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Page 1
Exercise 11A
1. Find the SP when:
(i). CP = ? 950, gain = 6%
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + 6) /100) × 950}
= {(106 /100) × 950}
= 100700/100
= ?1007
(ii). CP = ? 9600, gain = 16 2/3 %
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + (50/3)) /100) × 9600}
= {((((300 + 50)/3)) /100) × 9600}
= {((350/3) /100) × 9600}
= {((350/3) × (1/100)) × 9600}
= {(350/300) × 9600}
= {(350/3) × 96}
= {350 × 32}
= ?11200
(iii). CP = ? 1540, loss = 4%
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - 4) /100) × 1540}
= {(96 /100) × 1540}
= 147840/100
= ?1478.40
(iv). CP = ? 8640, loss = 12 1/2 %
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - (25/2)) /100) × 8640}
= {(((200 - 25)/2)) /100) × 8640}
= {((175/2) /100) × 8640}
= {((175/2) × (1/100)) × 8640}
Page 2
Exercise 11A
1. Find the SP when:
(i). CP = ? 950, gain = 6%
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + 6) /100) × 950}
= {(106 /100) × 950}
= 100700/100
= ?1007
(ii). CP = ? 9600, gain = 16 2/3 %
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + (50/3)) /100) × 9600}
= {((((300 + 50)/3)) /100) × 9600}
= {((350/3) /100) × 9600}
= {((350/3) × (1/100)) × 9600}
= {(350/300) × 9600}
= {(350/3) × 96}
= {350 × 32}
= ?11200
(iii). CP = ? 1540, loss = 4%
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - 4) /100) × 1540}
= {(96 /100) × 1540}
= 147840/100
= ?1478.40
(iv). CP = ? 8640, loss = 12 1/2 %
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - (25/2)) /100) × 8640}
= {(((200 - 25)/2)) /100) × 8640}
= {((175/2) /100) × 8640}
= {((175/2) × (1/100)) × 8640}
= {(175/200) × 8640}
= {1512000/200}
= ?7560
2. Find the gain or loss percent when:
(i). CP = ? 2400 and SP = ? 2592
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (2592-2400)
= ? 192
Gain % = {(gain/CP) × 100}
= {(192/2400) × 100}
= {192/24}
= 8%
(ii). CP = ? 1650 and SP = ? 1452
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1650 - 1452)
= ? 198
Loss % = {(Loss/CP) × 100}
= {(198/1650) × 100}
= {19800/1650}
= 12%
(iii). CP = ? 12000 and SP = ? 12800
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (12800 - 12000)
= ? 800
Gain % = {(gain/CP) × 100}
= {(800/12000) × 100}
= {800/120}
= 6 2/3 %
= 6.66%
(iv). CP = ? 1800 and SP = ? 1611
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
Page 3
Exercise 11A
1. Find the SP when:
(i). CP = ? 950, gain = 6%
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + 6) /100) × 950}
= {(106 /100) × 950}
= 100700/100
= ?1007
(ii). CP = ? 9600, gain = 16 2/3 %
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + (50/3)) /100) × 9600}
= {((((300 + 50)/3)) /100) × 9600}
= {((350/3) /100) × 9600}
= {((350/3) × (1/100)) × 9600}
= {(350/300) × 9600}
= {(350/3) × 96}
= {350 × 32}
= ?11200
(iii). CP = ? 1540, loss = 4%
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - 4) /100) × 1540}
= {(96 /100) × 1540}
= 147840/100
= ?1478.40
(iv). CP = ? 8640, loss = 12 1/2 %
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - (25/2)) /100) × 8640}
= {(((200 - 25)/2)) /100) × 8640}
= {((175/2) /100) × 8640}
= {((175/2) × (1/100)) × 8640}
= {(175/200) × 8640}
= {1512000/200}
= ?7560
2. Find the gain or loss percent when:
(i). CP = ? 2400 and SP = ? 2592
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (2592-2400)
= ? 192
Gain % = {(gain/CP) × 100}
= {(192/2400) × 100}
= {192/24}
= 8%
(ii). CP = ? 1650 and SP = ? 1452
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1650 - 1452)
= ? 198
Loss % = {(Loss/CP) × 100}
= {(198/1650) × 100}
