of the square)
Example: What will be the area of each triangle if we draw two diagonals of a square with side 7 cm?
Sol: Area of square = 7 × 7
= 49 cm²
The area of each triangle = 1/4 (Area of the square)
= 1/4 × 49
= 12.25 cm²

Congruent Parts of Rectangles

Two parts of a rectangle are congruent to each other if the area of the first part is equal to the area of the second part.
Example
The area of each congruent part = 1/2 (Area of the rectangle)
= 1/2 (l × b) cm²
=1/2 (4 × 3) cm²
= 1/2 (12) cm²
= 6 cm²

Parallelogram

It is a simple quadrilateral with two pairs of parallel sides. Also denoted as ∥ gm
Area of parallelogram = base × height
 Or b × h (bh)
We can take any of the sides as the base of the parallelogram. And the perpendicular drawn on that side from the opposite vertex is the height of the parallelogram.
Example: Find the area of the figure given below:

Sol: Base of ∥ gm = 8 cm
Height of ∥ gm = 6 cm
Area of ∥ gm = b × h
= 8 × 6
= 48 cm

Area of Triangle

Triangle is a three-sided closed polygon. If we join two congruent triangles together then we get a parallelogram. So the area of the triangle will be half of the area of the parallelogram.
Area of Triangle = 1/2 (Area of ∥ gm)
= 1/2 (base × height)
Example: Find the area of the figure given below:

Sol: Area of triangle = 1/2 (base × height)
= 1/2 (12 × 5)
= 1/2 × 60
= 30 cm²

Download the notes Short Notes: Perimeter and Area

Download as PDF

Download as PDF

Circles

It is a round, closed shape.

The circumference of a Circle
The circumference of a circle refers to the distance around the circle.

• Radius: A straight line from the Circumference till the centre of the circle.
• Diameter: It refers to the line from one point of the Circumference to the other point of the Circumference.
• π (pi): It refers to the ratio of a circle's circumference to its diameter.

Circumference(c) = π × diameter
C = πd
= π × 2r
d = 2r

Example: What is the circumference of a circle of diameter 12 cm (Take π = 3.14)?
Sol: C = πd
C = 3.14 × 12
= 37.68 cm

Area of Circle

Area of the circle = (Half of the circumference) × radius
= πr²

Example: Find the area of a circle of radius 23 cm (use π = 3.14).
Sol: R = 23 cm
π = 3.14
Area of circle = 3.14 × 23²
= 1,661 cm²

Take a Practice Test Test yourself on topics from Class 7 exam

Practice Now

Practice Now

Conversion of Units

Sometimes we need to convert the unit of the given measurements to make it similar to the other given units.

Conversion of Units

Example 1: Convert 70 cm² in mm²
Sol:
1 cm = 10 mm
1 cm² = 10 × 10
1 cm² = 100 mm²
70 cm² = 700 mm²

Example: 2 Convert 3.5 ha in m²
Sol: 1 ha = 10000 m²
3.5 ha = 10000 × 3.5
ha = 35000 m²

Applications

We can use these concepts of area and perimeter of plane figures in our day to day life.

• If we have a rectangular field and want to calculate that how long will be the length of the fence required to cover that field, then we will use the perimeter.
• If a child has to decorate a circular card with the lace then he can calculate the length of the lace required by calculating the circumference of the card, etc.

Example: A rectangular park is 35 m long and 20 m wide. A path 1.5 m wide is constructed outside the park. Find the area of the path.
Sol: Area of rectangle ABCD – Area of rectangle STUV
AB = 35 + 2.5 + 2.5
= 40 m
AD = 20 + 2.5 + 2.5
= 25 m
Area of ABCD = 40 × 25
= 1000 m²
Area of STUV = 35 × 20
= 700 m²
Area of path = Area of rectangle ABCD – Area of rectangle STUV
= 1000 – 700
= 300 m²