Word Problem: Decimals | Mathematics for Class 4 PDF Download

Q1: Reena purchased a notebook worth ₹6.50 and a pen worth ₹3.25. How much did she spend in all?
Sol: Arrange the amounts in proper columns.
Add as ordinary numbers.
Place the decimal point to separate rupees from paise.Hence, Reena spent ₹9.75 in all.

Q2:  Rahul carried ₹8.75 to a shop. He bought a chocolate worth ₹2.50. How much money did he take back home?

Sol: Arrange the amounts in proper columns.
 Subtract as ordinary numbers.
Place the decimal point to separate rupees from paise.  Hence, the amount that Rahul took back home is ₹6.25.

Q3: Mary has ₹2. She spends ₹0.5 on a toy. How much money does she have left?
Sol: To find how much is left with Mary now, we subtract the amount she spent from the amount she had initially.
Initial amount of money Mary had = ₹2
Amount Mary spent on the toy = ₹0.5
Therefore the money left = Initial money - money spent = ₹2 - ₹0.5 = ₹1.5
Mary has ₹1.5 left after buying the toy.

Q4:  Maria and Vanessa are neighbors, and every week they go grocery shopping together. Last week Maria spent ₨ 45.75, exactly 3 times more than Vanessa spent. How much money did Vanessa spend?
Sol: If Maria spent 3 times more than Vanessa than the money that Vanessa spent is 3 times less. Let money spent by Vanessa be = ₨ x
=> 45.75 = 3x

Money spent by Vanessa = x =  ₨ 45.75 ÷ 3 = ₨ 15.25

Q5: Tim saves 10% of his weekly pocket money, which is ₹5. How much money does Tim save each week?
Sol: We need to calculate 10% of his weekly pocket money, which is ₹5.
To calculate 10% of a number, we divide the number by 10.
10% of ₹5 = (10/100) x ₹5 = ₹0.5
Therefore, Tim saves ₹0.5 each week.

Q6: A pizza is divided into 8 equal slices. If you eat 0.25 of the pizza, how many slices did you eat?
Sol:  To find out how many slices you ate, we need to multiply the fraction of the pizza you ate (0.25) by the total number of slices in the pizza (8).
Total slices you ate = Fraction x Total number of slices = 0.25 x 8 = 2
Therefore, you ate 2 slices of the pizza.

Q7: In a game, you score 0.3 points for each correct answer. If you answered 5 questions correctly, how many points did you score?
Sol: To find out how many points you scored, we need to multiply the number of correct answers (5) by the points awarded for each correct answer (0.3).
Total points = Number of correct questions x Score for each correct answer = 5 x 0.3 = 1.5
Therefore, you scored 1.5 points in the game.

Q8: James has a rectangular box. The length of the box is 25.78 cm and its width is 7.16 cm less than its length. What is the area of the rectangle?
Sol: The length is given which is 25.78 cm. The width is 7.16 cm less than its length.
First, we need to find out the width of the rectangular box.
Width of the box = 25.78 - 7.16 = 18.62 cm

We know that the area of the rectangle is length x width.
Area of the rectangular form = length x width = 25.78 x 18.62 = 480.0236 cm²

Hence, the final answer is 480.0236 cm²

Q9: Aaron scored 452.65 marks out of 600 in the final examination. How many marks did he lose?
Sol: To find out how many marks Aaron lost, we need to subtract his score from the total possible marks.
=> Total possible marks - Aaron's score = Marks lost
=> 600 - 452.65 = 147.35
Therefore, Aaron lost 147.35 marks in the final examination.

Q10: The price of a t-shirt was ₹250.45. John paid with ₹300. How much change did John get?

Sol: To find out how much change John received, we need to subtract the price of the t-shirt from the amount he paid.
=> Amount paid - Price of the t-shirt = Change
=> ₹300 - ₹250.45 = ₹49.55
Therefore, John received ₹49.55 in change.

Q11: Compare the numbers. Add: > or < or =
75.8 ____ 0.09
Sol:75.8 > 0.09

Q12: Kavita travelled 267.97km and Sheena travelled 862.73km using their own cars. Who travelled the most and by how much? 
Sol: The approximate distance covered by Kavita is 200km and Sheena is 800km. As the distance travelled by Sheena is the longest so we will subtract 267.97 from 862.73
Hence the required answer = 862.73  - 267.97 = 594.76

Q13: A pack of crayons costs ₹80.5. Jake gave the cashier ₹100. How much change did Jake receive?

Sol:  To find out how much change Jake received, we need to subtract the cost of the pack of crayons from the amount he paid.
According to question , Amount paid - Cost of the crayons = Change
₹100 - ₹80.5 = ₹19.5
Therefore, Jake received ₹19.5 in change.

Q14: Compare the numbers. Add: > or < or =
0.03 ____ 0.5
Sol: 0.03 < 0.5

Q15: In a well filled with water, 184.5 liters are removed followed by 128.75 liters and finally 84.5 liters. After these withdrawals, there are 160 liters in the well. How much water did the well originally have?
Sol: Let us assume the original concentration of water be = x litres

According to question => x - 184.4 - 128.75 - 84.5 = 160
=> x = 184.4 + 128.75 + 84.5 + 160
=> x = 557.75 litres

Q16: The cost of a book was ₹150.0, Sarah paid with a ₹200.0 note. How much change did Sarah receive?

Sol: To find out how much change Sarah received, we need to subtract the cost of the book from the amount she paid.
Amount paid - Cost of the book = Change
₹200.0 - ₹150.0 = ₹50.0
Therefore, Sarah received ₹50 in change.