Class 9 Exam  >  Class 9 Notes  >  Mathematics (Maths) Class 9  >  Very Short Answer Type Questions: Linear Equations in Two Variables

Class 9 Maths Question Answers - Linear Equations in Two Variables

Question 1. Show that x = 1, y = 3 satisfy the linear equation 3x – 4y + 9 = 0.
Solution: We have 3x – 4y + 9 = 0
Putting x = 1, y = 3, we get
L.H.S. = 3(1) – 4(3) + 9 = 3 – 12 + 9
= 12 – 12 = 0 = R.H.S.
Since, L.H.S. = R.H.S.
∴ x = 1 and y = 3 satisfy the given linear equation.

Question 2. Write whether the following statements are True or False? Justify your answers.
(i) ax + by + c, where a, b and c are real numbers, is a linear equation in two variables. 

(ii) A linear equation 2x + 3y = 5 has a unique solution. 

(iii) All the points (2, 0), (–3, 0), (4, 2) and (0, 5) lie on the x-axis.

(iv) The line parallel to y-axis at a distance 4 units to the left of y-axis is given by the equation x = –4. 

(v) The graph of the equation y = mx + c passes through the origin.
Solution. 

(i) False. [Because ax + by + c = 0 is a linear equation in two variables if both ‘a‘ and ‘b’ are non-zero.]

(ii) False. [Because a linear equation in two variables has infinitely many solutions.]

(iii) False. [Because the points (2, 0) and (–3, 0) lie on the x-axis, (0, 5) lie on the y-axis whereas the point (4, 2) lies in the first quadrant.]

(iv) True.

(v) False. [Because the point (0, 0) i.e., x = 0 + y = 0 does not satisfy the equation]

Question 3. Write whether the following statement is True or False? Justify your answer.
The coordinates of points given in the table:

Class 9 Maths Question Answers - Linear Equations in Two Variables

Represent some of the solutions of the equation 2x + 2 = y.
Solution. True. [Since, on looking at the given coordinates, we observe that each y-coordinate is two units more than double the x-coordinate.]

Question 4. Look at the following graphical representation of an equation. Which of the points (0, 0) (0, 4) or (–1, 4) is a solution of the equation?

Class 9 Maths Question Answers - Linear Equations in Two Variables

Solution: Since, the point (0, 4) lies on the line.
Class 9 Maths Question Answers - Linear Equations in Two Variables  is a solution of the equation.
.

Question 5. Look at the following graphical representation of an equation. Which of the following is not its solution? 

Class 9 Maths Question Answers - Linear Equations in Two Variables

Solution: The point (6, 0) does not lie on the graph.
∴ The point (6, 0) is not the solution of the equation.

The document Class 9 Maths Question Answers - Linear Equations in Two Variables is a part of the Class 9 Course Mathematics (Maths) Class 9.
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FAQs on Class 9 Maths Question Answers - Linear Equations in Two Variables

1. What is a linear equation in two variables?
Ans. A linear equation in two variables is an equation that can be written in the form ax + by = c, where a, b, and c are constants and x and y are variables.
2. How many solutions can a linear equation in two variables have?
Ans. A linear equation in two variables can have three types of solutions - no solution, a unique solution, or infinitely many solutions.
3. How do you graph a linear equation in two variables?
Ans. To graph a linear equation in two variables, we can use the slope-intercept form (y = mx + b) or the intercepts method. In the slope-intercept form, we identify the slope (m) and y-intercept (b) to plot the line. In the intercepts method, we find the x-intercept and y-intercept to plot the line.
4. Can a linear equation have more than two variables?
Ans. No, a linear equation can only involve two variables. If there are more than two variables, it becomes a system of linear equations.
5. How can linear equations in two variables be used in real-life situations?
Ans. Linear equations in two variables can be used to model and solve various real-life problems. They can help in determining relationships between two variables, such as the cost and quantity of a product, distance and time, or temperature and pressure. By solving these equations, we can make predictions or solve practical problems.
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