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Unit Test (Solution): A Peek Beyond the Point | Mathematics (Ganita Prakash) Class 7 - New NCERT PDF Download

Maximum Marks: 30
Attempt all questions

  • Question numbers 1 to 5 carry 1 mark each.
  • Question numbers 6 to 8 carry 2 marks each.
  • Question numbers 9 to 11 carry 3 marks each.
  • Question numbers 12 to 13 carry  5 marks each.

Q1. What is the decimal form of 45 tenths? (1 Mark)
(a) 4.5
(b) 45.0
(c) 0.45
(d) 450
Ans: 
(a) 4.5

Q2. How many millimeters are in 1 centimeter? (1 Mark)
(a) 100
(b) 10
(c) 1000
(d) 1
Ans:
(b) 10

Q3. What is the place value of 7 in the number 12.374? (1 Mark)
(a) Tenths
(b) Hundredths
(c) Thousandths
(d) Units
Ans:
(b) Hundredths

Q4. State whether the following statement is True or False:  (1 Mark)
"Adding zeros to the right of a decimal number after the last digit changes its value."
Ans:
False

(Adding zeros after the last decimal digit does not change the value, e.g., 0.2 = 0.200)

Q5. Which number is closest to 2? (1 Mark)
(a) 1.9
(b) 2.1
(c) 2.01
(d) 2.11
Ans:
(c) 2.01
(2.01 is 0.01 away from 2, closest among the options)

Q6. Convert 345 mm to centimeters and express the answer in decimal form. (2 Mark)
Ans:
 1 cm = 10 mm
345 mm ÷ 10 = 34.5 cm

Q7. Add the decimals 8.56 and 3.27. (2 Mark)
Ans:
 8.56 + 3.27 = 11.83

Q8. Find the next three terms in the decimal sequence: 2.5, 3.0, 3.5, 4.0, ... (2 Mark)
Ans:
 Pattern: Each term increases by 0.5
4.0 + 0.5 = 4.5
4.5 + 0.5 = 5.0
5.0 + 0.5 = 5.5
= 4.5, 5.0, 5.5

Q9. Convert 567 grams to kilograms using decimals, and verify by converting back to grams. (3 Mark)
Ans:
 1 kg = 1000 g
567 g ÷ 1000 = 0.567 kg
Verification: 0.567 kg × 1000 = 567 g
= 0.567 kg

Q10. Subtract 7.89 from 12.34 and estimate the answer using whole number parts before calculating. (3 Mark)
Ans:
 Estimation:
Whole numbers: 12 and 7
12 − 7 = 5, answer between 5 and 6
Calculation:
12.34 − 7.89 = 4.45

Q11. Write the decimal forms of the following : 25 tens, 25 ones, 25 tenths, and 25 hundredths (3 Mark)
Ans:  

Place-value partValueDecimal form
25 tens25 × 10 = 250250.00
25 ones25 × 1  = 2525.00
25 tenths25 × 0.1 = 2.52.50
25 hundredths25 × 0.01 = 0.250.25

Add them up:
250+25+2.5+0.25=277.75
So the combined number is 277.75, where:

  • the 7 in the ones place and the 7 in the tenths place come from adding each column, and
  • the 5 in the hundredths place comes from the 0.25 part.

Q12. A shop sells cloth at ₹25.50 per meter. Calculate the cost of 3.2 meters of cloth. Then, convert 750 paise to rupees and determine if it is enough to pay for the cloth. (5 Mark)
Ans:
 Cost of cloth:
3.2 × 25.50 = 81.60
Convert paise to rupees:
1 rupee = 100 paise
750 paise ÷ 100 = 7.50 rupees
Comparison:
7.50 rupees is less than 81.60 rupees, so it is not enough.
Cost = ₹81.60, 750 paise = ₹7.50 (not enough)

Q13.  Answer the following (5 Mark)
(i) Pinto delivers 3.65 L, 4.15 L, and 4.1 L of milk to a dairy on the first three days. In 6 days, he supplies a total of 24.8 litres of milk. How much milk does he supply on the last three days? 
(ii) Indian Railways offers an optional travel-insurance scheme for passengers who book e-tickets. The premium is 60 paise per passenger. On one busy day, 1.25 lakh passengers choose this insurance. How much money (in rupees) does Indian Railways collect as the insurance premium that day?

Ans: 

(i)
Step 1: Milk supplied in the first three days:
3.65+4.15+4.1 = 11.9 L
Step 2: Total milk supplied in 6 days:  24.8 L
Step 3: Milk supplied in the last three days:
24.8−11.9=12.9 L
(ii) 
1 lakh = 100 000 passengers
1.25 lakh = 1.25 × 100 000 = 125 000 passengers
Premium per passenger = 60 paise = ₹0.60
Total premium collected
125000 × ₹0.60= ₹75000
Indian Railways collects ₹75,000 in insurance fees that day.

The document Unit Test (Solution): A Peek Beyond the Point | Mathematics (Ganita Prakash) Class 7 - New NCERT is a part of the Class 7 Course Mathematics (Ganita Prakash) Class 7 - New NCERT.
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FAQs on Unit Test (Solution): A Peek Beyond the Point - Mathematics (Ganita Prakash) Class 7 - New NCERT

1. What is the main purpose of the Point class in programming?
Ans. The main purpose of the Point class is to represent a point in a two-dimensional space, defined by its x and y coordinates. It allows for the creation of objects that can store these coordinates and provides methods to manipulate and interact with them.
2. How can I create an instance of the Point class?
Ans. To create an instance of the Point class, you typically use a constructor that initializes the x and y coordinates. For example, you might write something like `Point p = new Point(3, 4);` where 3 is the x-coordinate and 4 is the y-coordinate of the point.
3. What methods are commonly included in a Point class?
Ans. Common methods in a Point class include getters and setters for the x and y coordinates, a method to calculate the distance to another point, and a method to display the point's coordinates. Some implementations might also include methods for comparing points or checking if they are equal.
4. How do I calculate the distance between two points using the Point class?
Ans. To calculate the distance between two points, you can use the distance formula: distance = sqrt((x2 - x1)^2 + (y2 - y1)^2). In the Point class, you would typically create a method that takes another Point instance as a parameter and returns the distance calculated using this formula.
5. Can the Point class be extended for more complex geometrical shapes?
Ans. Yes, the Point class can be extended to create more complex geometrical shapes. For instance, you can create subclasses like Line, Triangle, or Rectangle that utilize the Point class for defining their vertices. This allows for more sophisticated geometrical operations and manipulations.
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