= {19800/1650}
= 12%
(iii). CP = ? 12000 and SP = ? 12800
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (12800 - 12000)
= ? 800
Gain % = {(gain/CP) × 100}
= {(800/12000) × 100}
= {800/120}
= 6 2/3 %
= 6.66%
(iv). CP = ? 1800 and SP = ? 1611
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1800 - 1611)
= ? 189
Loss % = {(Loss/CP) × 100}
= {(189/1800) × 100}
= {189/18}
= 10 1/2%
= 10.5%
3. Find the CP when:
(i). SP = ? 924, gain = 10%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + 10)) × 924}
= {(100/ 110) × 924}
= {92400/110}
= ? 840
(ii). SP = ? 1755, gain = 12 1/2 %
Solution:-
Gain = 12 1/2 = 25/2
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + (25/2))) × 1755}
= {(100/ ((200 + 25)/2)) × 1755}
= {(200/ 225) × 1755}
= {351000/225}
= ? 1560
(iii). SP = ? 8510, loss = 8%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 - loss %)) × SP}
= {(100/ (100 - 8)) × 8510}
= {(100/ 92) × 8510}
= {851000/92}
= ? 9250
(iv). SP = ? 5600, loss = 6 2/3 %
Solution:-
Loss = 6 2/3 = 20/3
By using the formula, we have:
Page 4
Exercise 11A
1. Find the SP when:
(i). CP = ? 950, gain = 6%
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + 6) /100) × 950}
= {(106 /100) × 950}
= 100700/100
= ?1007
(ii). CP = ? 9600, gain = 16 2/3 %
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + (50/3)) /100) × 9600}
= {((((300 + 50)/3)) /100) × 9600}
= {((350/3) /100) × 9600}
= {((350/3) × (1/100)) × 9600}
= {(350/300) × 9600}
= {(350/3) × 96}
= {350 × 32}
= ?11200
(iii). CP = ? 1540, loss = 4%
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - 4) /100) × 1540}
= {(96 /100) × 1540}
= 147840/100
= ?1478.40
(iv). CP = ? 8640, loss = 12 1/2 %
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - (25/2)) /100) × 8640}
= {(((200 - 25)/2)) /100) × 8640}
= {((175/2) /100) × 8640}
= {((175/2) × (1/100)) × 8640}
= {(175/200) × 8640}
= {1512000/200}
= ?7560
2. Find the gain or loss percent when:
(i). CP = ? 2400 and SP = ? 2592
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (2592-2400)
= ? 192
Gain % = {(gain/CP) × 100}
= {(192/2400) × 100}
= {192/24}
= 8%
(ii). CP = ? 1650 and SP = ? 1452
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1650 - 1452)
= ? 198
Loss % = {(Loss/CP) × 100}
= {(198/1650) × 100}
= {19800/1650}
= 12%
(iii). CP = ? 12000 and SP = ? 12800
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (12800 - 12000)
= ? 800
Gain % = {(gain/CP) × 100}
= {(800/12000) × 100}
= {800/120}
= 6 2/3 %
= 6.66%
(iv). CP = ? 1800 and SP = ? 1611
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1800 - 1611)
= ? 189
Loss % = {(Loss/CP) × 100}
= {(189/1800) × 100}
= {189/18}
= 10 1/2%
= 10.5%
3. Find the CP when:
(i). SP = ? 924, gain = 10%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + 10)) × 924}
= {(100/ 110) × 924}
= {92400/110}
= ? 840
(ii). SP = ? 1755, gain = 12 1/2 %
Solution:-
Gain = 12 1/2 = 25/2
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + (25/2))) × 1755}
= {(100/ ((200 + 25)/2)) × 1755}
= {(200/ 225) × 1755}
= {351000/225}
= ? 1560
(iii). SP = ? 8510, loss = 8%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 - loss %)) × SP}
= {(100/ (100 - 8)) × 8510}
= {(100/ 92) × 8510}
= {851000/92}
= ? 9250
(iv). SP = ? 5600, loss = 6 2/3 %
Solution:-
Loss = 6 2/3 = 20/3
By using the formula, we have:
CP = ? {(100/ (100 – loss %)) × SP}
= {(100/ (100 - (20/3))) × 5600}
= {(100/ ((300 - 20)/3)) × 5600}
= {(300/ 280) × 5600}
= {168000/28}
= ? 6000
4. Sudhir bought an almirah for ? 13600 and spent ? 400 on its transportation. He sold it for ? 16800.
Find his gain percent.
