Solutions of Sources of Energy (Page No- 158) - Physics By Lakhmir Singh, Class 10 Class 10 Notes | EduRev

Class 10 Physics Solutions By Lakhmir Singh & Manjit Kaur

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Class 10 : Solutions of Sources of Energy (Page No- 158) - Physics By Lakhmir Singh, Class 10 Class 10 Notes | EduRev

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Lakhmir Singh Physics Class 10 Solutions Page No:158

Question 27:
(a) Differentiate between nuclear fission and nuclear fusion.
(b) Which of the two, nuclear fission and nuclear fusion, is made use of :
(i) for the production of electricity ?
(ii) for making a hydrogen bomb ?
(c) Which produces more energy : nuclear fusion or nuclear fission ?
(d) Calculate the energy released in joules when 5 g of a material is completely converted into energy during a nuclear reaction.
(e) How much is this energy in MeV ? (Speed of light = 3 × 108 m/s)
Solution :

(a) 

 

Nuclear Fission

Nuclear Fusion

Natural occurrence of the process:

Fission reaction does not normally occur in nature.

Fusion occurs in stars, such as the sun

Byproducts of the reaction:

Fission produces many highly radioactive particles.

Few radioactive particles are produced by fusion reaction, but if a fission ' trigger' is used, radioactive particles will result from that.

Energy Ratios:

The energy released by fission is a million times greater than that released in chemical reactions: but lower than the energy released by nuclear fusion

The energy released by fusion is three to four times greater than the energy released by fission

Nuclear weapon:
One class of nuclear weapon is a fission bomb, also known as an atomic bomb or atom bomb.
One class of nuclear weapon is the hydrogen bomb, which uses a fission reaction to 'trigger' a fusion reaction
Energy requirement:
Takes little energy to split two atoms in a fission reaction
Extremely high energy is required to bring two or more protorts close enough that nuclear forces overcome their electrostatic repulsio.

 

(b) (i) Nuclear fission 
(ii) Nuclear fusion
(c) Nuclear fusion
(d)Mass.m = 5g = 0.005kg Speedof light, c=3x108m/s

We know that, E= mc2
E = 0.005x(3x108)2
E = 4.5x1014.J 

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