The position vector of a point is a directed line segment that locates the point with respect to a chosen reference or origin. In mechanics, it describes the position of a particle or a point of a body relative to a fixed reference frame. As the point moves, the position vector changes in length, direction, or both.
Choose a Cartesian origin O and orthonormal basis vectors i, j, k. The position vector of a point P is written as
r = x(t) i + y(t) j + z(t) k
where x(t), y(t), z(t) are the coordinates of P as functions of time.
The magnitude (distance from origin) is
|r| = √(x(t)² + y(t)² + z(t)²)
A unit vector in the direction of r is
er = r / |r|
Differentiate the position vector with respect to time to obtain the velocity vector.
r(t) = x(t) i + y(t) j + z(t) k
v(t) = dr/dt = dx/dt i + dy/dt j + dz/dt k
Differentiate velocity to obtain acceleration.
a(t) = d2r/dt2 = d2x/dt2 i + d2y/dt2 j + d2z/dt2 k
When motion is along a fixed straight line through the origin (or when the position vector is chosen along the path), r = s(t) e where e is a fixed unit vector along the line.
v = dr/dt = ds/dt e
Here ds/dt is the scalar speed along the line and v has the same direction as the line.
For motion on a circle of radius R about the origin, the magnitude |r| = R is constant and only the direction of r changes with time.
Let the angular coordinate be θ(t). Then
r = R er
Differentiate r with respect to time using the polar unit-vector relations given below to obtain the velocity perpendicular to r.
In plane motion use polar coordinates (r, θ) with unit vectors er (radial) and eθ (transverse). The position vector is
r = r er
The time derivatives of the unit vectors are
d(er)/dt = θ̇ eθ
d(eθ)/dt = -θ̇ er
Differentiate the position vector to get velocity and acceleration.
v = dr/dt = ṙ er + r θ̇ eθ
a = d2r/dt2 = (r̈ - r θ̇²) er + (r θ̈ + 2 ṙ θ̇) eθ
Here ṙ = dr/dt, r̈ = d2r/dt2, θ̇ = dθ/dt, and θ̈ = d2θ/dt2.
For a rigid body, the position vector locates any point of the body relative to a chosen origin. When the body undergoes translation and rotation, the velocity of a point P with position vector r relative to a body-fixed origin O is expressed as the sum of the velocity of O and the rotational contribution.
vP = vO + ω × r
Here ω is the angular velocity vector of the rigid body and × denotes the vector (cross) product.
Find the velocity of a particle whose position vector is r(t) = (3t) i + (4) j (units: metres, time in seconds).
r(t) = 3t i + 4 j
dr/dt = 3 i + 0 j
Therefore the velocity is
v = 3 i m/s
The position vector is the fundamental quantity that locates a point with respect to an origin. Differentiation of the position vector yields velocity and acceleration. Choosing an appropriate coordinate system (Cartesian, polar, or body-fixed) simplifies the description of motion for straight-line, circular, or general curved paths and is essential for solving practical engineering kinematics problems.
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| 1. What is a position vector? | ![]() |
| 2. How is a position vector different from a displacement vector? | ![]() |
| 3. Can position vectors be negative? | ![]() |
| 4. How are position vectors used in physics? | ![]() |
| 5. Can position vectors be used in three-dimensional space? | ![]() |