Solution:-
From the question,
Sudhir bought an almirah for = ? 13600 = cost price
Transportation cost = ? 400
The total cost price of almirah = ? (13600 + 400)
= ? 14000
He sold it for = ? 16800 = Selling price
By comparing SP and CP = SP > CP, so there is a gain
Gain = SP – CP
= 16800 – 14000
= ? 2800
Gain % = {(gain/CP) × 100}
= {(2800/14000) × 100}
= {2800/140}
= 20%
5. Ravi purchased an old house for ?765000 and spent ?115000 on its repairs. Then, he sold it a gain
of 5%. How much did he get?
Solution:-
From the question,
Ravi purchased an old house for = ? 765000 = Cost price
He spent on its repairs = ? 115000
Total cost price of old house = (765000 + 115000)
= ? 880000
Then, he sold it at a gain of 5%
SP = {((100 + gain %) /100) × CP}
= {((100 + 5) /100) × 880000}
= {(105 /100) × 880000}
= 105 × 8800
= ? 924000
?the selling price of the house is ? 924000
6. A vendor buys lemons at ?25 per dozen and sells them at the rate of 5 for ? 12. Find his gain or
loss percent.
Page 5
Exercise 11A
1. Find the SP when:
(i). CP = ? 950, gain = 6%
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + 6) /100) × 950}
= {(106 /100) × 950}
= 100700/100
= ?1007
(ii). CP = ? 9600, gain = 16 2/3 %
Solution:-
We have,
SP = {((100 + gain %) /100) × CP}
= {((100 + (50/3)) /100) × 9600}
= {((((300 + 50)/3)) /100) × 9600}
= {((350/3) /100) × 9600}
= {((350/3) × (1/100)) × 9600}
= {(350/300) × 9600}
= {(350/3) × 96}
= {350 × 32}
= ?11200
(iii). CP = ? 1540, loss = 4%
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - 4) /100) × 1540}
= {(96 /100) × 1540}
= 147840/100
= ?1478.40
(iv). CP = ? 8640, loss = 12 1/2 %
Solution:-
We have,
SP = {((100 - loss %) /100) × CP}
= {((100 - (25/2)) /100) × 8640}
= {(((200 - 25)/2)) /100) × 8640}
= {((175/2) /100) × 8640}
= {((175/2) × (1/100)) × 8640}
= {(175/200) × 8640}
= {1512000/200}
= ?7560
2. Find the gain or loss percent when:
(i). CP = ? 2400 and SP = ? 2592
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (2592-2400)
= ? 192
Gain % = {(gain/CP) × 100}
= {(192/2400) × 100}
= {192/24}
= 8%
(ii). CP = ? 1650 and SP = ? 1452
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1650 - 1452)
= ? 198
Loss % = {(Loss/CP) × 100}
= {(198/1650) × 100}
= {19800/1650}
= 12%
(iii). CP = ? 12000 and SP = ? 12800
Solution:-
Since (SP) > (CP), so there is a gain
Gain = (SP) – (CP)
= ? (12800 - 12000)
= ? 800
Gain % = {(gain/CP) × 100}
= {(800/12000) × 100}
= {800/120}
= 6 2/3 %
= 6.66%
(iv). CP = ? 1800 and SP = ? 1611
Solution:-
Since (SP) < (CP), so there is a loss
Loss = (CP) – (SP)
= ? (1800 - 1611)
= ? 189
Loss % = {(Loss/CP) × 100}
= {(189/1800) × 100}
= {189/18}
= 10 1/2%
= 10.5%
3. Find the CP when:
(i). SP = ? 924, gain = 10%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + 10)) × 924}
= {(100/ 110) × 924}
= {92400/110}
= ? 840
(ii). SP = ? 1755, gain = 12 1/2 %
Solution:-
Gain = 12 1/2 = 25/2
By using the formula, we have:
CP = ? {(100/ (100 + gain %)) × SP}
= {(100/ (100 + (25/2))) × 1755}
= {(100/ ((200 + 25)/2)) × 1755}
= {(200/ 225) × 1755}
= {351000/225}
= ? 1560
(iii). SP = ? 8510, loss = 8%
Solution:-
By using the formula, we have:
CP = ? {(100/ (100 - loss %)) × SP}
= {(100/ (100 - 8)) × 8510}
= {(100/ 92) × 8510}
= {851000/92}
= ? 9250
(iv). SP = ? 5600, loss = 6 2/3 %
Solution:-
Loss = 6 2/3 = 20/3
By using the formula, we have:
CP = ? {(100/ (100 – loss %)) × SP}
= {(100/ (100 - (20/3))) × 5600}
= {(100/ ((300 - 20)/3)) × 5600}
= {(300/ 280) × 5600}
= {168000/28}
= ? 6000
4. Sudhir bought an almirah for ? 13600 and spent ? 400 on its transportation. He sold it for ? 16800.
Find his gain percent.
