Q1: If x/y + y/x = -1 and (xy, ≠ 0), the value of x3 – y3 is
(a) 1
(b) -1
(c) 0
(d) 2
Ans: (c)
x/y + y/x = -1
x2 + y2 = − xy
or
x2 + y2 + xy = 0
Now x3 – y3 = (x − y) (x2 + y2 + xy) = (x − y) × 0 = 0
Hence (c) is the correct answer
Q2: If p + q + r = 0 ,then the value of
(a) 1
(b) 3
(c) -1
(d) 0
Ans: (b)
Now we know that p3 + q3 + r3 − 3pqr = (p + q + r) (p2 + q2 + r2 − pq − qr − pr)
as p + q + r = 0
p3 + q3 + r3 − 3pqr = 0 or p3 + q3 + r3 = 3pqr
Now
Hence (b) is the correct answer.
Q3: The product of (x + a) (x + b) is
(a) x2 + (a + b)x + ab
(b) x2 - (a - b)x + ab
(c) x2 + (a - b)x + ab
(d) x2 + (a - b)x + ab
Ans: (a)
Q4: The value of (x + 2y + 2z)2 + (x - 2y - 2z)2 is
(a) 2x2 + 8y2 + 8z2
(b) 2x2 + 8y2 + 8z2 + 8xyz
(c) 2x2 +8y2 + 8z2 - 8yz
(d) 2x2 + 8y2 + 8z2 + 16yz
Ans: (d)
(d) 6
Ans: (a)
Q1: P(x) = x - 1 and g(x) =x2 - 2x + 1 . p(x) is a factor of g(x)
Ans: True, as g(1) = 0
Q2: The factor of 3x2 – x - 4 are (x + 1)(3x - 4)
Ans: True, we can get this by split method
Q3: Every linear polynomial has only one zero
Ans: True
Q4: Every real number is the zero’s of zero polynomial
Ans: True
Q5: A binomial may have degree 4
Ans: True, example x4 + 1
Q6: 0, 2 are the zeroes of x2- 2x
Ans: True
Q7: The degree of zero polynomial is not defined
Ans: True
Q1: Is 3x1/2 - 4x + 15 a polynomial of one variable?
Ans: No. it is not a polynomial
Q2: Is ∛x - √2x a polynomial
Ans: No. It is not a polynomial
Q3: What will be the degree of polynomials 30x5 - 15x2 + 40
Ans: Degree of Polynomial is 5
Q4: Is (y2)1/2 + 2√3 a polynomial of one variable?
Ans: Yes it is a polynomial of one variable
Q5: What will be the coefficient of x3 in 9x3 - 5x + 20.
Ans: Coefficient of x3 is 9
Q6: Show that x = 1 is a root of the polynomial 3x3 - 4x2 + 8x - 7
Ans: On putting x = 1
X = 1 is root of polynomial
3x3 - 4x2 + 8x - 7
3(1)3 - 4(1)2 + 8(1) - 7
3 - 4 + 8 - 7 = 0
X = 1 is root of polynomial
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