To determine the equivalent resistance of two resistors when connected in series - Lab Experiment Video Lecture - Class 10

to determine the equivalent resistance
of two resistors when connected in
series
a pirate is required dry cell with
terminals g6 ever-ready cell ten pieces
of insulated thick copper wire with bear
ends single key or one-way key ammeter
Walt meter real stat 10 ohm to known
resistors a and B of resistance 1 ohm
and 2 ohm respectively
sandpaper
procedure rub the bare ends of the
connecting wires with sandpaper so that
bright shiny copper metal is seen
remove the plug from the one-way key
K
connect tightly the key to the ammeter
rheostat of 10 ohm only known resistors
a and B of 1 ohm and 2 ohm respectively
in the series with the help of
connecting wires to the dry-cell
connect a voltmeter in parallel to the
combination of resistors a and B in
series make sure that positive and
negative terminals of voltmeter and
ammeter are connected properly
if there is a zero error in ammeter and
voltmeter corrected by adjusting the
adjustment screw insert the black key
and check that voltmeter and ammeter
show deflection
adjust the slider of the rheostat such
that the ammeter shows deflection of
0.15 ampere
read the value of potential difference
from the voltmeter
now adjust the slider of the rheostat
such that the ammeter shows a current of
0.20 ampere read and record the values
of potential difference and the current
repeat the experiment four times more
for the current value of 0.25 ampere
0.30 ampere
0.35 ampere
and 0.40 ampere in each case read and
record the potential difference
calculate average resistance of
resistors a and B mean resistance of
resistors a and B connected in series
equals total number of resistance in
each case upon number of cases
conclusion the main resistance of
resistors a and B is equal to the sum
total of the individual resistances of
the resistors a and B