Solution:-
From the question,
Sudhir bought an almirah for = ? 13600 = cost price
Transportation cost = ? 400
The total cost price of almirah = ? (13600 + 400)
= ? 14000
He sold it for = ? 16800 = Selling price
By comparing SP and CP = SP > CP, so there is a gain
Gain = SP – CP
= 16800 – 14000
= ? 2800
Gain % = {(gain/CP) × 100}
= {(2800/14000) × 100}
= {2800/140}
= 20%
5. Ravi purchased an old house for ?765000 and spent ?115000 on its repairs. Then, he sold it a gain
of 5%. How much did he get?
Solution:-
From the question,
Ravi purchased an old house for = ? 765000 = Cost price
He spent on its repairs = ? 115000
Total cost price of old house = (765000 + 115000)
= ? 880000
Then, he sold it at a gain of 5%
SP = {((100 + gain %) /100) × CP}
= {((100 + 5) /100) × 880000}
= {(105 /100) × 880000}
= 105 × 8800
= ? 924000
?the selling price of the house is ? 924000
6. A vendor buys lemons at ?25 per dozen and sells them at the rate of 5 for ? 12. Find his gain or
loss percent.
Solution:-
Cost price of 12 lemons = ?25
Then, cost price of 1 lemon = ? (25/12)
Cost price of 5 lemons = (25/12) × 5
= 125/12
= ? 10.42
He sold 5 lemons for = ?12 =Selling price
By comparing SP and CP = SP > CP, so there is a gain
Gain = SP – CP
= 12 – 10.42
= ? 1.58
Gain % = {(gain/CP) × 100}
= {(1.58/10.42) × 100}
= {15800/1042}
= 15.2%
7. The selling price of 12 pens is equal to the cost price of 15 pens. Find the gain percent.
Solution:-
Let the cost price of 1 pen = ? 1
So, cost price of 12 pens = ? 12
From the question,
Selling price of 12 pens = cost price of 15 pens = ? 15
Gain = SP – CP
= 15 -12
= ? 3
Gain % = {(gain/CP) × 100}
= {(3/12) × 100}
= {300/12}
= 25%
8. The selling price of 16 spoons is equal to the cost price of 15 spoons. Find the loss percent.
Solution:-
Let the cost price of 1 spoon = ? 1
So, cost price of 16 pens = ? 16
From the question,
Selling price of 16 spoons = cost price of 15 spoons = ? 15
Loss = (CP) – (SP)
= ? (16 - 15)
= ? 1
Loss % = {(Loss/CP) × 100}
= {(1/16) × 100}
= {100/16}
= 6.25%
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FAQs on RS Aggarwal Solutions: Profit & Loss - Mathematics (Maths) Class 7 (Old NCERT)
| 1. What is profit and loss in mathematics? |  |
Ans. Profit and loss is a concept in mathematics that deals with the calculation of the gain or loss made in a business transaction. It involves calculating the difference between the selling price and the cost price of an item or service.
| 2. How do you calculate profit and loss? | |
Ans. To calculate profit, you subtract the cost price from the selling price. If the result is positive, it is a profit. If the result is negative, it is a loss. The formula for profit is Profit = Selling Price - Cost Price.
| 3. Can you give an example of calculating profit and loss? | |
Ans. Sure! Let's say you bought a shirt for $20 and sold it for $30. To calculate the profit, you subtract the cost price from the selling price: $30 - $20 = $10. So, in this case, you made a profit of $10.
| 4. What is the difference between gross profit and net profit? | |
Ans. Gross profit is the difference between the total revenue and the cost of goods sold. It represents the profit made before deducting any other expenses. Net profit, on the other hand, is the final profit after deducting all expenses, including taxes and operating costs.
| 5. How is profit and loss related to everyday life? | |
Ans. Profit and loss calculations are used in various aspects of everyday life. For example, when buying and selling goods, calculating discounts, or determining the financial performance of a business. Understanding profit and loss helps individuals make informed decisions regarding their personal finances and business transactions.
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RS Aggarwal Solutions: Profit & Loss Class 7 Questions
The "RS Aggarwal Solutions: Profit & Loss Class 7 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 7 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RS Aggarwal Solutions: Profit & Loss on the App
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students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
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The content of RS Aggarwal Solutions: Profit & Loss is prepared as per the latest Class 7 syllabus.
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