Que 1:
Sol: Region bounded by
x = 0, x = 1 and y = x, y = 1
Now we evaluate the integral by hanging the order of integral
Que 2: The value of the double integral
Sol: Region of integration is bounded y=0, y = x and x = 0, x = π
changing the order of integration
= 2
Que :-3 Evaluate
Sol:
Que 4:- Change the order of integration in the double integral
Sol: Domain of integration is bounded by the following curves
point of intersection of the curve y =2 - x2 and y = -x we get when
So (-1,1 ) and (2,-2 ) are the points of intersection.
Now the given integral modify by changing the order of integration we get
Que 5:- Changing the order of integration of
Sol:
The region of integration is bounded by y = 0, y = x, x = 1, x = 2 after changing the order the integration changes to
Que 6:- Let D the triangle bounded by the y-axis the line 2y = π. Then the value of the integral
(a) 1/2
(b) 1
(c) 3/2
(d) 2
Sol:
Que 7: Change the order of integration in the integral
Sol:
Que 8:- Let I = Then using the transformation x = rcosθ, y = rsinθ, integral is equal to
Sol:
Que 9: Evaluate integral
(a) 0
(b) 1/2
(c) 1
(d)2
Sol: Region of integration is bounded by curves
changing the order
Que10:- The value of equals
(a) π/4
(b) 1/2π
(c) 1/4
(d) 1/2
Sol:
Que 11:
(a) Find in the area of the smaller of the two regions enclose between
Sol:
Sol (b)
The region of integration is bounded by x = 0, x = y, y = 1, y = ∞ and shown in figure changing the order
Que12:- Let f , be a continuous function with
Sol:
Que13:- By changing the order of integration, the integral can be expressed as
Sol:
27 docs|150 tests
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